Annual Effective Dose Limits (SQA National 5 Physics): Revision Note

Exam code: X857 75

Leander Oates

Written by: Leander Oates

Reviewed by: Katie M

Updated on

Annual effective dose limits

  • The annual effective dose limit is defined as:

The maximum equivalent dose (H) that should be received per year

  • The equivalent dose is a measure of how harmful a dose of radiation is

    • The unit is sieverts (Sv)

    • However, 1 Sv is a very large amount, so millisieverts (mSv) are often used

  • The annual effective dose limit for a member of the public is 1 mSv

  • The annual effective dose limit for a radiation worker is 20 mSv

  • These limits exclude the average amount of background radiation that everyone is consistently exposed to

  • The average annual background radiation in the UK is 2.2 mSv

    • Therefore, the general public is recommended to be exposed to no more than 1 mSv above the average background radiation per year

Examiner Tips and Tricks

You do need to know the annual effective doses for the public and for those who work with radiation.

You also need to know the average annual background radiation in the UK.

You will not be given these values on your data sheet, so you do need to memorise them.

  • The annual effective dose limits are used to assess workplace safety in different situations where workers are exposed to radiation

  • For example:

    • Dentists who commonly perform X-rays

    • Radiologists

    • Nuclear power technicians

    • Aircraft crew

  • It is also used for risk assessment to keep members of the public safe

  • For example:

    • Travelling on an aeroplane

    • Radon levels in residential areas

    • Setting industry safety standards for radiation use

    • Setting safety standards for locations where radiation is, or has been used

  • Medical procedures are not included in the annual effective dose limit for members of the public

    • The risks of radiation exposure have to be weighed against the benefits of medical treatment for each patient individually

Worked Example

A technician operates an X-ray fluorescence machine.

The equivalent dose rate received by the technician during the operation is measured to be 15 space straight mu Sv space straight h to the power of negative 1 end exponent.

Determine the maximum number of hours the technician may operate the machine in one year without exceeding this annual dose limit.

Answer:

Step 1: List the known quantities

  • Equivalent dose rate received, H with dot on top space equals space 15 space straight mu Sv space straight h to the power of negative 1 end exponent

  • Annual effective dose limit for a radiation worker, H space equals space 20 space mSv

Step 2: Convert the annual effective dose limit to μSv

  • milli = 10-3

  • micro = 10-6

fraction numerator 1 space mSv over denominator 1 space straight mu Sv end fraction space equals space 10 to the power of negative 3 end exponent over 10 to the power of negative 6 end exponent space equals space 10 to the power of open parentheses negative 3 close parentheses minus open parentheses negative 6 close parentheses end exponent space equals space 10 cubed

20 space mSv space equals space 20 cross times 10 to the power of negative 3 end exponent space straight mu Sv space equals space 20 space 000 space straight mu Sv

Step 3: Write out the appropriate relationship

H with dot on top space equals space H over t

Step 4: Rearrange to make time the subject

  • Multiply both sides by t

H with dot on top t space equals space fraction numerator H up diagonal strike t over denominator up diagonal strike t end fraction

H space equals space H with dot on top t

  • Divide both sides by H with dot on top

fraction numerator H over denominator H with dot on top end fraction space equals space fraction numerator stack up diagonal strike H with dot on top t over denominator stack up diagonal strike H with dot on top end fraction

t space equals space fraction numerator H over denominator H with dot on top end fraction

Step 5: Substitute in the values to calculate

t space equals space fraction numerator 20 space 000 space straight mu Sv over denominator 15 space straight mu Sv space straight h to the power of negative 1 end exponent end fraction

t space equals space 1333.33 space straight h

Step 6: Round to an appropriate number of significant figures

  • The least precise input value is 2 s.f.

  • Therefore, the final answer can only be given to the same precision

t space equals space 1300 space straight h space open parentheses 2 space straight s. straight f. close parentheses

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Leander Oates

Author: Leander Oates

Expertise: Physics Content Creator

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Katie M

Reviewer: Katie M

Expertise: Physics Content Creator

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.