Sharing an Amount in a Ratio (SQA National 5 Applications of Mathematics): Revision Note

Exam code: X844 75

Dan Finlay

Written by: Dan Finlay

Reviewed by: Roger B

Updated on

Sharing an amount in a ratio

How do I share an amount in a given ratio?

  • STEP 1
    Add together all parts in the ratio to find the total number of parts

    • £200 is to be shared between two people, A and B, in the ratio 5:3

    • There are 8 parts in total

      • A receives 5 parts and B receives 3 parts

  • STEP 2
    Divide the amount being shared by the total number of parts

    • £200 must be split into 8 parts

      • 1 part equals £200 ÷ 8 = £25

  • STEP 3
    Multiply the amount each part is worth by the number of parts for each quantity in the ratio

    • Person A receives 5 parts

      • 5 × 25 = £125 for person A

    • Person B receives 3 parts

      • 3 × 25 = £75 for person B

    • Check the values in the new ratio add up to the total amount being shared 

      • £125 + £75 = £200

Examiner Tips and Tricks

Sharing an amount in a ratio is the same skill as finding fractions of an amount. For example, sharing an amount in the ratio 2 space colon space 3 is the same as finding 2 over 5 and 3 over 5 of the amount.

Worked Example

A farmer has only sheep, pigs and cows on her farm.

The numbers of sheep, pigs and cows are in the ratio 2 : 3 : 5.

The farmer has 240 animals in total on her farm.

Find the number of pigs.

Answer:

STEP 1

Add together all the parts in the ratio

2 plus 3 plus 5 equals 10

STEP 2

Divide the total number of animals by the total number of parts

240 divided by 10 equals 24

STEP 3

Multiply this by the number of parts for pigs

3 cross times 24 equals 72

72 pigs

How do I find quantities in a ratio if I don't know the total amount?

  • STEP 1
    Identify the number of parts that correspond to the given quantity

    • Consider two people (A and B) sharing money in the ratio 5 : 3

      • If person A receives £90 then £90 is equal to 5 parts

      • If person B receives £90 then £90 is equal to 3 parts

      • If person A receives £90 more than person B then £90 is equal to 5 - 3 = 2 parts

  • STEP 2
    Divide the quantity by the number of parts to find the value of one part

    • If person A receives £90 then 1 part is equal to £90 ÷ 5 = £18

    • If person B receives £90 then 1 part is equal to £90 ÷ 3 = £30

    • If person A receives £90 more than person B then 1 part is equal to £90 ÷ 2 = £45

  • STEP 3
    Multiply this by the number of parts in each of the unknown quantities

    • If person A receives £90 then B receives 3 × £18 = £54

    • If person B receives £90 then A receives 5 × £30 = £150

    • If person A receives £90 more than person B then

      • A receives 5 × £45 = £225

      • B receives 3 × £45 = £135

      • the total received is (5 + 3) × £45 = £360

Examiner Tips and Tricks

It really helps to visualise these problems using boxes. Suppose A and B share money in the ratio 5 : 3, then imagine A has 5 boxes and B has 3 boxes. The amounts in each of the boxes must be equal.

straight A space colon space straight B
5 space colon thin space 3
box enclose ? box enclose ? box enclose ? box enclose ? box enclose ? space colon space box enclose ? box enclose ? box enclose ?

Read the question to determine where you need to share the money or amount:

  • it could be between all boxes if you know the total

  • it could just between one person's boxes

  • it could even be different a number of boxes if you are given the difference between the quantities

Worked Example

Fiona and Gert share sweets in the ratio 4 : 7. Fiona receives 24 fewer sweets than Gert.

Find the number of sweets that Gert receives.

Answer:

STEP 1

Identify how many parts the 28 sweets represent

7 - 4 = 3
Fiona has 3 fewer parts
24 sweets = 3 parts

STEP 2

Find the value of one part

24 divided by 3 equals 8

STEP 3

Multiply this by the number of Gert's parts

7 cross times 8 equals 56

56 sweets

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Dan Finlay

Author: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Roger B

Reviewer: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.