Single-Slit Diffraction (DP IB Physics): Revision Note

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Single Slit Intensity Pattern

  • When monochromatic light passes through a single rectangular slit, a diffraction pattern can be observed on a faraway screen

  • This pattern, similar to the double slit interference pattern, contains:

    • bright fringes of maximum intensity, produced by constructive interference

    • dark fringes of zero or minimum intensity, produced by destructive interference

single-slit-diffraction

The diffraction pattern produced by a laser beam diffracted through a single slit onto a screen is different to the diffraction pattern produced through a double slit

  • However, the single-slit diffraction and double-slit interference patterns are slightly different

  • The central maximum of the single-slit diffraction pattern is:

    • wider and brighter than the other bright fringes

    • wider than that of the double-slit interference pattern

  • On either side of the wide central maxima for the single slit diffraction pattern are much narrower and less bright maxima

    • These get dimmer as the order increases

Features of the single-slit intensity pattern

  • If a laser emitting blue light is directed at a single slit, where the slit width is similar in size to the wavelength of the light, its intensity pattern will be as follows:

Diffraction with a laser, downloadable AS & A Level Physics revision notes

The intensity pattern of blue laser light diffracted through a single slit

  • The features of the single slit intensity pattern are: 

    • the central bright fringe has the greatest intensity of any fringe and is called the central maximum

    • the dark fringes are regions with zero intensity

    • the intensity of each bright fringe gradually decreases on either side of the central maxima

Effect of changing wavelength

  • If the wavelength passing through the gap increases, the wave diffracts more

  • This means the angle of diffraction of the waves increases as they pass through the slit

    • As a result, the width of the bright maxima also increases

  • Red light

    • has the longest wavelength on the visible light spectrum

    • produces a diffraction pattern with wider fringes (due to a larger angle of diffraction)

  • Blue light

    • has a shorter wavelength on the visible light spectrum

    • produces a diffraction pattern with narrower fringes (due to a smaller angle of diffraction)

9-2-1-fringe-width-depends-on-the-wavelength-of-light-ib-hl

Fringe width depends on the wavelength of the light 

  • If the blue laser is replaced with a red laser:

    • the light diffracts more as the waves pass through the single slit

    • the fringes in the intensity pattern appear wider

Diffraction graph, downloadable AS & A Level Physics revision notes

The intensity pattern of red laser light shows that longer wavelengths diffract more than shorter wavelengths

Effect of changing slit width

  • If the slit is made narrower:

    • the angle of diffraction is greater

    • the waves spread out more beyond the slit

  • For a narrower slit, the intensity graph shows that: 

    • the intensity of the maxima decreases

    • the width of the central maxima increases

    • the spacing between fringes is wider

Single slit diffraction equation

  • These properties of wavelength and slit width for single slit diffraction for the first minimum can be explained using the equation:

theta space equals space lambda over b

  • Where:

    • theta = the angle of diffraction of the first minimum (°)

    • lambda = wavelength of incident light (m)

    • b = slit width (m)

  • This equation tells us:

    • the longer the wavelength of light, the larger the angle of diffraction

    • the narrower the slit width then the larger the angle of diffraction

9-3-2-slit-width

Slit width and angle of diffraction are inversely proportional. Increasing the slit width leads to a decrease in the angle of diffraction, hence the maxima appear narrower

Single slit geometry

  • The diffraction pattern made by waves passing through a slit of width b can be explained by considering Huygen's principle, in which

    • each point on a wavefront acts as a source of secondary waves, or wavelets

    • the wavelets are coherent and interfere with each other

  • The central maximum is produced by:

    • wavelets travelling straight forward open parentheses theta space equals space 0 degree close parentheses

    • constructive interference due to all wavelets travelling the same distance

Position of the first minimum

  • For wavelets travelling to the first minimum at an angle theta to the centre line (which splits the slit in half):

    • the wavelets on one half of the slit will travel a greater distance than the wavelets on the other half

    • if all the wavelets from one half cancel out all the wavelets from the other half, this will result in a dark region (destructive interference)

  • Every point on the wavefront can be paired with another point a distance b over 2 away

    • For all the wavelet pairs to cancel (or interfere destructively), the path difference must be lambda over 2

oRULRXAE_9-2-2-diffraction-geometry-ib-hl

The geometry of single-slit diffraction

  • If the distance d between the slit and the screen is considerably larger than the slit width, d space much greater-than space b:

    • the waves can be considered to travel nearly parallel to each other

9-2-2-single-slit-geometry

Determining the path difference using two parallel waves

  • For two rays, r subscript 1 and r subscript 2, travelling parallel to each other at an angle theta between the normal and the slit, where:

    • r subscript 1 emerges from the top edge of the slit

    • r subscript 2 emerges from the centre of the slit, exactly halfway down

  • The path difference is the extra distance travelled by r subscript 2, which is equal to:

path difference = r subscript 1 space minus space r subscript 2 space equals space b over 2 space sin space theta

  • For the two rays, r subscript 1 and r subscript 2, to interfere destructively:

path difference = lambda over 2

  • Therefore, the angle of the first minimum occurs when:

lambda over 2 space equals space b over 2 space sin space theta

lambda space equals space b space sin space theta

  • Since the distance between the slit and the screen is much larger than the slit width open parentheses d space much greater-than space b close parentheses, the angle theta is very small

  • Therefore, the small-angle approximation open parentheses sin space theta space almost equal to space theta close parentheses can be applied:

lambda space almost equal to space b theta

  • This leads to the equation for the angle of diffraction of the first minimum:

theta space equals space lambda over b

  • Using similar reasoning, additional minima occur at:

theta space equals space fraction numerator n lambda over denominator b end fraction

  • Where n = 1, 2, 3... etc.

  • Note: In general, the condition for destructive interference for single slit diffraction can be described by b space sin space theta space equals space n lambda. This expression should be used for angles at which the small-angle approximation is not valid

Width of the central maximum

  • The central maximum extends from the centre to the first minimum on each side

  • The distance to the first minimum can be found using trigonometry

tan space theta space equals space y over d

  • Where

    • theta = angle of the first minimum (rad)

    • y = distance from the centre to the first minimum (m)

    • d = distance from the slit to the screen (m)

Diagram of single slit diffraction showing central maximum and first minimum on a screen; distance d, angle θ, and distance y indicated.

Determining the width of the central maximum

  • Using the small-angle approximation open parentheses tan space theta space almost equal to space theta close parentheses:

theta space almost equal to space y over d

y space almost equal to space d theta

  • The total width of the central maximum is equal to 2 y, which gives:

width space equals space 2 y space equals space 2 d theta

  • Substituting the expression for the angle of the first minimum:

width space equals space fraction numerator 2 lambda d over denominator b end fraction

Worked Example

A group of students are performing a diffraction investigation where a beam of coherent light is incident on a single slit with width b.

The light is then incident on a screen which has been set up a distance D away.

9-2-2-we1-intensity-of-interference-ib-hl

A pattern of light and dark fringes is seen.

The teacher asks the students to change their setup so that the width of the first bright maximum increases.

Suggest three changes the students could make to the set-up of their investigation which would achieve this.

Answer:

Step 1: Write down the equation for the angle of diffraction

theta space equals space lambda over b

  • The width of the fringe is related to the size of the angle of diffraction theta

Step 2: Use the equation to determine the factors that could increase the width of each fringe

Change 1:

  • The angle of diffraction theta is inversely proportional to the slit width b

theta space proportional to space 1 over b

  • Therefore, reducing the slit width would increase the fringe width

Change 2:

  • The angle of diffraction theta is directly proportional to the wavelength lambda

theta space proportional to space lambda

  • Therefore, increasing the wavelength of the light would increase the fringe width

Change 3:

  • The distance between the slit and the screen will also affect the width of the central fringe

  • A larger distance means the waves must travel further, hence, they will spread out more

  • Therefore, moving the screen further away would increase the fringe width

Examiner Tips and Tricks

Make sure you have a good understanding of the models and assumptions made in single slit geometry, i.e. Huygens' principle, parallel rays, and the small angle approximation.

When applying the small-angle approximation open parentheses sin space theta space almost equal to space tan space theta space almost equal to space theta close parentheses, keep in mind:

  • theta must be in radians, not degrees

  • it is most accurate for angles of 10 degree open parentheses straight pi over 18 space rad close parentheses or less

Double Slit Modulation

  • When light passes through a double slit, two types of interference occur:

    • The diffracted rays passing through one slit interfere with the rays passing through the other

    • Rays passing through the same slit interfere with each other

  • This produces a double-slit intensity pattern where the single-slit intensity pattern modulates (adjusts) the intensity of the light on the screen

    • The single-slit intensity pattern has a distinctive central maximum and subsequent maxima at lower intensity

    • The double-slit interference pattern has equally spaced intensity peaks with maxima of equal intensity

    • Together, the combined double slit intensity pattern has equally spaced bright fringes, but now within a single slit 'envelope

Graph showing light intensity patterns: single slit has wide peaks, double slit has narrow peaks, combined pattern overlays both effects.

The double slit interference pattern is modulated inside the single slit intensity pattern

  • This is assuming that:

    • The slit width is not negligible

    • The distance between the slits is much greater than their width 

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Ashika

Author: Ashika

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Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.