Complex Roots of Quadratics (DP IB Applications & Interpretation (AI)): Revision Note

Amber

Written by: Amber

Reviewed by: Mark Curtis

Updated on

Complex roots of quadratics

When does a quadratic have complex roots?

  • The quadratic equation a z squared plus b z plus c equals 0 where a comma space b comma space c element of straight real numbers has complex roots if

    • b squared minus 4 a c less than 0

      • the discriminant is negative

How do I solve a quadratic with complex roots?

  • To solve a quadratic equation with complex roots, a z squared plus b z plus c equals 0

    • either use the quadratic formula

      • e.g. plus-or-minus square root of negative 9 end root equals plus-or-minus 3 straight i

    • or complete the square

Examiner Tips and Tricks

You can can check your answer by substituting your complex roots back into the equation a z squared plus b z plus c equals 0 (which should given 0 plus 0 straight i if correct).

  • The two complex roots to the quadratic equation a z squared plus b z plus c equals 0 where a comma space b comma space c element of straight real numbers are complex conjugate pairs

    • i.e. if z equals p plus q straight i is a root, then z to the power of asterisk times equals p minus q straight i is the other root

  • This is not true if any of the coefficients a, b or c are complex

How do I factorise a quadratic expression using complex roots?

  • If a quadratic expression a z squared plus b z plus c has a negative discriminant (b squared minus 4 a c less than 0), then it can factorised as follows:

    • set the expression equal to zero

      • a z squared plus b z plus c equals 0

    • solve this equation to find the complex roots

      • z subscript 1 equals p plus q straight i and z subscript 2 equals z subscript 1 to the power of asterisk times equals p minus q straight i

    • rewrite a z squared plus b z plus c in the factorised form a open parentheses z minus z subscript 1 close parentheses open parentheses z minus z subscript 2 close parentheses

      • You could expand inside each bracket

      • a open parentheses z minus p minus q straight i close parentheses open parentheses z minus p plus q straight i close parentheses

Worked Example

Solve the quadratic equation z2 - 2z + 5 = 0 and hence, factorise z2 - 2z + 5.

1-9-3-ib-aa-hl-complex-roots-we-solution-1-a

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Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.