Exam code: 9701
This question is about benzene.
Draw the displayed formula for benzene.
State the bond angle in the planar regular hexagon structure of benzene.
State the type of hybridisation of the carbon atoms in benzene.
Was this exam question helpful?
Benzene can exist as C6H6 or be substituted in a number of different ways to form aromatic compounds.
State the IUPAC name for compounds W, X and Y.
State the IUPAC name for compound Z.
State the bond angle that is present in the benzene molecule.
In benzene, each of the carbon atoms is sp2 hybridised.
i) Explain how neighbouring carbon atoms form σ bonds.
[1]
ii) Neighbouring carbon atoms also form π bonds. Explain how these π bonds are formed.
[1]
Was this exam question helpful?
State the IUPAC name for the following aromatic compounds
compound X ..........................................................................
compound Y .........................................................................
Explain why the benzene ring is planar.
Compound X can be formed from benzene. Outline the reagents for the two step reaction to formation of compound X
step 1 .......................................................................................
step 2 ......................................................................................
Was this exam question helpful?
State the bond angle that is present in the benzene molecule.
Explain why a molecule of benzene, C6H6 does not tend to react with bromine whereas hexene, C6H12, will react to form dibromohexane, C6H12Br2.
State the name of the mechanism that benzene will undergo if reacted with bromine in the presence of a halogen carrier to form bromobenzene, C6H5Br.
Was this exam question helpful?