Proof by Contradiction (Edexcel A Level Maths: Pure): Exam Questions

Exam code: 9MA0

1 hour24 questions
1
3 marks

Given that x is an integer such that x2 is odd, use proof by contradiction to show, using algebra, that x is odd.

2
3 marks

x is an integer such that x2 is even.

Prove by contradiction, using algebra, that x is even.

3
3 marks

Given that x is an integer such that 3x is odd, use proof by contradiction to show, using algebra, that x is odd.

4
2 marks

Below is an attempt at a proof by contradiction to show that there is no largest multiple of 7.

Line 1:

Assume there is a number, S, say, that is the largest multiple of 7

Line 2:

S=7k

Line 3:

Consider the number S+7

Line 4:

S+7=7k+7

Line 5:

S+7=7(k+1)

Line 6:

So S+7 is a multiple of 7

Line 7:

This is a contradiction to the assumption that S is the largest multiple of 7

Line 8:

Therefore, there is no largest multiple of 7

Both line 2 and line 6 are incomplete.

Complete these lines of the proof.

5
2 marks

"There are an infinite number of positive multiples of 10."

A proof by contradiction starts as follows:

Proof

Assume there are a finite number of positive multiples of 10.

This means there is a greatest multiple of 10, written as 10k, where k.

Consider the expression 10k+10.

Write the statements needed to complete the proof.

1
3 marks

Given that p and q are integers such that

pq is even

use algebra to prove by contradiction that at least one of p or q is even.

2
4 marks

Given that m3+5 is odd, use proof by contradiction to show, using algebra, that m is even.

3
4 marks

Prove by contradiction that there are an infinite number of positive even numbers.

4a
1 mark

A student is attempting to answer the following exam question:

“Prove by contradiction that 2 is an irrational number. You may use without proof the fact that if a number n2 is even, then n must also be even.”

The student’s proof is as follows:

Line 1:

Assume 2 is a rational number.  Therefore, it can be written in the form 2=ab, where a and b are integers with b0, and where a and b have no common factors.

Line 2:

Squaring both sides gives 4=a2b2

Line 3:

Multiplying both sides by b2 gives a2=2b2

Line 4:

 

Line 5:

This means a can be written as a=2m, for some integer m

Line 6:

Squaring gives a2=(2m)2=4m2

Line 7:

Substituting a2=4m2 into a2=2b2 gives  4m2=2b2

Line 8:

Dividing both sides by 2 gives 2m2=b2

Line 9:

This shows that b2 is even, and therefore b must be even

Line 10:

It has been shown that both a and b are even, so they share a common factor of 2.

Line 11:

This is a contradiction of the assumption that a and b have no common factors.

Line 12:

Therefore, 2 is irrational.

There is an error within the first three lines of the proof.

Find the error and write down the correct line of the proof.

4b
1 mark

Line 4 of the proof is missing.

Complete this line of the proof.

5
3 marks

Given that x3 is odd, use proof by contradiction to show, using algebra, that x is odd.

6
4 marks

x and y are two real numbers such that x+y is an irrational number.

Prove by contradiction that x or y or both are irrational numbers.

7
3 marks

Prove by contradiction that a triangle cannot have more than one obtuse angle.

1
4 marks

Use proof by contradiction to show that 3 is an irrational number.

2
3 marks

A student attempts to answer the following question:

Given that x is an obtuse angle, use algebra to prove by contradiction that

sinxcosx1

The student starts the proof with:

Assume that sinxcosx<1 when x is an obtuse angle

(sinxcosx)2<1...

Complete the proof.

3
6 marks

Prove by contradiction that 11 is an irrational number. 

You may use without proof the fact that if n2 is a multiple of 11, then n is a multiple of 11.

4
3 marks

Given that xn is odd where n is a positive integer, use proof by contradiction to show, using algebra, that x is odd.

5
4 marks

Prove by contradiction that there are an infinite number of positive powers of 2.

6
1 mark

Below is a proof by contradiction that log27 is irrational.

Line 1: 

Assume log27 is a rational number.  Therefore it can be written in the form log27=ab, where a and b are integers with no common factors, and b0. Note that ab>1 (as ab=log27>log22=1) so we can assume that a>b>0.

Line 2: 

Rearranging log27=ab gives 2ab=7

Line 3: 

Raising both sides to the power b gives (2ab)b=7b

Line 4: 

Line 5: 

This says that a power of 2 must equal a power of 7

Line 6: 

This is not possible, except when a=b=0 which contradicts a>b>0

Line 7: 

Therefore log27 is irrational

Lines 4 is missing.

Complete this line of the proof.

7
4 marks

Use proof by contradiction to show that, given a rational number x and an irrational number y, x+y is irrational.

8
5 marks

Prove by contradiction that there are no positive integers x and y such that

9x2y2=13

1
4 marks

Prove by contradiction that there are no positive integers p and q such that

4p2q2=25

2
5 marks

Prove by contradiction that there are an infinite number of prime numbers.

3
5 marks

Without solving the equation directly, use algebra to prove by contradiction that the solutions to the equation 

3x2+10x8=0

cannot be written in the form x=ab where a and b are both odd integers.

4
4 marks

A composite number, N, has the following properties:

  • It is a positive integer greater than 1

  • It is not a prime number

  • It has at least two prime factors

  • It can be written as a product of its prime factors, p1, p2, ..., pk:

N=p1×p2×...×pk

where k2.

Prove by contradiction that any composite number, N, must have at least one prime factor that is less than or equal to N.