Show that the equation has a solution between 1 and 2.
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Exam code: J560
Show that the equation has a solution between 1 and 2.
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Show that the equation has a solution between
and
.
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Show that the equation has a solution between
and
.
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Show that the equation has a solution between
and
.
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Show that the equation has a solution between
and
.
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The equation has a solution between
and
.
Find this solution correct to 1 decimal place.
Show your working.
x = ......................................................
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The equation has a solution between
and
.
Find this solution correct to 1 decimal place.
Show your working.
x = .......................................................
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It is known that the equation has a solution that lies between
and
.
Use a suitable method to find the solution correct to 1 decimal place.
You must show your working clearly.
x = .......................................................
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The equation has a negative solution and a positive solution.
The positive solution lies between and
.
Use a suitable method to find the positive solution correct to 1 decimal place.
Show your working.
t = .......................................................
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Show that the equation has a solution between
and
.
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Show that the equation has a solution between
and
.
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Find this solution correct to 1 decimal place.
Show your working.
x = .......................................................
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The equation has a solution between
and
.
Use a suitable method to find this solution correct to two decimal places.
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A value of between 2 and 3 satisfies the equation
By writing the equation in the form where
and
are integers you should find, determine the value of
correct to one decimal place.
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Student A decides to solve the equation using the quadratic formula and gets the two solutions
Student B decides to solve the equation using a sign-change method between and
, where
is an integer.
They want to find the larger solution to 1 decimal place.
Show Student B's working, stating clearly the value of .
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The volume of a sphere of radius cm, where
, is 5 cm3 more than the volume of a square-based cuboid with height 10 cm, width
cm and length
cm.
Use a suitable method to find to 1 decimal place.
[In this question, you may use that the volume of a sphere of radius is
]
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