Trig Equations using t-formulae (Edexcel A Level Further Maths): Revision Note

Exam code: 9FM0

Mark Curtis

Last updated

Trig equations using t-formulae

What are the t-formulae?

  • The three t-formulae state that if t equals tan theta over 2 then

    • sin theta equals fraction numerator 2 t over denominator 1 plus t squared end fraction

    • cos theta equals fraction numerator 1 minus t squared over denominator 1 plus t squared end fraction

    • tan theta equals fraction numerator 2 t over denominator 1 minus t squared end fraction

  • They express sin theta, cos theta and tan theta in terms of one variable only, t

  • From these, you can see the reciprocals

    • cosec theta equals fraction numerator 1 plus t squared over denominator 2 t end fraction

    • sec theta equals fraction numerator 1 plus t squared over denominator 1 minus t squared end fraction

    • cot theta equals fraction numerator 1 minus t squared over denominator 2 t end fraction

Examiner Tips and Tricks

You must learn the t-formulae for sin theta, cos theta and tan theta as they are not given in the formulae booklet!

How do I solve trigonometric equations using the t-formulae?

  • To solve trigonometric equations using t-formulae

    • let t equals tan theta over 2

    • convert all trig functions into algebraic fractions in t using

      • sin theta equals fraction numerator 2 t over denominator 1 plus t squared end fraction, cos theta equals fraction numerator 1 minus t squared over denominator 1 plus t squared end fraction, tan theta equals fraction numerator 2 t over denominator 1 minus t squared end fraction

      • cosec theta equals fraction numerator 1 plus t squared over denominator 2 t end fraction, sec theta equals fraction numerator 1 plus t squared over denominator 1 minus t squared end fraction, cot theta equals fraction numerator 1 minus t squared over denominator 2 t end fraction

    • form and solve an equation in t

      • This may be quadratic, cubic, quartic, ...

      • Find all the t-solutions

    • convert the t-solutions back into theta-solutions

      • using t equals tan theta over 2

        • i.e. theta over 2 equals arctan open parentheses... close parentheses so theta equals 2 cross times...

      • and checking the range given

  • You may need to adapt the t-substitution to match the equation, e.g.:

    • for equations in sin 4 theta and cos 4 theta use t equals tan 2 theta

    • for equations in tan x over 3 and sin x over 3 use t equals tan x over 6

Examiner Tips and Tricks

The t-formulae can't find solutions that make the t-substitution undefined, e.g. t equals tan theta over 2 would not pick up a solution at theta equals pi.

Worked Example

Use the substitution t equals tan x over 2 to solve for 0 less than x less than 2 pi

2 cos x plus sin x equals 1

giving answers to 3 significant figures where necessary.

Answer:

Write cos x in terms of its t-formula

cos x equals fraction numerator 1 minus t squared over denominator 1 plus t squared end fraction

Write sin x in terms of its t-formula

sin x equals fraction numerator 2 t over denominator 1 plus t squared end fraction

Substitute these into the equation

2 open parentheses fraction numerator 1 minus t squared over denominator 1 plus t squared end fraction close parentheses plus fraction numerator 2 t over denominator 1 plus t squared end fraction equals 1

Multiply both sides by 1 plus t squared

2 open parentheses 1 minus t squared close parentheses plus 2 t equals 1 plus t squared

Make one side zero

table row cell 2 minus 2 t squared plus 2 t end cell equals cell 1 plus t squared end cell row 0 equals cell 3 t squared minus 2 t minus 1 end cell end table

Solve the quadratic equation, e.g. by factorisation

table row 0 equals cell open parentheses 3 t plus 1 close parentheses open parentheses t minus 1 close parentheses end cell row t equals cell negative 1 third space or space t equals 1 end cell end table

Convert each t solution back into x solutions using t equals tan x over 2

For table row t equals cell negative 1 third end cell end table

table row cell tan x over 2 end cell equals cell negative 1 third end cell row cell x over 2 end cell equals cell arctan open parentheses negative 1 third close parentheses plus n pi end cell row cell x over 2 end cell equals cell negative 0.32175... comma space 2.81984... comma space.... end cell row x equals cell negative 0.64350... comma space 5.63968... comma space.... end cell end table

  • Find x solutions in the range 0 less than x less than 2 pi

table row x equals cell 5.63968... end cell end table

For table row t equals 1 end table

table row cell tan x over 2 end cell equals 1 row cell x over 2 end cell equals cell arctan open parentheses 1 close parentheses plus n pi end cell row cell x over 2 end cell equals cell pi over 4 comma fraction numerator space 5 pi over denominator 4 end fraction comma space... end cell row x equals cell pi over 2 comma fraction numerator space 5 pi over denominator 2 end fraction comma space... end cell end table

  • Find x solutions in the range 0 less than x less than 2 pi

table row x equals cell pi over 2 end cell end table

Present all the solutions (rounding 5.63968... to 3 s.f.)

table row x equals cell 5.64 space open parentheses 3 space straight s. straight f. close parentheses space or space x equals pi over 2 end cell end table

Examiner Tips and Tricks

Other methods to solve this equation, e.g. writing in the form R cos open parentheses x plus alpha close parentheses, score no marks if the question asks you to use t-substitutions.

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Mark Curtis

Author: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.