Algebraic Roots & Indices (OCR GCSE Maths: Higher): Exam Questions

Exam code: J560

2 hours49 questions
1
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1 mark

Simplify      (m2)5

2a
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1 mark

Simplify   m5 ÷ m3

2b
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2 marks

Simplify    5x4y3 × x2y

3a
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1 mark

Simplify    m5 × m3

3b
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1 mark

Simplify      p6p2

4a
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1 mark

Simplify      p2 × p5

4b
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1 mark

Simplify      g6 ÷ g4

4c
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1 mark

Simplify       (k3)2

5
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1 mark

Simplify    t8 ÷ t3

6a
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1 mark

Simplify      (t3)2

6b
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1 mark

Simplify     w9w4

7
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1 mark

Given that y18 ÷ y6 = yk , find the value of k.

k = ................... 

8
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1 mark

Simplify.

a6 ÷ a2

9
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1 mark

Simplify.

(b5)3

10
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1 mark

Simplify.

3y3y4

11
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1 mark

Simplify  (3x2 y)0

12
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1 mark

Simplify  x9x2

13
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1 mark

Write down the value of g0

14
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1 mark

Simplify  e8÷e2

15
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1 mark

Simplify w1 × w0 Circle your answer.

1

0

w

w2

1
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2 marks

Simplify     5u2w4 × 7uw3

2
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2 marks

Simplify     (9x8y3)12

3a
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1 mark

Simplify       a4 × a5

3b
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2 marks

Simplify           45e6f85ef2

3c
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1 mark

Write down the value of   912

4a
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1 mark

Simplify        x7 × x3

4b
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1 mark

Simplify       (m4)3

4c
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2 marks

Simplify    36af812a5f2

5
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2 marks

Simplify      (3x2y4)3

6a
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1 mark

Simplify      (p3)2

6b
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1 mark

Simplify     t8t3

6c
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1 mark

23 × 2n = 29 Work out the value of n.

6d
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1 mark

2x3 = 128

Work out the value of x.

7
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2 marks

Simplify fully    p3 × p4p2

8a
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2 marks

Solve     3x2 = 147

8b
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1 mark

Work out the value of 23

8c
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2 marks

Simplify    (3x2)3

8d
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2 marks

w = 4p  16

Make p the subject of this formula.

9
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2 marks

Simplify       2a3b × 5a2b3

10
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2 marks

Simplify fully    n7 × n3n6

11a
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1 mark

Simplify    m3 × m4

11b
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2 marks

Simplify     (5np3)3

11c
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2 marks

Simplify       32q9r44q3r

12
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3 marks

Simplify fully.

3a8×2a5a2

13
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2 marks

Show that a5× (a3)2 can be expressed as a11.

14
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2 marks

Simplify  (2x3y5 )4

15
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2 marks

Simplify   (16e10 f6 )12

1
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3 marks

1615 × 2x = 834

Work out the exact value of x.

2a
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1 mark

p3 × px = p9

Find the value of x.

2b
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1 mark

(72)y = 710

Find the value of y.

2c
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2 marks

100a × 1000b can be written in the form 10w

Show that w = 2a + 3b

3a
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1 mark

Simplify fully    (3e)0

3b
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2 marks

Simplify fully      (64x625y2)12

4
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3 marks

Show that a4 3×1a  can be expressed as a13.

5a
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2 marks

Simplify.

4a12×3a2

5b
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3 marks

[2a2a3]3

6
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3 marks

Show that  (a3)13×(a2)12=1.

7
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1 mark

Given that  (1x3)4=xm

find the value of m

m = ................................................. 

8
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2 marks

Given that  7206×7m7214=73

find the value of m

m = ................................................ 

9
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3 marks

Simplify completely      (16w8y20)34

10
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4 marks

Given that  n(45)=(12)4 where n>0

find the value of n.

n = .............................................. 

11
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2 marks

Given that  y5 × yny6=y13

work out the value of n.

n = ...........................................

12
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1 mark

Simplify fully  (9t4w918t6w10)2

13
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4 marks

Given that  4k+3 = 16×2k

find the value of k. Show your working clearly.

k = .................................................. 

14
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3 marks

Write 27×(32)7 as a single power of 3.

15
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3 marks

Write 16 × 82x as a power of 2 in terms of x.

16
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1 mark

The nth term of a sequence is  4(2n + 2n1)

Circle the expression that is equivalent to 4(2n + 2n1)

2n+2 + 2n+1

22n + 22(n1)

8n + 8n1

2n+2 + 2n1

 

 

17
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3 marks

Simplify fully   a3b2cd×cab5

18
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4 marks

62+82 = 125a33

Work out the value of a.

19
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2 marks

(arb)4=16r20  where a and b are positive integers.

Work out a and b

a=......................b=......................