Finding Vector Paths (AQA GCSE Maths: Foundation): Revision Note

Exam code: 8300

Finding vector paths

How do I find the vector between two points?

  • A vector path is a path of vectors taking you from a start point to an end point

  • The following grid is made up entirely of parallelograms

    • The vectors a and b defined as marked in the diagram:

      • Any vector that goes horizontally to the right along a side of a parallelogram will be equal to a

      • Any vector that goes up diagonally to the right along a side of a parallelogram will be equal to b

Vectors on a grid of parallelograms
  • To find the vector between two points, you need to find the route which uses the least number of moves

    • Count how many times you need to go horizontally to the right

      • This will tell you how many a's are in your answer

    • Count how many times you need to go up diagonally up and to the right

      • This will tell you how many b's are in your answer

    • Add the a's and b's together

      • E.g. AR=2a+3b

  • You will have to put a negative in front of the vector if it goes in the opposite direction

    • -a is one length horizontally to the left

    • -b is one length down diagonally to the left

      • E.g. FB=b+a or FB=ab

      • Likewise, BF=FB=(b+a)=ba

Vector paths on a grid
  • It is possible to describe any vector that goes from one point to another in the above diagram in terms of a and b

Examiner Tips and Tricks

Mark schemes will accept different correct paths, as long as the final answer is fully simplified. Check for symmetries in the diagram to see if the vectors given can be used anywhere else.

Worked Example

The following diagram consists of a grid of identical parallelograms.

Vectors a and b are defined by a = AB and b = AF.

Vectors on a grid of parallelograms

Write the following vectors in terms of a and b.

a) AE

Answer:

To get from A to E we need to follow vector a four times to the right 

AE = AB +BC + CD + DE= a + a  + a + a

AE=4a 

b) GT

Answer:

There are many ways to get from G to T
One option is to go from to (b twice), and then from to (a three times) 

GT = GL +LQ + QR + RS + ST=b + b + a + a + a

GT=3a+2b

c) EK

Answer:

There are many ways to get from E to K
One option is to go fromto O (b twice), and then from O to ( -a four times)

EK = EJ +JO + ON + NM + ML + LK  =b + b  a  a  a  a

EK=2b4a

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Jamie Wood

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