Types of Sequences (AQA GCSE Maths): Revision Note

Exam code: 8300

Types of sequences

What other sequences are there?

  • Linear and quadratic sequences are particular types of sequence covered in previous notes

  • Other sequences include geometric and Fibonacci sequences, which are looked at in more detail below

  • Other sequences include cube numbers and triangular numbers

  • Another common type of sequence in exam questions, is fractions with combinations of the above

    • Look for anything that makes the position-to-term and/or the term-to-term rule easy to spot

SeqOth Notes fig2, downloadable IGCSE & GCSE Maths revision notes

What is a geometric sequence? 

  • A geometric sequence can also be referred to as a geometric progression and sometimes as an exponential sequence

  • In a geometric sequence, the term-to-term rule would be to multiply by a constant, r

    • an+1 = r.an

  • r is called the common ratio and can be found by dividing any two consecutive terms, or

    • r = an+1 / an

  • In the sequence 4, 8,  16,  32,  64, ... the common ratio, r, would be 2 (8 ÷ 4 or 16 ÷ 8 or 32 ÷ 16 and so on)

    SeqOth Notes fig3, downloadable IGCSE & GCSE Maths revision notes

What is a Fibonacci sequence? 

  • The Fibonacci sequence is 1, 1,  2,  3,  5,  8,  13,  21,  34,  55, ...

  • The sequence starts with the first two terms as 1

  • Each subsequent term is the sum of the previous two

    • ie The term-to-term rule is an+2 = an+1 + an

    • Notice that two terms are needed to start a Fibonacci sequence

  • Any sequence that has the term-to-term rule of adding the previous two terms is called a Fibonacci sequence but the first two terms will not both be 1

  • Fibonacci sequences occur a lot in nature such as the number of petals of flowers

SeqOth Notes fig4, downloadable IGCSE & GCSE Maths revision notes

Problem solving and sequences

  • When the type of sequence is known it is possible to find unknown terms within the sequence

  • This can lead to problems involving setting up and solving equations

    • Possibly simultaneous equations

  • Other problems may involve sequences that are related to common number sequences such as square numbers, cube numbers and triangular numbers

SeqOth Notes fig5, downloadable IGCSE & GCSE Maths revision notes

Worked Example

(a) Identify the types of sequence below;

(i)       4, 5, 9, 14, 23, 37, 60, ...

(ii)      6, 10, 16, 24, 34, ...

(iii)      12, 7, 2, -3, ...

Answer:

(i)

The previous two terms sum to the next term, e.g. 14 + 23 = 37

Fibonacci sequence

(ii)

Find the differences

6 space space space space space 10 space space space space space 16 space space space space space 24 space space space space space 34
space space plus 4 space space space plus 6 space space space plus 8 space space space plus 10

Find the second differences

6 space space space space space 10 space space space space space 16 space space space space space 24 space space space space space 34
space space plus 4 space space space plus 6 space space space plus 8 space space space plus 10
space space space space space space space space plus 2 space space space plus 2 space space space plus 2

There is a constant second difference

Quadratic sequence

(iii)

Find the differences

12 space space space space space space space 7 space space space space space space space 2 space space space space space space space minus 3
space space space space minus 5 space space space minus 5 space space space minus 5

The first difference is constant

Linear sequence

(b)

The 3rd and 6th terms in a Fibonacci sequence are 7 and 31 respectively.

Find the 1st and 2nd terms of the sequence.

Answer:

Write down the terms you know

Label the unknown second term, x

n

1

2

3

4

5

6

a subscript n

x

7

31

Recall that in a Fibonacci sequence, the previous two terms sum to the next term

n

1

2

3

4

5

6

a subscript n

x

7

x plus 7

x plus 7 plus 7

31

The 4th and 5th terms sum to the 6th term

open parentheses x plus 7 close parentheses plus open parentheses x plus 7 plus 7 close parentheses equals 31

Solve for x

table row cell 2 x plus 21 end cell equals 31 row cell 2 x end cell equals 10 row x equals 5 end table

2nd term = 5

The 1st term (unknown) plus the 2nd term (5) sum to the 3rd term (7)

7 - 5 = 2

1st term = 2

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