Gibbs Free-Energy Change, ∆G, & Entropy Change, ∆S (Oxford AQA International A Level (IAL) Chemistry): Revision Note
Exam code: 9622
Gibbs Free-Energy Change, ∆G
- The feasibility of a reaction does not only depend on the entropy change of the reaction but can also be affected by the enthalpy change - Therefore, using the entropy change of a reaction only to determine the feasibility of a reaction is inaccurate 
 
- The Gibbs free energy (G) is the energy change that takes into account both the entropy change of a reaction and the enthalpy change 
- The Gibbs equation is: 
ΔGꝋ = ΔHreactionꝋ - TΔSsystemꝋ
- Where the units for each term are: - ΔGꝋ = kJ mol-1 
- ΔHreactionꝋ = kJ mol-1 
- T = K 
- ΔSsystemꝋ = J K-1 mol-1 
 
Calculating Gibbs Free-Energy Change
- The Gibbs equation can be used to calculate the Gibbs free energy change of a reaction 
ΔGꝋ = ΔHreactionꝋ - TΔSsystemꝋ
- The equation can also be rearranged to find values of ΔHreactionꝋ, ΔSsystemꝋ or the temperature, T 
- For example, if for a given reaction, the values of ΔGꝋ, ΔHreactionꝋ and ΔSsystemꝋ are given, the temperature can be found by rearranging the Gibbs equation as follows: 
T = 
Worked Example
Calculate the Gibbs free energy for the reaction of methanol, CH3OH, with hydrogen bromide, HBr, at 298 K.
CH3OH (l) + HBr (g) → CH3Br (g) + H2O (l) ΔHrθ = -47 kJ mol-1
- ΔSθ [CH3OH (l)] = +240 J K-1 mol-1 
- ΔSθ [HBr (g)] = +99.0 J K-1 mol-1 
- ΔSθ [H2O (l)] = +70.0 J K-1 mol-1 
- ΔSθ [CH3Br (g)] = +246 J K-1 mol-1 
Answer:
- Calculate ΔSsystemθ - ΔSsystemθ = ΣΔSproductsθ - ΣΔSreactantsθ 
- ΔSsystemθ = (ΔSꝋ [CH3Br (g)] + ΔSθ [H2O (l)]) - (ΔSθ [CH3OH (l)] + ΔSθ [HBr (g)]) 
- ΔSsystemθ = (246 + 70.0) - (240 + 99.0) 
- ΔSsystemθ = -23.0 J K-1 mol-1 
 
- Convert ΔSθ into kJ K-1 mol-1 - ΔSsystemθ = - = 0.023 kJ K-1 mol-1 
 
- Calculate ΔGꝋ - ΔGθ = ΔHreactionθ - TΔSsystemθ 
- ΔGθ = -47 - (298 x -0.023) 
- ΔGθ = -40.146 kJ mol-1 
- ΔGθ = -40.1 kJ mol-1 
 
Feasible Reactions
- The feasibility of a reaction can be affected by the temperature 
- The Gibbs equation will be used to explain what will affect the feasibility of a reaction for exothermic and endothermic reactions 

Exothermic reactions
- In exothermic reactions, ΔHreactionθ is negative 
- If the ΔSsystemθ is positive: - Both the first and second term will be negative 
- Resulting in a negative ΔGθ so the reaction is feasible 
- Therefore, regardless of the temperature, an exothermic reaction with a positive ΔSsystemθ will always be feasible 
 
- If the ΔSsystemθ is negative: - The first term is negative and the second term is positive 
- At high temperatures, the -TΔSsystemθ will be very large and positive and will overcome ΔHreactionθ 
- Therefore, at high temperatures ΔGθ is positive and the reaction is not feasible 
- The reaction is more feasible at low temperatures, as the second term will not be large enough to overcome ΔHreactionθ resulting in a negative ΔGθ 
 
- This corresponds to Le Chatellier’s principle which states that for exothermic reactions an increase in temperature will cause the equilibrium to shift position in favour of the reactants, i.e. in the endothermic direction - In other words, for exothermic reactions, the products will not be formed at high temperatures 
- The reaction is not feasible at high temperatures 
 
Summary of factors affecting Gibbs free energy for exothermic reactions
| If ΔH .... | And if ΔS .... | Then ΔG is | Spontaneous? | Because | 
|---|---|---|---|---|
| is negative < 0 exothermic | is positive > 0 more disorder | always negative < 0 | Always | Forward reaction spontaneous at any T | 
| is negative < 0 exothermic | is negative < 0 more order | negative at low T positive at high T | Dependent on T | Spontaneous only at low T TΔS < H | 
Endothermic reactions
- In endothermic reactions, ΔHreactionθ is positive 
- If the ΔSsystemθ is negative: - Both the first and second term will be positive 
- Resulting in a positive ΔGθ so the reaction is not feasible 
- Therefore, regardless of the temperature, endothermic with a negative ΔSsystemθ will never be feasible 
 
- If the ΔSsystemꝋ is positive: - The first term is positive and the second term is negative 
- At low temperatures, the -TΔSsystemθ will be small and negative and will not overcome the larger ΔHreactionθ 
- Therefore, at low temperatures ΔGθ is positive and the reaction is less feasible 
- The reaction is more feasible at high temperatures as the second term will become negative enough to overcome the ΔHreactionθ resulting in a negative ΔGθ 
 
- This again corresponds to Le Chatellier’s principle which states that for endothermic reactions an increase in temperature will cause the equilibrium to shift position in favour of the products - In other words, for endothermic reactions, the products will be formed at high temperatures 
- The reaction is therefore feasible 
 
Summary of factors affecting Gibbs free energy for endothermic reactions
| If ΔH .... | And if ΔS .... | Then ΔG is | Spontaneous? | Because | 
|---|---|---|---|---|
| is positive > 0 endothermic | is negative < 0 more order | always positive > 0 | Never | Reverse reaction spontaneous at any T | 
| is positive > 0 endothermic | is positive > 0 more disorder | negative at high T positive at low T | Dependent on T | Spontaneous only at high T TΔS > H | 
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