Complex Roots of Quadratics (DP IB Applications & Interpretation (AI)): Revision Note
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Complex Roots of Quadratics
What are complex roots?
A quadratic equation can either have two real roots (zeros), a repeated real root or no real roots
This depends on the location of the graph of the quadratic with respect to the x-axis
If a quadratic equation has no real roots we would previously have stated that it has no real solutions
The quadratic equation will have a negative discriminant
This means taking the square root of a negative number
Complex numbers provide solutions for quadratic equations that have no real roots
How do we solve a quadratic equation when it has complex roots?
If a quadratic equation takes the form ax2 + bx + c = 0 it can be solved by either using the quadratic formula or completing the square
If a quadratic equation takes the form ax2 + b = 0 it can be solved by rearranging
The property i = √-1 is used
If the coefficients of the quadratic are real then the complex roots will occur in complex conjugate pairs
If z = p + qi (q ≠ 0) is a root of a quadratic with real coefficients then z* = p - qi is also a root
The real part of the solutions will have the same value as the x coordinate of the turning point on the graph of the quadratic
When the coefficients of the quadratic equation are non-real, the solutions will not be complex conjugates
To solve these you can use the quadratic formula
How do we factorise a quadratic equation if it has complex roots?
If we are given a quadratic equation in the form az2 + bz + c = 0, where a, b, and c ∈ ℝ, a ≠ 0 we can use its complex roots to write it in factorised form
Use the quadratic formula to find the two roots, z = p + qi and z* = p - qi
This means that z – (p + qi) and z – (p – qi) must both be factors of the quadratic equation
Therefore we can write az2 + bz + c = a(z – (p + qi))( z – (p - qi))
This can be rearranged into the form a(z – p – qi)(z – p + qi)
Examiner Tips and Tricks
Once you have your final answers you can check your roots are correct by substituting your solutions back into the original equation
You should get 0 if correct! [Note: 0 is equivalent to
]
Worked Example
Solve the quadratic equation z2 - 2z + 5 = 0 and hence, factorise z2 - 2z + 5.

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