De Moivre's Theorem (DP IB Analysis & Approaches (AA)): Revision Note

Amber

Written by: Amber

Reviewed by: Mark Curtis

Updated on

De Moivre's theorem

What is de Moivre’s theorem?

  • De Moivre’s theorem states that forspace z equals r space cis space theta equals r open parentheses cos space theta plus isin space theta close parentheses 

    • z to the power of n space equals space left square bracket r blank left parenthesis cos invisible function application theta plus isin invisible function application theta right parenthesis right square bracket to the power of n blank equals r to the power of n left parenthesis cos invisible function application n theta plus isin invisible function application n theta right parenthesis blank

    • where

      • n element of straight real numbers

      • r equals vertical line z vertical line

      • theta equals arg space z

      • z not equal to 0

  • In exponential (Euler’s) form this is simply

    • open parentheses r straight e to the power of straight i theta end exponent close parentheses to the power of n equals blank r to the power of n straight e to the power of straight i n theta end exponent

      • It confirms that you can use 'index laws' with complex exponentials

Examiner Tips and Tricks

De Moivre's theorem is given in the formula booklet as

left square bracket r left parenthesis cos invisible function application theta plus isin invisible function application theta right parenthesis right square bracket to the power of n equals r to the power of n left parenthesis cos invisible function application n theta plus isin invisible function application n theta right parenthesis equals r to the power of n straight e to the power of straight i n theta end exponent equals r to the power of n blank cis blank n theta blank

Examiner Tips and Tricks

Questions will only ask for rational powers of n, e.g. n equals 3 comma space 10 comma space minus 3 comma space 1 half comma space minus 3 over 4 comma space... but you need to be aware that de Moivre's theorem holds for all real numbers, n element of straight real numbers.

How do I find positive powers of a complex number?

  • To raise a complex number z to a power, n

    • write z in modulus-argument (polar) form

    • apply de Moivre's theorem in the form z to the power of n equals r to the power of n open parentheses cos space n theta plus straight i space sin space n theta close parentheses

    • simplify the real and imaginary parts

  • e.g. if z equals 2 open parentheses cos pi over 12 plus straight i space sin pi over 12 close parentheses, find z to the power of 8

    • z to the power of 8 equals 2 to the power of 8 open parentheses cos open parentheses 8 cross times pi over 12 close parentheses plus straight i space sin open parentheses 8 cross times pi over 12 close parentheses close parentheses

      • using z to the power of n equals r to the power of n open parentheses cos space n theta plus straight i space sin space n theta close parentheses

    • which simplifies to 256 open parentheses cos open parentheses fraction numerator 2 pi over denominator 3 end fraction close parentheses plus straight i space sin open parentheses fraction numerator 2 pi over denominator 3 end fraction close parentheses close parentheses equals 256 open parentheses negative 1 half plus fraction numerator straight i square root of 3 over denominator 2 end fraction close parentheses

      • giving z to the power of 8 equals negative 128 plus 128 square root of 3 space straight i

Examiner Tips and Tricks

In questions where r equals 1, the powers z to the power of 0 open parentheses equals 1 close parentheses comma space z to the power of 1 comma space z squared comma space z cubed comma space... may form a periodic sequence, meaning you could write down, say, z to the power of 101 by spotting the pattern (instead of using de Moivre's theorem)!

How do I find negative powers of a complex number?

  • z to the power of n equals r to the power of n open parentheses cos space n theta plus straight i space sin space n theta close parentheses works for negative powers

    • e.g. 1 over z equals z to the power of negative 1 end exponent equals r to the power of negative 1 end exponent open parentheses cos open parentheses negative theta close parentheses plus straight i space sin open parentheses negative theta close parentheses close parentheses

      • recall that cos open parentheses negative theta close parentheses equals cos space theta and sin open parentheses negative theta close parentheses equals negative sin space theta

      • giving 1 over z equals r to the power of negative 1 end exponent open parentheses cos space theta minus straight i space sin space theta close parentheses

Examiner Tips and Tricks

You must learn the relationships cos open parentheses negative theta close parentheses equals cos space theta and sin open parentheses negative theta close parentheses equals negative sin space theta (they are not given in the formula booklet).

Worked Example

Find the value of begin mathsize 16px style open parentheses fraction numerator square root of 3 over denominator 6 end fraction plus 1 over 6 straight i close parentheses to the power of negative 3 end exponent end style,  giving your answer in the form a plus b straight i.

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Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.