Ionisation Energy & Electronic Configuration (Cambridge (CIE) AS Chemistry): Revision Note
Exam code: 9701
Ionisation Energies: Electronic Configuration
Using Successive Ionisation Energy Data
Each ionisation energy refers to the energy required to remove one one mole of electrons from one mole of a specific species in the gaseous state
First ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms
Successive ionisation energies are the energy required to remove one mole of electrons from one mole of gaseous positive ions
As electrons are removed, the ion becomes more positively charged
This increases the electrostatic attraction between the nucleus and remaining electrons
Therefore, ionisation energies increase progressively
A large jump in successive ionisation energies indicates that:
An electron is being removed from a new, inner shell closer to the nucleus
These electrons experience a stronger attraction to the nucleus and require more energy to remove
How to deduce electronic configuration
Look for the largest increase between two successive ionisation energies
The number of electrons removed before this jump = number of outer-shell (valence) electrons
This corresponds to the element’s group number in the Periodic Table (for s- and p-block elements)
Worked Example
Deduce the electronic configuration of element Z, a Period 3 element, using successive ionisation energy data.
IE | 5th | 6th | 7th | 8th |
---|---|---|---|---|
IE (kJ mol-1) | 6542 | 9362 | 11,018 | 33,606 |
Answer
You are told that the element is in Period 3
Period 3 elements have electrons up to the 3rd shell:
3s and 3p subshells are included
There is a large jump between the 7th and 8th IE, so element Z must be in Group 17
So element Z is in Period 3 and Group 17:
This corresponds to chlorine, Cl
The electronic configuration of Cl is:
1s22s22p6 3s23p5
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