Quadratic Formula (SQA National 5 Maths): Revision Note

Exam code: X847 75

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Solving a quadratic equation using the quadratic formula

What is the quadratic formula?

  • A quadratic equation has the form ax2 + bx + c = 0 (where a ≠ 0)

    • you need "= 0" on one side

  • The quadratic formula is a formula that gives both solutions to a quadratic equation:

x equals fraction numerator negative b plus-or-minus square root of open parentheses b squared minus 4 a c close parentheses end root over denominator 2 a end fraction

Examiner Tips and Tricks

The quadratic formula is given to you on the Formulae List in the exam paper.

Just make sure the quadratic equation has "= 0" on the right-hand side. Otherwise it needs rearranging first

How do I use the quadratic formula to solve a quadratic equation?

  • Read off the values of a, b and c from the equation

  • Substitute these into the formula

    • Write this line of working in the exam

    • Put brackets around any negative numbers being substituted in

  • To solve 2x2 - 8x - 3 = 0 using the quadratic formula:

    • a = 2, b = -8 and c = -3

    • x equals fraction numerator negative open parentheses negative 8 close parentheses plus-or-minus square root of open parentheses negative 8 close parentheses squared minus 4 cross times 2 cross times open parentheses negative 3 close parentheses end root over denominator 2 cross times 2 end fraction

    • Either type this into a calculator or simplify by hand

      • Type it once using + for  ± then again using - for  ±

    • The solutions are x = 4.345207... or x = -0.345207....

      • To 3 decimal places: x = 4.345 or x = -0.345

      • To 3 significant figures: x = 4.35 or x = -0.345

Examiner Tips and Tricks

The instruction 'give your answer to ... decimal places' or 'give your answer to ... significant figures' is a very strong hint that a quadratic equation should be solved using the quadratic formula.

Be sure to give your answer to the required degree of accuracy.

How do I write the solutions in an exact (surd) form?

  • It is also possible to give answers in an exact (surd) form

  • For the example above, work out the number under the square root sign

    • Be careful with negatives!

      • open parentheses negative 8 close parentheses squared minus 4 cross times 2 cross times open parentheses negative 3 close parentheses equals 64 plus 24 equals 88

    • Now take the square root of this number and use surd rules to simplify

      • square root of 88 equals square root of 4 cross times 22 end root equals square root of 4 cross times square root of 22 equals 2 square root of 22

    • Substitute this back into the formula and simplify

      • x equals fraction numerator 8 plus-or-minus 2 square root of 22 over denominator 4 end fraction equals fraction numerator 2 open parentheses 4 plus-or-minus square root of 22 close parentheses over denominator 4 end fraction equals fraction numerator 4 plus-or-minus square root of 22 over denominator 2 end fraction

      • The solutions in exact (surd) form are x equals fraction numerator 4 plus square root of 22 over denominator 2 end fraction or x equals fraction numerator 4 minus square root of 22 over denominator 2 end fraction

  • Calculators that can solve quadratics will give solutions in exact (surd) form

Can I use my calculator to solve quadratic equations?

  • If your calculator solves quadratic equations, use it to check your final answers

    • But a correct method and working must still be shown

  • If your calculator gives you solutions with terms containing bold i, these are "complex" and are not what you are looking for

    • You may have made a mistake entering the quadratic equation

    • Or the equation may not have any real number solutions

Worked Example

Solve the equation 3 x squared minus 2 x minus 4 equals 0.

Give your answers correct to 2 decimal places.

Answer:

Write down the values of a, b and c

a = 3, b = -2, c = -4
 

Substitute these values into the quadratic formula, x equals fraction numerator negative b plus-or-minus square root of open parentheses b squared minus 4 a c close parentheses end root over denominator 2 a end fraction

  • Put brackets around any negative numbers

x equals fraction numerator negative open parentheses negative 2 close parentheses plus-or-minus square root of open parentheses negative 2 close parentheses squared minus 4 cross times 3 cross times open parentheses negative 4 close parentheses end root over denominator 2 cross times 3 end fraction 

Use your calculator to evaluate this expression

First the 'plus' version

table row x equals cell fraction numerator negative open parentheses negative 2 close parentheses plus square root of open parentheses negative 2 close parentheses squared minus 4 cross times 3 cross times open parentheses negative 4 close parentheses end root over denominator 2 cross times 3 end fraction end cell row blank equals cell fraction numerator 1 plus square root of 13 over denominator 3 end fraction end cell row blank equals cell 1.535183... end cell end table

Then the 'minus' version

table row x equals cell fraction numerator negative open parentheses negative 2 close parentheses minus square root of open parentheses negative 2 close parentheses squared minus 4 cross times 3 cross times open parentheses negative 4 close parentheses end root over denominator 2 cross times 3 end fraction end cell row blank equals cell fraction numerator 1 minus square root of 13 over denominator 3 end fraction end cell row blank equals cell negative 0.868517... end cell end table

Round to 2 decimal places, as required

x equals 1.54 space space or space space x equals negative 0.87 space space open parentheses 2 space straight d. straight p. close parentheses

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Roger B

Author: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.