Solving Equations (AQA A Level Maths: Pure): Exam Questions

Exam code: 7357

3 hours35 questions
1a
Sme Calculator
2 marks

The figure below shows the curve with equation y=f(x) where

f(x)=2x22x3+3

  • The equation f(x)=0 has only one solution, x=α

  • You may assume that f(x) is continuous for all values of x

q1a-10-1-solving-equations-easy-a-level-maths-pure

(i) Find f(1.5)

(ii) Find f(1.6)

1b
Sme Calculator
1 mark

Use part (a) to write down an interval containing the root α, in the form

a<α<b

where a and b are constants to be found.

2
3 marks

A function f(x) is continuous for all values of x.

The equation f(x)=0has only one solution, x=3.1, correct to 2 significant figures.

(i) Write down the lower bound, l, and the upper bound, u, of the solution.

(ii) Write down a statement about the signs of f(u) and f(l ).

3a
Sme Calculator
1 mark

Show that the equation

x35x=2

can be written as

x=15(x32)

3b
Sme Calculator
3 marks

Starting with x0=1, use the iterative formula

xn+1=15( xn32)

to find the values of x1, x2and x3.

Give your answers correct to 4 decimal places, where necessary.

4a
Sme Calculator
2 marks

The function f(x) is given by

f(x)=xex           x

Show there is a root, α, of the equation f(x)=0 in the interval 0.5<x<0.6.

4b
Sme Calculator
2 marks

(i) Find f'(x).

(ii) Show that the Newton-Raphson method is given by the iteration formula

xn+1=xnxnexn1+exn

4c
Sme Calculator
4 marks

(i) Use the Newton-Raphson method with x0=0.55 to find the values of x1, x2 and x3, giving your answers correct to 5 decimal places.

(ii) Assuming that the answers are converging to α, use the unrounded values of x2 and x3 to estimate α to the highest degree of accuracy possible.

5
Sme Calculator
6 marks

The diagram below shows part of the curve with the equation y=53ex

Graph showing a curve extending rightwards with a shaded area between x=1 and x=2 under the curve. Axes marked as x and y.

The trapezium rule is used to estimate the shaded area on the graph which is given by the integral

12(53ex) dx

(i) Given that 4 trapezia of equal width are used, calculate the width of one trapezium, h.

(ii) Complete the table of values below, giving each value correct to 3 significant figures.

x

1

1.25

1.5

1.75

2

y

3.90

 

 

4.48

 

(iii) Use the trapezium rule with the values from the table in part (ii) to find an estimate of the shaded area, giving your answer correct to 2 significant figures.

6a
Sme Calculator
1 mark

The figure below show the curve with equation y=f(θ) where

  • f(θ) =1cos θ

  • θ is measured in radians

  • πθπ

q7-10-1-solving-equations-easy-a-level-maths-pure

Find f(1.5) and f(1.6).

6b
2 marks

A student claims that the answers to part (a) show that a root of f(θ)=0 lies in the interval [1.5, 1.6].

Explain why the student is incorrect.

7
Sme Calculator
3 marks

The solution to the equation f(x)=0 is x=α.

The equation f(x)=0 can be rearranged to x=g(x).

The diagram below shows a sketch of the graphs of y=g(x) and y=x.

q8-10-1-solving-equations-easy-a-level-maths-pure

Starting with an initial estimate of x0, show on the diagram how the iteration formula

xn+1=g(xn)

converges to α.

Indicate, on the x-axis, the positions of x1 and x2.

8a
Sme Calculator
6 marks

The diagram below shows part of the graph with equation y=(x2)23.

QBPQiCZA_q8-10-1-solving-equations-easy-a-level-maths-pure

The trapezium rule is used to estimate the area of the shaded region shown above, given by

410(x2)23 dx

(i) If all the y-values in the table below are used, write down the number of x-values, the number of trapezia and the width of each trapezium.

x

4

5

6

7

8

9

10

y 

1.59

2.08

2.52

2.92

3.30

3.70

4.00

(ii) Use the trapezium rule to find an estimate of the shaded area.

(iii) State, with a reason, whether your answer to part (ii) is an overestimate or an underestimate.

8b
1 mark

State, with a reason, whether your answer to part (ii) is an overestimate or an underestimate.

9a
Sme Calculator
2 marks

Show that the equation x3+3=5x can be written in the form

x=axb3

where a and b are integers to be found.

9b
Sme Calculator
1 mark

Taking x0=1.8 as the first approximation, use the iteration formula

xn+1=axnb3

with your values of a and b in part (a) to find, by repeated iteration, a solution to the equation

x3+3=5x

10
Sme Calculator
2 marks

Part of the curve y=tan θ is shown below, where θ is measured in radians.

q5-10-1-solving-equations-medium-a-level-maths-pure

A student uses a change of sign argument to show that the interval [1.55, 1.65] contains a solution to the equation tan θ=0

Explain whether, or not, this is a valid method.

1a
Sme Calculator
3 marks

The table below shows corresponding values of x and y for y=ln x.

x

2

2.5

3

3.5

4

y

0.833

0.957

1.048

1.119

1.177

Use the trapezium rule with all the values in the table to find an estimate for

24ln x dx

1b
1 mark

State, with a reason, whether your answer to part (a) is an overestimate or an underestimate of the value of the integral.

2a
1 mark

The graph of y=f(x) where

f(x)=2x(ln x)33          x>0

is shown below, where α and β are solutions to the equation f(x)=0

q7-10-1-solving-equations-medium-a-level-maths-pure

The Newton-Raphson method is to be used to estimate the values of α and β.

Indicate on the diagram the starting value, x0, that would lead to the Newton-Raphson method failing to find either solution, α or β.

[You do not need to calculate the value of x0.]

2b
3 marks

Find an expression for f'(x).

2c
Sme Calculator
3 marks

Apply the Newton-Raphson method with x0=1 to find β.

Give your answer to 5 significant figures.

3a
Sme Calculator
4 marks

The curve with equation y=ex+2x is shown below.

The shaded area is represented by

28ex+2xdx

q8-10-1-solving-equations-medium-a-level-maths-pure

Use the trapezium rule with 6 equally spaced trapezia to find an estimate for the area of the shaded region.

Give your answer to 3 significant figures.

3b
1 mark

Explain how the accuracy of the estimate in part (a) can be improved.

4a
Sme Calculator
2 marks

f(x)=x34x+1

Show that the equation f(x)=0 has a root α in the interval 1<x<2.

4b
Sme Calculator
3 marks

The iterative formula

xn+1=41xn

is used with x1=1.5 to find an approximate value for α.

Calculate the values of x2 and x3, giving your answers to 4 decimal places.

4c
2 marks

Show that if the iteration converges to a limit α, then α must be a root of the equation f(x)=0.

5a
Sme Calculator
2 marks

The diagram below shows part of the graph y=f(x) where

f(x)=2x cos (3x)1

q1a-10-1-solving-equations-medium-a-level-maths-pure

Show that a solution to the equation f(x)=0 exists in the interval 1.6<x<1.7

5b
Sme Calculator
3 marks

Using a suitable interval. show that x=2.55 is a solution to the equation f(x)=0, correct to 3 significant figures.

6a
2 marks

Sketch two separate diagrams to show how the trapezium rule can lead to either an underestimate or an overestimate.

6b
Sme Calculator
4 marks

Use the trapezium rule with step size h=0.25 to find an estimate for the area bounded by the curve with equation y=1+0.3x2sin x and the lines x=1, x=2 and the x-axis.

Give your answer to 3 significant figures.

7a
Sme Calculator
2 marks

The function f(x) is defined as

  f(x)=x2ln (x+2)             x>0

Show that there is a solution to the equation f(x)=0 in the interval 1<x<1.2

7b
2 marks

Find an expression for f'(x)

7c
Sme Calculator
2 marks

Taking x0=1 as the first approximation, apply the Newton-Raphson method repeatedly to find a solution to the equation f(x)=0 in the interval [1, 1.2].

Give your answer correct to 3 decimal places.

8a
Sme Calculator
4 marks

The trapezium rule is to be used to approximate

48f(x) dx

The table below shows values of x and f(x).

x 

4

4.5

5

5.5

6

6.5

7

7.5

8

 f(x)

3.16

3.39

3.61

3.81

4

4.18

4.36

4.53

4.69

Using the values in the table, find an estimate for the integral using

(i) 2 trapezia,
(ii) 4 trapezia,
(iii) 8 trapezia.

8b
1 mark

Explain which estimate from part (a) is likely to be the most accurate approximation of

48f(x) dx

9a
Sme Calculator
1 mark

The diagram below shows part of the curve with the equation y=2ln x

q4-10-1-solving-equations-medium-a-level-maths-pure

The trapezium rule is used to estimate the area of the shaded region, given by

5102ln x dx

Four equally spaced trapezia are used, each of width h.

Find h.

9b
Sme Calculator
2 marks

Complete the table of values below, correct to 3 significant figures.

x

5

6.25

7.5

8.75

10

y

3.05

 

4.04

 

 

9c
Sme Calculator
2 marks

Using the trapezium rule with all the values of y in the table, find an estimate for

5102ln x dx

9d
1 mark

State whether your answer to part (c) is an overestimate or an underestimate.

10
Sme Calculator
5 marks

The diagram below shows part of the graph with equation y=3xex2.

The area between the curve and the x-axis from x=0.5 to x=1 is shaded.

q3a-10-1-solving-equations-hard-a-level-maths-pure

Use the trapezium rule with 5 equally spaced trapezia to find an estimate for the area of the shaded region.

Give your answer to 3 significant figures.

11a
Sme Calculator
1 mark

The figure below shows the line y=x and the curve y=ln (x1)+3

q6-10-1-solving-equations-medium-a-level-maths-pure

The iteration formula

xn+1=ln(xn1)+3

with x0=2 is used to find an estimate for a root, α, of the equation f(x)=0.

Write down an expression for f(x).

11b
Sme Calculator
2 marks

Draw a staircase diagram on the graph in part (a) to determine whether the iteration formula starting with x0=2 finds an approximation for the x-coordinate of point S or the x-coordinate of point T.

11c
Sme Calculator
2 marks

Find the values of the estimates x1, x2, x3 and x4, giving each answer to 3 decimal places.

11d
Sme Calculator
2 marks

Using a suitable interval, show that α=4.146 to 3 decimal places.

1a
1 mark

The diagram below shows part of the curve y = f(x) where

f(x)=3x2sin2 x 2        3π2<x<3π2

q1a-10-1-solving-equations-hard-a-level-maths-pure

You are given that f(0.9)=0.509 and f(3.4)=0.265, to 3 significant figures,

A student wishes to find an estimate of the root of f(x)=0 that is close to x=0.98

Explain why a change of sign in the interval [0.9, 3.4] is not necessarily helpful to the student.

1b
Sme Calculator
2 marks

Using a suitable interval, show that there is a root close to x=0.98.

1c
Sme Calculator
2 marks

Show that the root close to x=0.98 is 0.982, correct to 3 significant figures.

2a
Sme Calculator
2 marks

The graph below shows a sketch of the line y=x and the curve  y=3x2+2x13

pmoTqjiD_q1a-10-1-solving-equations-hard-a-level-maths-pure

An iteration formula is used to find the three roots of the equation

x33x22x+1=0

Draw a staircase diagram on the graph above to show that the iteration formula

xn+1=3xn2+2xn1 3

with a starting value of x0=0.5 converges to the largest positive root of the equation.

2b
Sme Calculator
3 marks

(i) Use the iteration formula from part (a) with x0=0.5 to find x1, x2 and x3, to 3 significant figures.

(ii) If the root is close to x=3.5, describe the speed of convergence to the root of the values x1, x2 and x3.

2c
Sme Calculator
2 marks

Show that the root close to x=3.5 is 3.49, correct to 3 significant figures.

3a
Sme Calculator
5 marks

The function f(x) is defined as

  f(x)=sin 3xln 2x         x>0

where x is in radians.

Apply the Newton-Raphson method with a starting approximation of x0=0.8 to find a solution to the equation

sin 3x=ln 2x

giving your answer correct to 4 decimal places.

3b
1 mark

The graph of y=f(x) has a local maximum point with coordinates (β, f(β)).

Describe what happens when applying the Newton-Raphson method with a starting approximation of x0=β.

4
Sme Calculator
3 marks

Graphs of y=f(x) for four different functions are shown below.

q5a-10-1-solving-equations-hard-a-level-maths-pure
q5-2-10-1-solving-equations-hard-a-level-maths-pure

Match each graph above with the correct statement below:

  1. f(x) is not continuous and it is possible to have an interval showing no sign change that contains exactly one root

  2. f(x) is not continuous and it is possible to have an interval showing no sign change that contains more than one root

  3. f(x) is continuous and it is possible to have an interval showing no sign change that contains exact one root

  4. f(x) is continuous and it is possible to have an interval showing no sign change that contains more than one root

5a
2 marks

The diagram below shows the line y=x and the curve y=g(x).

QpsJxjGx_q1a-10-1-solving-equations-hard-a-level-maths-pure

Draw a cobweb diagram on the graph above, using the starting approximation x0 indicated.

You must show

  • the first two estimates, x1 and x2

  • convergence to a root of the equation xg(x)=0

5b
Sme Calculator
3 marks

By forming a suitable iteration formula with x0=2 and using repeated iteration, find a root of the equation

xsin 0.8x=2.5

correct to 2 significant figures.

5c
Sme Calculator
2 marks

Using a suitable interval and a suitable function that should be stated, show that your answer to part (b) is correct to 2 significant figures.

6a
Sme Calculator
1 mark

The diagram below shows part of the graph of y=f(x) where

f(x)=0.3esin x0.5

Two roots of the equation f(x)=0 are shown, α and β.

gfVjCPAq_q1a-10-1-solving-equations-hard-a-level-maths-pure

Write down the x-coordinate of the maximum point, M, on the graph.

6b
Sme Calculator
6 marks

The Newton-Raphson method is applied to find an estimate for the root β.

The starting approximation, x0, is the smallest positive integer value greater than the x-coordinate of the maximum point M.

Find the first four estimates and use a suitable interval to find β correct to 5 significant figures.

7a
Sme Calculator
3 marks

The diagram below shows the graph of y=f(x) where the function f(x) is defined by

f(x)=105x212x+4       x>2

NJMlean__q1a-10-1-solving-equations-hard-a-level-maths-pure

The function f(x) has a positive root close to x=1.4

An iteration formula is given by

x subscript n plus 1 end subscript equals square root of k minus fraction numerator 1 over denominator 10 x plus 20 end fraction end root to the power of blank

where k is an integer to be found.

Use repeated iteration to find an estimate of the positive root, to 6 decimal places, using a starting value of x0=1.4

7b
Sme Calculator
5 marks

Apply the Newton-Raphson method with x0=1.4 to find an estimate of the positive root, to 6 decimal places.

7c
1 mark

Compare the rates at which the estimates converge between the different methods in part (a) and part (b).

8a
Sme Calculator
1 mark

The function, f(x), is defined by

f(x)=1exx+1              x

Show that the equation f(x)=0 can be written in the form

  x=eax+b

where a and b are integers to be found.

8b
Sme Calculator
2 marks

On the same diagram, sketch the graphs of y=x and y=eax+b, using your values of a and b from part (a).

8c
2 marks

The equation f(x)=0 has a root, α, close to x=1.

Draw a cobweb diagram on the graph in part (b) to show how the iteration formula

xn+1=eaxn+b

with x0=2 converges to α.

8d
Sme Calculator
3 marks

(i) Find the values of x1, x2 and x3, giving each answer correct to 3 significant figures.

(ii) How many iterations, n, are required before xn and xn1 agree with each other to 2 decimal places?

8e
Sme Calculator
1 mark

The root α lies in the interval p<x<q.

Find the values of p and q that give the largest interval such that α can be found to 2 decimal places.

9a
Sme Calculator
3 marks

Apply the Newton-Raphson method with x0=1.5 to find a solution to equation

x52x4+3x34x2+1=0

correct to 4 significant figures.

9b
Sme Calculator
2 marks

Show that there is a solution to the equation in the interval [0.605 , 0.615].

Without further calculation, state the value of this solution to the highest degree of accuracy possible.

10
Sme Calculator
3 marks

The diagram below shows the graph of y=42xln x where x>0.

q7a-10-1-solving-equations-very-hard-a-level-maths-pure-screenshots

Use the trapezium rule in step sizes of 0.2 to find an estimate of the integral

12(42xln x) dx

to 3 significant figures.

1a
Sme Calculator
1 mark

The diagram below shows part of the graph with equation y=f(x) where

f(x)=xtan(πx)3

q1a-10-1-solving-equations-very-hard-a-level-maths-pure-screenshots

A student searches for a root of the equation f(x)=0.

They find that f(1.5)<0 and f(1.6)>0. They then conclude that there is a root in the interval 1.5<x<1.6.

Explain why the student’s conclusion is not correct.

1b
Sme Calculator
1 mark

Explain why a change of sign method would fail when searching for the rootx=0 of the equation

f(x)+3=0

2a
Sme Calculator
3 marks

The function f(x) is defined as

  f(x)=3+5cos x sin 2x                x

Show that the Newton-Raphson formula can be written as

xn+1=xn3+5cos xn sin2xnacos xn(1bsin2 xn)

where a and b are integers to be found.

2b
Sme Calculator
3 marks

Apply the Newton-Raphson method with x0=0.3 to find, to 5 significant figures, a solution of the equation

10cos2 x sin x=3

2c
Sme Calculator
2 marks

A student wants to use the Newton-Raphson method to find a solution to the equation

f(x)=3

in the range x>0.

A teacher tells the student that the Newton-Raphson method is not necessary.

Explain why and find a solution to the equation, giving the highest accuracy possible.

3a
Sme Calculator
4 marks

The diagram below shows the graph of y=f(x) where f(x) is defined by

  f(x)=5x+2x212                    x>0

q9a-10-1-solving-equations-very-hard-a-level-maths-pure-screenshots

The equation f(x)=0 has a solution close to x=0.4

Use repeated iteration with x0=0.4 to find this solution to 4 decimal places.

You must state your iteration formula clearly.

3b
Sme Calculator
3 marks

Apply the Newton-Raphson method to find the same root, using a different starting value of x0=0.5

Give your answer to 4 decimal places.

3c
1 mark

Compare the rates at which the estimates converge between the different methods in part (a) and part (b).

4a
Sme Calculator
3 marks

The figure below shows a sketch of the curve y=x(x6)2.

q10a-10-1-solving-equations-very-hard-a-level-maths-pure-screenshots

The coordinates of the local maximum point are (2, 32).

Use the trapezium rule with 4 equally-spaced trapezia to find an approximation to

15x(x6)2 dx

4b
Sme Calculator
3 marks

By replacing the trapezia with rectangles that fit above the curve, find an upper bound for the area shaded.

Use rectangles that fit below the curve to find a lower bound.