Algebraic Roots & Indices (Edexcel GCSE Maths: Higher): Exam Questions

Exam code: 1MA1

2 hours51 questions
1
1 mark

Simplify      (m2)5

2a
1 mark

Simplify   m5 ÷ m3

2b
2 marks

Simplify    5x4y3 × x2y

3a
1 mark

Simplify    m5 × m3

3b
1 mark

Simplify      p6p2

4a
1 mark

Simplify      p2 × p5

4b
1 mark

Simplify      g6 ÷ g4

4c
1 mark

Simplify       (k3)2

5
1 mark

Simplify    t8 ÷ t3

6a
1 mark

Simplify      (t3)2

6b
1 mark

Simplify     w9w4

7
1 mark

Simplify  (3x2 y)0

8
1 mark

Simplify  x9x2

9
1 mark

Write down the value of g0

10
1 mark

Simplify  e8÷e2

11
1 mark

Simplify w1 × w0

  • 1

  • 0

  • w

  • w2

12
1 mark

Given that y18 ÷ y6 = yk , find the value of k.

k = ...................

13
1 mark

Simplify a6 ÷ a2

14
1 mark

Simplify (b5)3

15
1 mark

Simplify 3y3y4

1
2 marks

Simplify     5u2w4 × 7uw3

2
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2 marks

Simplify     (9x8y3)12

3a
1 mark

Simplify       a4 × a5

3b
2 marks

Simplify           45e6f85ef2

3c
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1 mark

Write down the value of   912

4a
1 mark

Simplify        x7 × x3

4b
1 mark

Simplify       (m4)3

4c
2 marks

Simplify    36af812a5f2

5
2 marks

Simplify      (3x2y4)3

6a
1 mark

Simplify      (p3)2

6b
1 mark

Simplify     t8t3

6c
1 mark

23 × 2n = 29

Work out the value of n.

6d
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1 mark

2x3 = 128

Work out the value of x.

7
2 marks

Simplify fully    p3 × p4p2

8a
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2 marks

Solve     3x2 = 147

8b
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1 mark

Work out the value of 23

8c
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2 marks

Simplify    (3x2)3

8d
2 marks

w = 4p  16

Make p the subject of this formula.

9
2 marks

Simplify       2a3b × 5a2b3

10
2 marks

Simplify fully    n7 × n3n6

11a
1 mark

Simplify    m3 × m4

11b
2 marks

Simplify     (5np3)3

11c
2 marks

Simplify       32q9r44q3r

12
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2 marks

Simplify  (2x3y5 )4

13
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2 marks

Simplify   (16e10 f6 )12

14
3 marks

Simplify fully.

3a8×2a5a2

15
2 marks

Show that a5× (a3)2 can be expressed as a11.

16
2 marks

Simplify 3b2cd2×10bc5dc

17
2 marks

Simplify fully (x6125)23

1
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3 marks

1615 × 2x = 834

Work out the exact value of x.

2a
1 mark

p3 × px = p9

Find the value of x.

2b
1 mark

(72)y = 710

Find the value of y.

2c
2 marks

100a × 1000b can be written in the form 10w

Show that w = 2a + 3b

3a
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1 mark

Simplify fully    (3e)0

3b
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2 marks

Simplify fully      (64x625y2)12

4
1 mark

Given that  (1x3)4=xm

find the value of m

m = .................................................

5
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2 marks

Given that  7206×7m7214=73

find the value of m

m = ..............................................

6
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3 marks

Simplify completely      (16w8y20)34

7
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4 marks

Given that  n(45)=(12)4 where n>0

find the value of n.

n = .............................................

8
2 marks

Given that  y5 × yny6=y13

work out the value of n.

n = ...........................................

9
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1 mark

Simplify fully  (9t4w918t6w10)2

10
4 marks

Given that  4k+3 = 16×2k

find the value of k.
Show your working clearly.

k = .................................................

11
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3 marks

Write 27×(32)7 as a single power of 3

12
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3 marks

Write 16 × 82x as a power of 2 in terms of x

13
1 mark

Choose the expression that is equivalent to 4(2n + 2n1)

  • 2n+2 + 2n+1

  • 22n + 22(n1)

  • 8n + 8n1

  • 2n+2 + 2n1

14
3 marks

Simplify fully   a3b2cd×cab5

15
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4 marks

62+82 = 125a33

Work out the value of a.

16
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2 marks

(arb)4=16r20  where a and b are positive integers.

Work out a and b

a=......................b=......................

17a
2 marks

Simplify 4a12×3a2

17b
3 marks

Simplify [2a2a3]3

18
3 marks

Show that a4 3×1a  can be expressed as a13.

19
3 marks

Show that  (a3)13×(a2)12=1.