Exam code: 9709
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Define power.
Power is the rate at which a force does work, that is the work done per second.
It is a scalar, it is measured in watts, and one watt is one joule per second.

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Define power.
Power is the rate at which a force does work, that is the work done per second.
It is a scalar, it is measured in watts, and one watt is one joule per second.
Fill in the two formulae for power:
average power
and, for a force acting in the direction of motion,
Average power , and for a force acting in the direction of motion,
.
The first gives an average over an interval of time, while gives the power at the instant the speed is
.
Which force is used in ?
The driving force of the engine, not the resultant force and not any resistance.
It is worth labelling it on a diagram, since
is already the resultant force in
and is also the usual letter for friction.
Why does a vehicle working at maximum power eventually stop accelerating?
Because with
fixed means the driving force falls as the speed rises.
Once it has fallen far enough to equal the total resistance, the resultant force is zero, so the acceleration is zero and the speed can rise no further.
A car of mass meets a constant resistance of
and has a maximum speed of
. Find the maximum power of its engine.
At maximum speed the acceleration is zero, so the driving force equals the resistance, .
The maximum power is therefore , or
.
The mass is not needed, since neither formula for power involves it.
True or False?
A car travelling at constant speed on a level road has an engine that is doing no work.
False.
The driving force is still moving the car forwards, so it is still doing work, at a rate equal to the engine's power output.
What stays the same is the car's kinetic energy, because all of that work is going into overcoming the resistance.
A car climbs a hill at a known speed, working at a known power. How do you find its acceleration at that moment?
Use to find the driving force at that instant, then apply
along the slope.
The resultant force is the driving force minus the resistance and minus the component of the weight down the slope, and dividing it by the mass gives the acceleration.
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