Binomial Theorem (DP IB Analysis & Approaches (AA): SL): Exam Questions

3 hours29 questions
1a
2 marks

Consider the expansion of (4x−2)4.

Find the term in x4 in the expansion.

1b
3 marks

Hence find the term in x6 in the expansion of (3x−5)2(4x−2)4.

2a
3 marks

Expand and simplify (5+x)5 in descending powers of x.

2b
3 marks

Hence find the exact value of (5.1)5.

3a
2 marks

Expand and simplify (2−x)3 in descending powers of x.

3b
3 marks

Hence find the exact value of (1.8)3.

1
3 marks

Find the coefficient of the term in x3 in the expansion of (2−x)8.

2
4 marks

Find the first three terms, in ascending powers of x, in the expansion of (3+x)4.

3
4 marks

In the expansion of (a−x)4, the coefficient of the x2 term is 96.

Given that a > 0, find the value of a.

4
4 marks

Find the first three terms, in ascending powers of x, in the expansion of (9−2x)5.

5
4 marks

In the expansion of (a−2x)5, where a≠0, the coefficient of the x2 term is equal to the coefficient of the x3 term.

Find the value of a.

6
5 marks

In the expansion of (3+px)6, where p≠0, the coefficient of the x4 term is four times the coefficient of the x2 term.

Find the possible values of p.

7a
1 mark

Consider the expansion of (4ax−3)5.

Write down the number of terms in this expansion.

7b
4 marks

The coefficient of the term in x4 is −61440.

Find the value of a where a is a positive constant.

8a
4 marks

Consider the expansion of (x3+4x)4.

Find the first three terms in descending powers of x.

8b
3 marks

Find the value of the constant term.

9
5 marks

The coefficient of x7 in the expansion of x3(ax+3)5 is 1215.

Find the possible values of a.     

10
4 marks

Find the coefficient of the x16 term in the expansion of (2x2−x3)7.

11a
1 mark

Consider the expansion of (5x3−x)6.

Write down the number of terms in this expansion.

11b
4 marks

Find the first three terms, in descending powers of x, of the expansion.

12a
3 marks

Consider the expansion of (ax2+3x2)5.

Find an expression, in terms of a, for the coefficient of the x−1 term.

12b
2 marks

The coefficient of the x−1 term is 90.

Find the value of a.

13
4 marks

Consider the expansion (1−3x)4(1−2kx)2.

The coefficient of the x6 term is 36. Find the possible values of k.

14a
4 marks

Consider the expansion of (x33+kx)4. The constant term is −5003. 

Find the value of k.

14b
3 marks

Find the coefficient of the x4 term.

15a
3 marks

Consider the expansion of (32x−5)6.

Find the term in x3 in the expansion.

15b
5 marks

Hence find the term in x4 in the expansion of (x−2)(32x−5)6.

16
6 marks

In the expansion of 2x2(3+kx)7, the coefficient of the term in x5 is 210.

Find the value of k.

1a
2 marks

Consider the quadratic expression 5x2−15x+10.

Write down the quadratic expression in the form p(x−q)(x−r), where q<r.

1b
5 marks

Find the coefficient of the x8 term in the expansion of (5x2−15x+10)5.

2a
4 marks

The coefficient of x7 in the expansion of (x3)5 (ax+5)2 is 13.  

Find the possible values of a.

2b
4 marks

The sum of the coefficients of the expansion is 196243.

Determine which value of a found in part (a) is correct.

3
5 marks

In the expansion of (12x+1)n, the coefficient of the x2 term is 8n, where n∈ℤ+.

Find n.

4
5 marks

Given that (2+nx)2(1−2x)n=4−24x+....

Find the value of n.

5
5 marks

Given that (1+nx)2 (1+2x3)n=1+40x+...

Find the value of n.

6
7 marks

Consider the expansion of (x3a+3x5)9, where a>0. The coefficient of the x39 term is five times the coefficient of the x31 term.

Find a.

7
6 marks

Consider the expansion of (2x3−kx2)12, where k>0. The coefficient of the term in x6 is equal to the coefficient of the term in x16.

Find k.

1a
2 marks

Given that (1−2x)2(1+yx)3=1+zx+40x2+⋯+ky3x5.

Determine the value of k.

1b
7 marks

Find the possible values of y and z.

2a
2 marks

Given that (1−2ax)3(1+3x)3=1+bx−27x2+⋯+ka3x6.

Determine the value of k.

2b
7 marks

Find the possible values of a and b.

3
7 marks

The coefficient of the x5 term in the expansion of (1+2x)4(1−px)3 is −120.

Find the value of p.