Nucleic Acid & Amino Acid Sequence Comparison (AQA AS Biology): Revision Note
Exam code: 7401
Linking DNA to polypeptides
When comparing the genetic code to amino acid sequences, mRNA codons are often used
The four bases found in RNA molecules (adenine, uracil, cytosine and guanine) can form 64 different codons, yet there are only 20 amino acids that are coded for
Therefore, the genetic code is degenerate
Multiple mRNA codons can encode the same amino acid; e.g., UGU and UGC both code for the amino acid cysteine
This means that a change in the genetic code doesn’t necessarily result in a change in the amino acid sequence
Some codons send important signals to the translation machinery
The START codon marks the start of the protein and therefore initiates the process of translation from the right location (this is always the amino acid methionine in eukaryotic cells, coded for by the codon AUG)
STOP codons cause translation to terminate at the end of the protein and do not code for any amino acids, e.g. UAA
The genetic code is non-overlapping
Each base is only read once in the codon that it is part of
The number of amino acids in a protein can be calculated using the number of coding nucleotides in the mRNA molecule and vice versa:
Each amino acid is coded for by a triplet (codon) of 3 nucleotides
The last codon is a STOP codon, which does not code for an amino acid
When given the number of amino acids, multiply by 3 and add three (for the STOP codon)
Worked Example
A segment of mRNA contains 303 coding nucleotides.
How many amino acids will be in the polypeptide produced?
Step 1: When given the number of coding mRNA nucleotides, divide by 3
303 ÷ 3 = 101 codons
Step 2: Minus 1, to take into account the STOP codon
101 – 1 = 100 amino acids
(Assuming one of the codons is a stop codon and doesn’t code for an amino acid)
Working out an amino acid sequence
An amino acid sequence can be derived when given a genetic code table (or codon table)
The bases in the codon are read left to right across the table, and the corresponding amino acids can be found

Worked Example
A strand of DNA has the following sequence:
TAC CCG AAA ACT
Use a codon table to identify the sequence of amino acids coded for by this mRNA.
Step 1: Convert the DNA sequence into mRNA codons using complementary base pairing
TAC CCG AAA ACT → AUG GGC UUU UGA
Step 2: Use the codon table to translate the mRNA codons into an amino acid sequence
AUG = Met
GGC = Gly
UUU = Phe
UGA = Stop (does not code for an amino acid)
Therefore, the amnio acid sequence = Met - Gly - Phe
Examiner Tips and Tricks
You will not be required to memorise specific codons and the amino acids for which they code. When using the codon table, remember you need to use the mRNA codons, and not the DNA triplet codes. The mRNA sequence will have been formed from the DNA template strand during transcription and so will have a complementary sequence.
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