Equation of a Line in Cartesian Form (DP IB Analysis & Approaches (AA)): Revision Note

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Equation of a Line in Cartesian Form

What is the equation of a line in Cartesian form?

  • The Cartesian form of the equation of a line is fraction numerator x minus x subscript 0 over denominator l end fraction equals fraction numerator y minus y subscript 0 over denominator m end fraction equals fraction numerator z minus z subscript 0 over denominator n end fraction

    • open parentheses x subscript 0 comma space y subscript 0 comma space z subscript 0 close parentheses is the coordinates of any point on the line

    • The vector l bold italic i plus m bold italic j plus n bold italic k is a direction vector of the line

Examiner Tips and Tricks

This is given in the formula booklet under the geometry and trigonometry section. However, you need to remember what the components represent.

How do I find the equation of a line in Cartesian form?

  • You can find the Cartesian form by converting from the parametric form

    • Rearrange each equation to make lambda the subject

      • e.g. x equals x subscript 0 plus lambda l blank rightwards double arrow lambda equals fraction numerator x minus x subscript 0 over denominator l end fraction

    • Set the equations equal to each other

How do I convert from Cartesian form to vector form?

  • STEP 1
    Set each part of the equation equal to lambdaindividually

  • STEP 2
    Rearrange each of these three equations to make x, y, and z the subjects

    • This will give you the three parametric equations

      • x equals x subscript 0 plus lambda l blank

      • y equals y subscript 0 plus lambda m

      • z equals z subscript 0 plus lambda n

  • STEP 3
    Write this in the vector form begin mathsize 16px style open parentheses fraction numerator x over denominator table row y row z end table end fraction close parentheses equals blank open parentheses fraction numerator x subscript 0 over denominator table row cell y subscript 0 end cell row cell z subscript 0 end cell end table end fraction close parentheses plus lambda open parentheses fraction numerator l over denominator table row m row n end table end fraction close parentheses end style

  • STEP 4
    Set bold italic r  to equal begin mathsize 16px style open parentheses fraction numerator x over denominator table row y row z end table end fraction close parentheses end style

What do I do if any of the components of the direction vector are zero?

  • If one component of the direction vector is equal to zero

    • Then the corresponding variable is equal to a constant as it does not change

      • e.g. x equals x subscript 0

    • You write the Cartesian equation using two separate equations

      • e.g. x equals x subscript 0 comma space fraction numerator y minus y subscript 0 over denominator m end fraction equals fraction numerator z minus z subscript 0 over denominator n end fraction

  • If two components of the direction vector are equal to zero

    • Then both corresponding variables are equal to constants

      • e.g. x equals x subscript 0 and z equals z subscript 0

    • You write the Cartesian equation using three separate equations

    • You need to include the parameter for the third equation

      • e.g. x equals x subscript 0 comma space z equals z subscript 0 comma space fraction numerator y minus y subscript 0 over denominator m end fraction equals lambda

Examiner Tips and Tricks

It can help to compare this to the Cartesian equation for a line in 2D. Remember that y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses and m equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction. Combining the two equations, you get:

fraction numerator x minus x subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction equals fraction numerator y minus y subscript 1 over denominator y subscript 2 minus y subscript 1 end fraction

Worked Example

A line has the vector equation begin mathsize 16px style r blank equals blank open parentheses table row 1 row 0 row 2 end table close parentheses plus lambda open parentheses table row 4 row cell negative 2 end cell row 1 end table close parentheses end style. Find the Cartesian equation of the line.

3-10-1-ib-aa-hl-cartesianwe

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Amber

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