Amount of Substance (OCR A Level Chemistry A): Revision Note

Exam code: H432

Richard Boole

Written by: Richard Boole

Reviewed by: Philippa Platt

Updated on

The mole & the Avogadro constant

Amount of substance and the mole

  • Amount of substance refers to the quantity used to count particles in a substance

    • It is represented by the symbol n in equations

    • The unit of amount of substance is the mole (mol)

The Avogadro constant

  • Amount of substance links to the Avogadro constantNA,

    • The Avogadro constant defines the number of particles in one mole of a substance

    • This constant applies to atoms, molecules, ions and electrons

    • The value of NA is 6.02 x 1023 mol-1 

Molar mass

  • The mass of a substance that contains this number of particles is called one mole

    • This mass is known as the molar mass

    • It is defined as the mass of substance that contains the same number of particles as there are in exactly 12.00 g of carbon-12

  • The amount of substance (n), mass (m), and molar mass (M) are related by the equation:

n = fraction numerator m a s s comma space m over denominator M o l a r space m a s s comma space M end fraction

Molar gas volume

  • Molar gas volume is the volume occupied by one mole of any gas at room temperature and pressure (RTP)

    • At RTP, molar gas volume is 24.0 dm3 mol-1

  • One mole of an element has a mass equal to its relative atomic mass in grams:

    • One mole of carbon contains 6.02 × 10²³ atoms and has a mass of 12.0 g

    • One mole of water contains 6.02 × 10²³ molecules and has a mass of 18.0 g

      • (2 hydrogen atoms = 2 × 1.0, 1 oxygen atom = 16.0, total = 18.0 g)

Worked Example

Molar mass and molar gas volume

  1. Calculate the molar mass of:

    1. Carbon dioxide, CO2

    2. Magnesium nitrate, Mg(NO3)2 

(Ar data: C = 12.0, O = 16.0, Mg = 24.3, N = 14.0)

  1. Calculate the number of moles of each gas:

    1. 36.0 dm3 of carbon monoxide, CO

    2. 9.6 dm3 of chlorine, Cl2 

Answers

Answer 1: The molar mass is the mass of one mole of any substance

a. Carbon dioxide, CO2 = 12.0 + (16.0 x 2) = 44.0 g

b. Magnesium nitrate, Mg(NO3)2 = 24.3 + (14.0 x 2) + (16.0 x 3 x 2) = 148.3 g

Answer 2:

One mole of any gas occupies 24.0 dm3 

a. 36.0 dm3 is 1.5 times the molar gas volume of 24.0 dm3, therefore, there are 1.5 moles of carbon monoxide, CO

b. 9.6 dm3 is 0.4 times the molar gas volume of 24.0 dm3, therefore, there are 0.4 moles of chlorine, Cl2

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Richard Boole

Author: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener