Polynomials (Edexcel International A Level (IAL) Maths: Pure 2): Exam Questions

Exam code: YMA01

3 hours29 questions
1
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2 marks

Use the factor theorem to verify that (x2) is a factor of x3x214x+24.

2
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4 marks

Divide  x3+6x2+11x+6  by  (x+2).

3
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6 marks

Given f(x)=x35x22x+24 has a root at x=3, fully factorise f(x).

4
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4 marks

Use polynomial division to show that (x2) is a factor of 2x3+3x218x+8.

5
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4 marks

Given x=2 is a root of the function f(x)=x33x28x+4, fully factorise f(x).

6
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3 marks

Given that (x4) is a factor of x3kx24x+16, find the value of k.

7
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4 marks

Given that x=12 is a root of the function f(x)=2x3+(p2+1)x211x+4, find the possible values of p.

8a
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4 marks

Given that (x+1) is a factor of  f(x)=x35x2+3x+9, fully factorise f(x).

8b
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3 marks

Sketch the graph of y=f(x), labelling the coordinates of all points where the graph intersects the coordinate axes.

 

9
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4 marks

Find the remainder when  x37x6  is divided by (x+4).

10
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5 marks

The function f(x) is given by f(x)=x4+ax313x238x4b, where a and b are constants.

Given that both (x+1)  and (x+2) are factors of f(x), find the values a of b .

1
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2 marks

Divide x36x29x+14  by (x7).

2a
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2 marks

 f(x)=2x3x216x+15

Find the remainder when f(x) is divided by (x2).

2b
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4 marks

Given that (x+3) is a factor of f(x), factorise f(x) completely.

3a
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2 marks

 f(x)=2x33x272x35 

Show that f(x)=(2x+1)(ax2+bx+c),  where a, band c are constants to be found.

3b
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4 marks

Hence factorise f(x) completely.

3c
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2 marks

Write down all the real roots of the equation f(x)=0

4a
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2 marks

f(x)=4x3+4x223x30 

Use the factor theorem to show that (x+2) is a factor of f(x).

4b
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4 marks

Factorise f(x) completely.

4c
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2 marks

Write down all the real roots of the equation f(x)=0.

5a
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6 marks

f(x)=x3+9x2+rx+s. Given that f(2)=0 and f(1)=54 :

find the values of  r and  s.

5b
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3 marks

Factorise f(x) completely.

6
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5 marks

Consider the function f(x)=4x3+6x27x+2.

(i) Find the quotient and remainder when 4x3+6x27x+2 is divided by (x2). 

(ii) Hence write  4x3+6x27x+2 in the form (x2)(ax2+bx+c)+d, where a, b, c and d are constants to be determined.

7a
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5 marks

The function f(x)=2x35x2+ax+b  has (2x+3) as a factor, and when f(x) is divided by (x2) the remainder is 7. 

Show that a and b must satisfy the simultaneous equations:            2a+b=11

         3a2b=36

7b
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2 marks

Hence find a and b.

1
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2 marks

Divide x319x30 by (x5).

2a
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2 marks

f(x)=x328x+48

Find the remainder when f(x) is divided by (x3).

2b
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4 marks

Given that (x+6) is a factor of f(x), factorise f(x) completely.

3a
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2 marks

f(x)=6x319x2+11x+6

Show that f(x)=(2x3)(ax2+bx+c) where a, b and c are constants to be found. 

3b
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4 marks

Hence factorise f(x) completely.

3c
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2 marks

Write down all the real roots of the equation f(x)=0.

4a
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2 marks

f(x)=4x37x3

Use the factor theorem to show that (2x+1) is a factor of f(x).

4b
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4 marks

Factorise f(x) completely.

.

4c
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2 marks

Write down all the real roots of the equation f(x)=0.

5a
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6 marks

f(x)=x3+rx2+sx30. Given that f(2)=0  and f(3)=240 :

 find the values of r and s.

5b
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3 marks

Factorise f(x) completely.

6
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6 marks

Given that (x+4) is a factor of the function f(x)=px3+(5p+1)x2+5qx2q2 and that the remainder when f(x)  is divided by (x+1) is 12,  find the values of the constants p and q.

7
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4 marks

Show that 3x3+16x222x can be written in the form (3x+1)(ax2+bx+c)+d, where a, b, c and d are constants to be found.

1
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3 marks

Divide 4x437x2+9 by (2x1).

2a
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2 marks

f(x)=6x4+7x327x228x+12

Find the remainder when f(x) is divided by (2x+3).

2b
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5 marks

Given that (x+2) is a factor of f(x), factorise f(x) completely. 

3a
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2 marks

f(x)=3x4+x312x249x15

Show that f(x)=(3x+1)(ax3+bx2+cx+d) where a, b, c and d are constants to be found.

3b
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5 marks

Given that (x3) is a factor of f(x), factorise f(x) completely.

3c
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2 marks

Hence show that the equation f(x)=0 has exactly 2 real roots.

4
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4 marks

 Given that 3 is a root of the equation 2x3x211x12=0, prove that the equation has no other real roots.

5a
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1 mark

f(x)=2x415x310x2+105x+98

Show that f(1)=0 and f(2)=0.

5b
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7 marks

Hence, solve f(x)=0.