Binomial Theorem (DP IB Analysis & Approaches (AA): SL): Exam Questions

3 hours29 questions
1
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3 marks

Find the coefficient of the term in x3 in the expansion of (2x)8.

2
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3 marks

Find the first three terms, in ascending powers of x, in the expansion of (3+x)4.

3
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4 marks

In the expansion of (ax)4, the coefficient of the x2 term is 96.

Given that a > 0, find the value of a.

4
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3 marks

Find the first three terms, in ascending powers of x, in the expansion of (92x)5.

5
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4 marks

In the expansion of (a2x)5, the coefficient of the x2 term is equal to the coefficient of the x3 term. Find the value of a.

6
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3 marks

In the expansion of (3+px)6, the coefficient of the x4 term is four times the coefficient of the x2 term. Find the possible values of p.

7a
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1 mark

Consider the expansion of (4ax3)5.

Write down the number of terms in this expansion.

7b
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4 marks

The coefficient of the term in x4 is 61440.

Find the value of a where a is a positive constant.

8a
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3 marks

Consider the expansion of (x3+4x)4.

Write the first three terms in descending powers of x.

8b
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3 marks

Find the value of the constant term.

9
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4 marks

The coefficient of x7 in the expansion of x3(ax+3)5 is 1215.

Find the possible values of a.     

1
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4 marks

Find the coefficient of the x16 term in the expansion (2x2x3)7.

2a
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1 mark

Consider the expansion of (5x3x)6.

Write down the number of terms in this expansion.

2b
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4 marks

Find the first three terms, in descending powers of x, of the expansion.

3a
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3 marks

Consider the expansion of (ax2+3x2)5.

Find an expression, in terms of a, for the coefficient of the x1 term.

3b
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4 marks

The coefficient of the x1 term is 90.

Find the value of a.

4a
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2 marks

Consider the quadratic expression 5x215x+10..

Write down the quadratic expression in the form (pxq)(xr).

4b
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5 marks

Find the coefficient of the x8 term in the expansion of (5x215x+10)5. Give your answer in the form a×10k, where 1a<10, k.

5a
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4 marks

The coefficient of x7 in the expansion of (x3)5 (ax+5)2 is 13.  

Find the possible values of a.

5b
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4 marks

The sum of the coefficients of the expansion is 196243.

Determine which value of a found in part (a) is correct.

6
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6 marks

Consider the expansion (13x)4(12kx)2.

The coefficient of the x6 term is 36. Find the possible values of k.

7a
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4 marks

Consider the expansion of (x33+kx)4. The constant term is 5003. 

Find the value of k.

7b
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4 marks

Find the coefficient of the x4 term.

8
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5 marks

In the expansion of (12x+1)n, the coefficient of the x2 term is 8n, where n+.

Find n.

9a
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2 marks

Consider the expansion of (4x2)4.

Find the term in x4 in the expansion.

9b
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3 marks

Hence find the term in x6 in the expansion of (3x5)2(4x2)4.

10a
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3 marks

Consider the expansion of (32x5)6.

Find the term in x3 in the expansion.

10b
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5 marks

Hence find the term in x4 in the expansion of (x2)(32x5)6.

1
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7 marks

Given that (2+nx)2(12x)n=424x+....

Find the value of n.

2
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7 marks

Given that (1+nx)2 (1+2x3)n=1+40x...

Find the value of n.

3a
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3 marks

Consider the expansion (5+x)5.

Write down and simplify the expansion in descending powers of x.

3b
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3 marks

Hence, find the exact value of (5.1)5.

4a
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3 marks

Consider the expansion (2x)3.

Write down and simplify the expansion in descending powers of x.

4b
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3 marks

Hence find the exact value of (1.8)3.

5a
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2 marks

Given that (12x)2(1+yx)3=1+zx+40x2++ky3x5.

Determine the value of k.

5b
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7 marks

Find the possible values of y and z.

6a
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2 marks

Given that (12ax)3(1+3x)3=1+bx27x2++ka3x6.

Determine the value of k.

6b
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7 marks

Find the possible values of a and b.

7
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6 marks

In the expansion of 2x2(3+kx)7, the coefficient of the term in x5 is 210.

Find the value of k.

8
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7 marks

Consider the expansion of (x3a+3x5)9, a>0. The coefficient of the x39term is five times the coefficient of the x31term.

Find a, giving your answer to 3 significant figures.

9
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6 marks

Consider the expansion of (2x3kx2)12, where k>0. The coefficient of the term in x6 is equal to the coefficient of the term in x16.

Find k.

10
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8 marks

The coefficient of the x5 term in the expansion of (1+2x)4(1px)3 is 120.

Find the value of p.