Finding Areas Using a GDC (DP IB Analysis & Approaches (AA)): Revision Note

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Area Under a Curve Basics

What is meant by the area under a curve?

Notes fig1
  • The phrase “area under a curve” refers to the area bounded by

    • the graph of y equals f left parenthesis x right parenthesis

    • the x-axis

    • the vertical line x equals a

    • the vertical line x equals b

  • The exact area under a curve is found by evaluating a definite integral

  • The graph of y equals f left parenthesis x right parenthesis could be a straight line

    • The use of integration described below would still work

      • But the shape created would be a triangle, rectangle or trapezoid

      • It is easier then to use the relevant geometric area formulas

What is a definite integral?

  • A definite integral is written in the form integral subscript a superscript b f left parenthesis x right parenthesis space straight d x, where

    • space f left parenthesis x right parenthesis is the integrand (function to be integrated)

    • a and b are the integration limits

      • a is the lower limit, and b is the upper limit

      • These correspond to the lines x equals a and x equals b in the area under a curve

  • According to the Fundamental Theorem of Calculus, if F left parenthesis x right parenthesis is an antiderivative ofspace f left parenthesis x right parenthesis, then

integral subscript a superscript b f left parenthesis x right parenthesis space straight d x equals F left parenthesis b right parenthesis minus F left parenthesis a right parenthesis

  • The constant of integration (“plus c”) is not needed in definite integration

    • "plus c” would appear alongside both F(a) and F(b)

    • Then subtracting means the “plus c”’s would cancel

How do I form a definite integral to find the area under a curve?

  • The graph of y equals f left parenthesis x right parenthesis and the x-axis should be obvious boundaries for the area

    • So the key here is in finding a and b, the lower and upper limits of the integral 

  •  STEP 1

    Use the given sketch to help locate the limits

    You may prefer to plot the graph on your GDC and find the limits from there
     

  • STEP 2

    Look carefully where the ‘left’ and ‘right’ boundaries of the area lie

    • If the boundaries are vertical lines, the limits will come directly from their equations

      • Look out for the y-axis being one of the (vertical) boundaries – in this case the limit will be x equals 0

    • One, or both, of the limits, could be a root of the equationspace f left parenthesis x right parenthesis equals 0

      • i.e.  where the graph ofspace y equals f left parenthesis x right parenthesis crosses the x-axis

      • In this case solve the equationspace f left parenthesis x right parenthesis equals 0 to find the limit(s)

      • A GDC will solve this equation, either from the graphing screen or the equation solver

  • STEP 3

    The definite integral for finding the area can now be set up in the form

space A equals integral subscript a superscript b f left parenthesis x right parenthesis space straight d x

Examiner Tips and Tricks

Look out for questions that ask you to find an indefinite integral in one part (so “+c” needed), then in a later part use the same integral as a definite integral (where “+c” is not needed).

Examiner Tips and Tricks

Add information to any diagram provided in the question, as well as axes intercepts and values of integration limits.

Mark and shade the area you’re trying to find, and if no diagram is provided, sketch one!

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Definite Integrals using GDC

Does my calculator/GDC do definite integrals?

  • Modern graphic calculators (and some ‘advanced’ scientific calculators) have the functionality to evaluate definite integrals

    • i.e. they can calculate the area under a curve (see above)

  • If a calculator has a button for evaluating definite integrals it will look something like

integral subscript square superscript square square

  • This may be a physical button or accessed via an on-screen menu

  • Some GDCs may have the ability to find the area under a curve from the graphing screen

  • Be careful with any calculator/GDC

    • They may give you a decimal approximation rather than an exact answer

    • E.g. 3.141592654 instead of pi

How do I use my GDC to find definite integrals?

Without graphing first...

  • Once you know the definite integral function your calculator will need three things in order to evaluate it

    • The function to be integrated (integrand), space f left parenthesis x right parenthesis

    • The lower limit (a from x equals a)

    • The upper limit (b from x equals b)

  • Have a play with the order in which your calculator expects these to be entered – some do not always work left to right as it appears on screen!

With graphing first...

  • Plot the graph of y equals f left parenthesis x right parenthesis

    • You may also wish to plot the vertical lines x equals a and x equals b

      • For the vertical lines, make sure your GDC is expecting an "x equals" style equation

    • Once you have plotted the graph you need to look for an option regarding “area” or a physical button

      • It may appear as the integral symbol (e.g. integral straight d x)

      • Your GDC may allow you to select the lower and upper limits by moving a cursor along the curve - however this may not be very accurate

      • Your GDC may allow you to type the exact limits required from the keypad

Examiner Tips and Tricks

When revising for your exams, practise using your GDC to evaluate definite integrals (or to check any definite integrals you may have calculated by hand).

This will ensure you are confident using the calculator you plan to take into the exam, and should also get you into the habit of using you GDC to check your work, something you should do if possible.

Worked Example

a) Using your GDC to help, or otherwise, sketch the graphs of

y equals x to the power of 4 minus 2 x squared plus 5,

x equals 1 and

x equals 2 on the same diagram

5-2-3-ib-sl-ai-aa-we2-soltn-a

b) The area enclosed by the three graphs from part (a) and the x-axis is to be found.

Write down an integral that would find this area.

5-2-3-ib-sl-ai-aa-we2-soltn-b

c) Using your GDC, or otherwise, find the exact area described in part (b).

Give your answer in the form p over q where space p and space q are integers.

5-2-3-ib-sl-ai-aa-we2-soltn-c


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