Escape Speed (DP IB Physics: HL): Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Escape Speed

  • To escape a gravitational field, a mass must travel at, or above, the minimum escape speed

    • This is dependent on the mass and radius of the object creating the gravitational field, such as a planet, a moon or a black hole

  • Escape speed is defined as:

The minimum speed that will allow an object to escape a gravitational field with no further energy input

  • It is the same for all masses in the same gravitational field

    • For example, the escape speed of a rocket is the same as a tennis ball on Earth

  • The escape speed of an object is the speed at which all its kinetic energy has been transferred to gravitational potential energy

  • This is calculated by equating the equations:

12mvesc2 = GMmr

  • Where:

    • m = mass of the object in the gravitational field (kg)

    • vesc = escape velocity of the object (m s−1)

    • G = Newton's Gravitational Constant

    • M = mass of the object to be escaped from (i.e. a planet) (kg)

    • r = distance from the centre of mass M (m)

  • Since mass m is the same on both sides of the equation, it can be cancelled on both sides of the equation:

12vesc2 = GMr

  • Multiplying both sides by 2 and taking the square root gives the equation for escape velocity vesc:

vesc = 2GMr

Escape Velocity Diagram, downloadable AS & A Level Physics revision notes

For an object to leave the Earth's gravitational field, it will have to travel at a speed greater than the Earth's escape velocity, v

  • Rockets launched from the Earth's surface do not need to achieve escape velocity to reach an orbit around the Earth

  • This is because:

    • They are continuously given energy through fuel and thrust to help them move

    • Less energy is needed to achieve orbit than to escape from Earth's gravitational field

  • The escape velocity is not the velocity needed to escape the planet, but to escape the planet's gravitational field altogether

    • This could be quite a large distance away from the planet

Worked Example

Calculate the escape speed at the surface of the Moon.

  • Density of the Moon = 3340 kg m−3

  • Mass of the Moon = 7.35 × 1022 kg

Answer:

Step 1: List the known quantities

  • Gravitational constant, G = 6.67 × 10−11 N m2 kg−2

  • Density of the Moon, ρ = 3340 kg m−3

  • Mass of the Moon, M = 7.35 × 1022 kg

Step 2: Rearrange the density equation for radius r

Density:   ρ = MV  and volume of a sphere:  V = 43πr3

 ρ = M43πr3 = 3M4πr3

r = 3M4πρ3

Step 3: Calculate the radius by substituting in the values

r = 3 × (7.35×1022)4π × 33403 = 1.7384 × 106 m

Step 4: Substitute r into the escape speed equation

vesc = 2GMr = 2 × (6.67×1011) × (7.35×1022)1.7384×106

Escape speed of the Moon:  vesc = 2.37 km s−1

Examiner Tips and Tricks

When writing the definition of escape velocity, avoid terms such as 'gravity' or the 'gravitational pull / attraction' of the planet. It is best to refer to its gravitational field. This equation is given on the data sheet, but make sure you know how it is derived.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.