Electrochemical Cells (Edexcel International A Level (IAL) Chemistry): Revision Note

Exam code: YCH11

Stewart Hird

Written by: Stewart Hird

Reviewed by: Richard Boole

Updated on

Core Practical 12: Investigating Electrochemical Cells

Measuring the EMF of a cell

  • To measure a cell EMF you will need

    • Two small beakers, around 75 cm3 capacity

    • Strips of suitable metals such as copper, zinc, iron and silver

    • 1.0 mol dm-3 solutions of the metal ions (nitrates, chlorides or sulfates depending on their solubility)

    • A high resistance voltmeter (usually a digital multimeter has this)

    • Two sets of wires with crocodile clips

    • A salt bridge consisting of a strip of filter paper soaked in saturated potassium nitrate

Electrochemistry Calculations - Electrochemical Cell, downloadable AS & A Level Chemistry revision notes

The experimental set up for measuring the EMF of a cell made of two metal / metal ion half cells

The procedure

  • The strips of metals need to be freshly cleaned to remove any oxide coatings

    • This can be done with a piece of sandpaper

  • To support the metals, it is easiest to have long strips that can be folded over the side of the beaker and held in place with the crocodile clips

  • Fill up the beakers to about two thirds of the way with the metal ion solutions

  • Using tongs, dip a strip of filter paper into a beaker of saturated potassium nitrate solution and then place it between the two beakers making sure the ends of the strip are well immersed in the solutions

  • Connect the crocodile clips to the voltmeter, wait for a steady reading and record the measurement

Practical tips

  • If you don't get a positive reading on the voltmeter swap the terminals around

  • Voltmeters will have marked positive and negative terminals (usually in red and black, respectively), so when you get a positive reading this tells you the relative polarity of the metals in the cell

  • Change the salt bridge each time, to prevent cross contamination of ions between half cells

Calculating the Theoretical EMF of a Cell

  • The voltage you measure in your experiment can be compared to a theoretical value calculated using standard electrode potentials (E°)

    • These values are found in the electrochemical series in your data book.

  • The EMF of a cell is the difference between the E° values of the two half-cells

  • The formula is:

E°(cell) = E°(positive electrode) - E°(negative electrode)

  • A simple way to remember this is "most positive E° value minus most negative E° value

Worked Example

Calculate the theoretical EMF for a cell made of zinc and iron.

  1. Find the E° values from a data book:

    • Fe²⁺(aq) + 2e⁻ ⇌ Fe(s) has an E° = -0.44 V

    • Zn²⁺(aq) + 2e⁻ ⇌ Zn(s) has an E° = -0.76 V

  2. Identify the positive and negative electrodes:

    • The half-cell with the more positive (less negative) E° value will be the positive electrode

      • In this case, that is the Fe²⁺/Fe half-cell.

    • The half-cell with the more negative E° value will be the negative electrode

      • This is the Zn²⁺/Zn half-cell.

  3. Apply the formula:

    • E°(cell) = E°(positive) - E°(negative)

    • E°(cell) = (-0.44) - (-0.76)

    • E°(cell) = +0.32 V

This calculation is how the theoretical values in the specimen results table are determined.

Specimen Results

  • Here is a set of typical results for this experiment:

Negative electrode

Positive electrode

EMF / V

Zn (s) / Zn2+ (aq)

Cu2+ (aq) / Cu (s)

1.10

Zn (s) / Zn2+ (aq)

Fe2+ (aq) / Fe (s)

0.32

Fe (s) / Fe2+ (aq)

Cu2+ (aq) / Cu (s)

0.78

Zn (s) / Zn2+ (aq)

Ag+ (aq) / Ag (s)

1.56

Cu (s) / Cu2+ (aq)

Ag+ (aq) / Ag (s)

0.46

Analysis

  • It is unlikely you will get very close to the theoretical results as these would be obtained under standard conditions (1.0 mol dm-3 concentration, 298 K temperature)

    • This is because these conditions are hard to achieve in a school laboratory

  • However, the relative EMF of cells you construct should match the theoretical values

  • The higher the EMF, the larger the difference in reactivity ('electron pushing power') between the metals

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.