Gravitational Field Strength (DP IB Physics: HL): Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

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Gravitational Field Strength

  • There is a universal force of attraction between all matter with mass

    • This force is known as the ‘force due to gravity’ or the weight

  • The Earth’s gravitational field is responsible for the weight of all objects on Earth

  • A gravitational field is defined as:

A region of space where a test mass experiences a force due to the gravitational attraction of another mass

  • The direction of the gravitational field always acts toward the centre of the mass which produces the field

    • This is because gravitational forces are always attractive

  • Gravity has an infinite range, meaning it affects all objects in the universe

    • There is a greater gravitational force around objects with a large mass (such as planets)

    • There is a smaller gravitational force around objects with a small mass (almost negligible for atoms)

Gravitational Attractive Force, downloadable AS & A Level Physics revision notes

The Earth's gravitational field produces an attractive force. The force of gravity is always attractive

  • The gravitational field strength at a point is defined as:

The force per unit mass experienced by a test mass at that point

  • This can be written in equation form as:

g = Fm

  • Where:

    • g = gravitational field strength (N kg−1)

    • F = force due to gravity, or weight (N)

    • m = mass of test mass in the field (kg)

  • This equation shows that:

    • On planets with a large value of g, the gravitational force per unit mass is greater than on planets with a smaller value of g

  • An object's mass remains the same at all points in space

    • However, on planets such as Jupiter, the weight of an object will be greater than on a less massive planet, such as Earth

    • This means the gravitational force would be so high that humans, for example, would not be able to fully stand up

gravitational field strength, downloadable AS & A Level Physics revision notes

A person’s weight on Jupiter would be so large that a human would be unable to fully stand up

  • Factors that affect the gravitational field strength at the surface of a planet are:

    • the radius r (or diameter) of the planet

    • the mass M (or density) of the planet

  • This can be shown by equating the equation F = mg with Newton's law of gravitation:

F = GMmr2

  • Substituting the force F with the gravitational force mg leads to:

mg = GMmr2

  • Cancelling the mass of the test mass m leads to the equation:

g = GMr2

  • Where:

    • G = Newton's Gravitational Constant

    • M = mass of the body causing the field (kg)

    • r = distance from the mass where you are calculating the field strength (m)

  • This equation shows that: 

    • The gravitational field strength g depends only on the mass of the body M which produces the field

  • Hence, objects with any mass m in that field will experience the same gravitational field strength

    • The gravitational field strength g is inversely proportional to the square of the radial distance, r2

Worked Example

Calculate the mass of an object with a weight of 10 N on Earth.

Answer:

Worked Example

The mean density of the Moon is 35 times the mean density of the Earth. The gravitational field strength on the Moon is 16 the gravitational field strength on Earth.

Determine the ratio of the Moon's radius rM to the Earth's radius rE.

Answer:

Step 1: Write down the known quantities

  • gM = gravitational field strength on the Moon, ρM = mean density of the Moon

  • gE = gravitational field strength on the Earth, ρE = mean density of the Earth

ρM = 35ρE

gM = 16gE

Step 2: Write down the equations for the gravitational field strength, volume and density

Gravitational field strength:  g = GMr2

Volume of a sphere:  V = 43πr3           V  r3

Density:  ρ = MV          M = ρV = 43πρr3          M  ρr3

Step 3: Substitute the relationship between M and r into the equation for g

g  ρ(r3)r2           g  ρr

Step 4: Find the ratio of the gravitational field strength

gM  ρMrM

gE  ρErE

gM = 16gE          ρMrM = 16ρErE

Step 5: Substitute the ratio of the densities into the equation

(35ρE) rM = 16ρErE

35rM = 16rE

Step 6: Calculate the ratio of the radii

rMrE = 16÷35 = 518 = 0.28

Examiner Tips and Tricks

There is a big difference between g and G (sometimes referred to as ‘little g’ and ‘big G’ respectively), g is the gravitational field strength and G is Newton’s gravitational constant. Make sure not to use these interchangeably!

Remember the equation density =  massvolumewhich may come in handy with some calculations. The equation for the volume of common shapes is in your data booklet.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.