Alkanes - Introduction (Edexcel International A Level (IAL) Chemistry): Revision Note
Exam code: YCH11
Alkanes - Introduction
Hydrocarbons are compounds containing hydrogen and carbon only
Some of the hydrocarbon families that you are expected to know include: alkanes, alkenes and arenes
Alkanes and alkenes can be described as aliphatic
Arenes can be described as aromatic
Alkanes have the general molecular formula CnH2n+2
They contain only single bonds and are said to be saturated
Alkanes are named using the nomenclature rule alk + ane
The alk portion of the name depends on the number of carbons
1 carbon = meth
2 carbons = eth
3 carbons = prop
4 carbons = but
5 carbons = pent
After 5 carbons, the naming of alkanes matches the names of the polygons in Maths
The ane portion of the name suggests single bonds between the carbon atoms
The first six alkanes
The first six members of the alkanes are:
Methane
Molecular formula: CH4

Ethane
Molecular formula: C2H6

Propane
Molecular formula: C3H8

Butane
Molecular formula: C4H10

Pentane
Molecular formula: C5H12

Hexane
Molecular formula: C6H14

Types of alkanes
Alkanes can be linear, branched or cyclic
The key points are that there are no functional groups and only single bonds between the carbon atoms
Cycloalkanes have the general formula CnH2n
This general formula is the same as the alkene general formula but cycloalkanes are still saturated
Cycloalkanes are named using the nomenclature rule cyclo + alk + ane
The cyclo portion of the name shows that there is a ring structure
As with alkanes, the alk portion of the name depends on the number of carbons
The ane portion of the name suggests single bonds between the carbon atoms

Alkanes are compounds made up of carbon and hydrogen atoms only and contain no functional group
Alkanes - Reactions
The unreactive nature of alkanes can be explained by two factors
The high bond enthalpies of the C-C and C-H bonds
The very low polarity of the sigma (σ) bonds present
Bond enthalpy
The C-C bond has a mean bond enthalpy of about 347 kJ mol-1 and the C-H bond has a mean bond enthalpy of about 413 kJ mol-1
The C-H bond is stronger as the bond length is less than the C-C bond
This is because the hydrogen atom only consists of one shell, so the distance between the nuclei is shorter
Creating greater force of attraction to the nuclei and the pair of electrons between them
Polarity
The electronegativities of carbon and hydrogen are very similar, therefore the bonds will have very low polarity

Ethane is an example of an alkane that lacks polarity due to almost similar electronegativities of the carbon and hydrogen atoms
Alkanes are combusted (burnt) on a large scale for their use as fuels
Complete combustion
When alkanes are burnt in excess (plenty of) oxygen, complete combustion will take place
This means that all carbon and hydrogen will be oxidised to carbon dioxide and water respectively
alkane + oxygen carbon dioxide + water
For example, the complete combustion of octane to carbon dioxide and water
2C8H18 + 25O2 → 16CO2 + 18H2O
Incomplete combustion
When alkanes are burnt in only a limited supply of oxygen, incomplete combustion will take place and not all the carbon is fully oxidised
Some carbon is only partially oxidised to form carbon monoxide
alkane + oxygen carbon monoxide + water
For example, the incomplete combustion of octane to form carbon monoxide
2C8H18 + 17O2 → 16CO + 18H2O
Incomplete combustion often takes place inside a car engine due to a limited amount of oxygen present
With a reduced supply of oxygen, carbon will be produced in the form of soot:
alkane + oxygen carbon + water
For example, the incomplete combustion of octane to form carbon
2C8H18 + 9O2 → 16C + 18H2O
Free-radical substitution
Alkanes can undergo free-radical substitution in which a hydrogen atom gets substituted by a halogen (chlorine / bromine)
Since alkanes are very unreactive, ultraviolet light (sunlight) is needed for this substitution reaction to occur
The free-radical substitution reaction consists of three steps:
In the initiation step, the halogen bond (Cl-Cl or Br-Br) is broken by UV energy to form two radicals
These radicals create further radicals in a chain reaction called the propagation step
The reaction is terminated when two radicals collide with each other in a termination step

The fact that the bromine colour has disappeared only when mixed with an alkane and placed in sunlight suggests that the ultraviolet light is essential for the free radical substitution reaction to take place
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