A manufacturer produces calcium carbonate (CaCO2) by reacting calcium hydroxide (Ca(OH)2) with carbon dioxide gas (CO2) according to the balanced equation below:
Ca(OH)2 (s) + CO2 (g) ⟶ CaCO3 (s) + H2O (l)
A sample of 185 g of calcium hydroxide reacts with excess carbon dioxide.
Calculate the number of moles of calcium hydroxide present in the sample.
Determine the mass of calcium carbonate produced from this reaction.
In a second trial, only 122 g of calcium carbonate were collected. Calculate the percent yield for the reaction and explain one possible reason why the yield is less than 100%.
Did this page help you?


