Discriminant (SQA National 5 Maths): Revision Note

Exam code: X847 75

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Using the discriminant to determine the nature of roots

What is the discriminant?

  • Recall the quadratic formula  x=b±(b24ac)2a

    • which gives the solutions to the quadratic equation ax2+bx+c=0

  • The part of the formula under the square root, b2 – 4ac, is called the discriminant

How can I use the discriminant to determine the nature of the roots of a quadratic function?

  • A quadratic function is a function that can be written in the form  f(x)=ax2+bx+c, where a0

    • The roots of a quadratic function are the solutions to the equation  f(x)=0

      • I.e. to the quadratic equation ax2+bx+c=0

  • The sign of the discriminant tells you about the roots of the quadratic function

    • If b2 – 4ac > 0 (positive)

      • then the function has two real and distinct roots

        • i.e. the equation has two solutions, and they are different from each other

    • If b2 – 4ac = 0 

      • then the function has one repeated real root (which may also be described as two equal real roots)

        • i.e. the equation only has one distinct solution (which may also be seen as it having two solutions which are the same)

    • If b2 – 4ac < 0 (negative)

      • then the function has no real roots

        • i.e. the equation has no real number solutions

  • Interestingly, if b2 – 4ac is a perfect square number ( 1, 4, 9, 16, …) then this tells you that the quadratic expression ax2 + bx + c can be factorised!

Examiner Tips and Tricks

When an exam question asks you to describe the roots of a function, this is a strong hint that you will need to use the discriminant in your answer.

Be sure to use the official terms to describe the roots:

  • 'two real and distinct roots'

  • 'one repeated real root' (or 'two equal real roots')

  • 'no real roots'

Worked Example

Determine the nature of the roots of each of the following functions:

(a)  f(x)=16x28x+1

(b)  g(x)=3x2+5x2

(c)  h(x)=9x2+3x+1

Answer:

Part (a)

Calculate the value of the discriminant

  • a=16, b=8, c=1

b24ac=(8)24(16)(1)=6464=0

That is equal to zero, so

One repeated real root  (or Two equal real roots)
 

Part (b)

Calculate the value of the discriminant

  • a=3, b=5, c=2

b24ac=(5)24(3)(2)=25+24=49

49>0

That is greater than zero, so

Two real and distinct roots
 

Part (c)

Calculate the value of the discriminant

  • a=9, b=3, c=1

b24ac=(3)24(9)(1)=936=27

27<0

That is less than zero, so

No real roots

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.