Sketching Solution Trajectories (DP IB Applications & Interpretation (AI)): Revision Note

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Sketching Solution Trajectories

How do I sketch a solution trajectory for a system of coupled differential equations?

  • A phase portrait shows typical trajectories representing all the possible solutions to a system of coupled differential equations

  • For a given set of initial conditions, however, the solution will only have one specific trajectory

  • Sketching a particular solution trajectory will generally involve the following:

    • Make sure you know what the ‘typical’ solutions for the system look like

      • You don’t need to sketch a complete phase portrait unless asked, but you should know what the phase portrait for your system would look like

      • If the phase portrait includes ‘eigenvector lines’, however, it is worth including these in your sketch to serve as guidelines

    • Mark the starting point for your solution trajectory

      • The coordinates of the starting point will be the x and y values when t equals 0

      • Usually these are given in the question as the initial conditions for the system

    • Determine the initial direction of the solution trajectory

      • To do this find the values of fraction numerator d x over denominator d t end fraction and fraction numerator d y over denominator d t end fraction when t equals 0

      • This will tell you the directions in which x and y are changing initially

      • For example if fraction numerator d x over denominator d t end fraction equals negative 2 and fraction numerator d y over denominator d t end fraction equals 3 when t equals 0, then the trajectory from the starting point will initially be ‘to the left and up’, parallel to the vector open parentheses table row cell negative 2 end cell row 3 end table close parentheses

    • Use the above considerations to create your sketch

      • The trajectory should begin at the starting point (be sure to mark and label the starting point on your sketch!)

      • It should move away from the starting point in the correct initial direction

      • As it moves further away from the starting point, the trajectory should conform to the nature of a ‘typical solution’ for the system

Worked Example

Consider the system of coupled differential equations

fraction numerator d x over denominator d t end fraction equals x minus 5 y
fraction numerator d y over denominator d t end fraction equals negative 3 x plus 3 y

The initial conditions of the system are such that the exact solution is given by 

bold italic x equals straight e to the power of 6 t end exponent open parentheses table row cell negative 1 end cell row 1 end table close parentheses minus 2 straight e to the power of negative 2 t end exponent open parentheses table row 5 row 3 end table close parentheses

Sketch the trajectory of the solution, showing the relationship between x and y as t increases from zero.

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Roger B

Author: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.