Solving Quadratics by Factorising (Cambridge (CIE) O Level Additional Maths): Revision Note
Exam code: 4037
Solving quadratics by factorising
How do I solve a quadratic equation using factorisation?
- Rearrange it into the form ax2 + bx + c = 0 - zero must be on one side - it is easier to use the side where a is positive 
 
 
- Factorise the quadratic and solve each bracket equal to zero - If (x + 4)(x - 1) = 0, then either x + 4 = 0 or x - 1 = 0 - Because if A × B = 0, then either A = 0 or B = 0 
 
 
- To solve - …solve “first bracket = 0”: - x – 3 = 0 
- add 3 to both sides: x = 3 
 
- …and solve “second bracket = 0” - x + 7 = 0 
- subtract 7 from both sides: x = -7 
 
- The two solutions are x = 3 or x = -7 - The solutions have the opposite signs to the numbers in the brackets 
 
 
- To solve - …solve “first bracket = 0” - 2x – 3 = 0 
- add 3 to both sides: 2x = 3 
- divide both sides by 2: x = 
 
- …solve “second bracket = 0” - 3x + 5 = 0 
- subtract 5 from both sides: 3x = -5 
- divide both sides by 3: x = 
 
- The two solutions are x = - or x = 
 
- To solve - it may help to think of x as (x – 0) or (x) 
- …solve “first bracket = 0” - (x) = 0, so x = 0 
 
- …solve “second bracket = 0” - x – 4 = 0 
- add 4 to both sides: x = 4 
 
- The two solutions are x = 0 or x = 4 - It is a common mistake to divide both sides by x at the beginning - you will lose a solution (the x = 0 solution) 
 
 
Examiner Tips and Tricks
- Where permitted, and if you calculator has a quadratic solving feature, you can use it to check your final solutions! - Such calculators also help you to factorise (if you're struggling with that step) 
- e.g. A calculator gives solutions to - as x = - and x = - "Reverse" the method above to factorise! 
 
- Warning: a calculator (correctly) gives solutions to 12x2 + 2x – 4 = 0 as x = - and x = - But 12x2 + 2x – 4 ≠ - as these brackets expand to 6x2 + ... not 12x2 + ... 
- Multiply by 2 to correct this 
- 12x2 + 2x – 4 = 
 
 
Worked Example
(a) Solve 
 
Set the first bracket equal to zero
x – 2 = 0
Add 2 to both sides
x = 2
Set the second bracket equal to zero
x + 5 = 0
Subtract 5 from both sides
x = -5
Write both solutions together using “or”
x = 2 or x = -5
(b) Solve 
 
Set the first bracket equal to zero
8x + 7 = 0
Subtract 7 from both sides
8x = -7
Divide both sides by 8
x = 
Set the second bracket equal to zero
2x - 3 = 0
Add 3 to both sides
2x = 3
Divide both sides by 2
x = 
Write both solutions together using “or”
x =  or x = 
(c) Solve 
 
Do not divide both sides by x (this will lose a solution at the end)
Set the first “bracket” equal to zero
(x) = 0
Solve this equation to find x
x = 0
Set the second bracket equal to zero
5x - 1 = 0
Add 1 to both sides
5x = 1
Divide both sides by 5
x = 
Write both solutions together using “or”
x = 0 or x = 
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