Vector Pathways (SQA National 5 Maths): Revision Note

Exam code: X847 75

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Vector pathway basics

How do I find the vector between two points?

  • A vector pathway is a path of vectors taking you from a start point to an end point

  • The following grid is made up entirely of parallelograms

    • The vectors a and b are defined as marked in the diagram:

      • Any vector that goes horizontally to the right along a side of a parallelogram will be equal to a

      • Any vector that goes up diagonally to the right along a side of a parallelogram will be equal to b

Vectors on a grid of parallelograms
  • To find the vector between two points

    • Count how many times you need to go horizontally to the right

      • This will tell you how many a's are in your answer

    • Count how many times you need to go up diagonally to the right

      • This will tell you how many b's are in your answer

    • Add the a's and b's together

      • E.g. stack A R with rightwards arrow on top equals 2 bold a plus 3 bold b

  • You will have to put a negative in front of the vector if it goes in the opposite direction

    • -a is one length horizontally to the left

    • -b is one length down diagonally to the left

      • E.g. stack F B with rightwards arrow on top equals negative bold b plus bold a or stack F B with rightwards arrow on top equals bold a minus bold b

      • Likewise, stack B F with rightwards arrow on top equals negative stack F B with rightwards arrow on top equals negative open parentheses negative bold b plus bold a close parentheses equals bold b minus bold a

Vector paths on a grid
  • It is possible to describe any vector that goes from one point to another in the above diagram in terms of a and b

Examiner Tips and Tricks

In the exam, different correct pathways will earn full marks, as long as the final answer is fully simplified.

Check for symmetries in the diagram to see if the vectors given can be used anywhere else.

Worked Example

The following diagram consists of a grid of identical parallelograms.

Vectors a and b are defined by bold a space equals space AB with rightwards arrow on top and bold b bold space equals space AF with rightwards arrow on top.

Vector parallelogram grid with vectors a and b shown.

Write the following vectors in terms of a and b.

a) AE with rightwards arrow on top

b) GT with rightwards arrow on top

c) EK with rightwards arrow on top

Answer:

Part (a)

To get from A to E you need to follow vector bold a four times to the right 

table row cell AE with rightwards arrow on top space end cell equals cell space AB with rightwards arrow on top space plus thin space BC with rightwards arrow on top space plus space CD with rightwards arrow on top space plus space DE with rightwards arrow on top end cell row blank equals cell space bold a space plus bold space bold a space space plus space bold a space plus space bold a end cell end table

AE with rightwards arrow on top equals 4 bold a 

Part (b)

There are many ways to get from G to T

One option is to go from G to Q (bold b twice), and then from Q to T (bold a three times) 

table row cell GT with rightwards arrow on top space end cell equals cell space GL with rightwards arrow on top space plus thin space LQ with rightwards arrow on top space plus space QR with rightwards arrow on top space plus space RS with rightwards arrow on top space plus space ST with rightwards arrow on top end cell row blank equals cell bold b space plus space bold b space plus space bold a space plus space bold a space plus space bold a end cell end table

GT with rightwards arrow on top equals 2 bold b plus 3 bold a space space open parentheses or space 3 bold a plus 2 bold b close parentheses

Part (c)

There are many ways to get from E to K
One option is to go fromto O (bold b twice), and then from O to ( negative bold a four times)

table row cell EK with rightwards arrow on top space end cell equals cell space EJ with rightwards arrow on top space plus thin space JO with rightwards arrow on top space plus space ON with rightwards arrow on top space plus space NM with rightwards arrow on top space plus space ML with rightwards arrow on top space plus space LK with rightwards arrow on top space space end cell row blank equals cell bold b space plus space bold b space minus space bold a space minus space bold a space minus space bold a bold space minus bold space bold a end cell end table

EK with rightwards arrow on top equals 2 bold b minus 4 bold a space space open parentheses or space minus 4 bold a plus 2 bold b close parentheses

Finding more challenging vector pathways

How can vector pathway questions be made more challenging?

  • You may need to find expressions for vectors in places where you cannot simply count spaces on a grid

  • You should be familiar with the properties of different types of triangle and quadrilateral

    • You may need to use these properties to answer a vector pathway question

  • Look out for places where two vectors in a diagram are equal or where one is a multiple of the other

How do I use multiples in vector pathways?

  • When multiplying a vector by a scalar number, you can use the normal rules of algebra

    • E.g. expanding brackets, collecting like terms

Vector line divided into a ratio
  • In the example shown, if AX with rightwards arrow on top equals 3 over 8 AB with rightwards arrow on top and you know that AB with rightwards arrow on top equals 3 bold p minus bold q then

    • AX with rightwards arrow on top equals 3 over 8 open parentheses 3 bold p minus bold q close parentheses equals 9 over 8 bold p minus 3 over 8 bold q

  • Questions may specify that a point is the midpoint of a line segment

    • E.g. point straight M may be the midpoint of line segment AB

    • This means that AM with rightwards arrow on top equals 1 half AB with rightwards arrow on top and MB with rightwards arrow on top equals 1 half AB with rightwards arrow on top

  • Note that if one vector is a multiple of another, this means that the vectors are parallel

    • E.g. 2 open parentheses bold a minus bold b close parentheses is parallel to bold a minus bold b

      • It is twice as long and points in the same direction

    • negative 3 open parentheses bold a minus bold b close parentheses is also parallel to bold a minus bold b

      • It is three times as long and points in the opposite direction (because of the minus sign)

  • If two vectors are parallel, have the same length and point in the same direction

    • then they are equal

Worked Example

The diagram shows a parallelogram PQRS with a diagonal QS drawn.

Parallelogram PQRS with diagonal QS. Arrows on QR and QS indicate the vectors 'a' and 'b'. Point T lies on line PS.

QR with rightwards arrow on top represents vector bold a and QS with rightwards arrow on top represents vector bold b.

a) Express RS with rightwards arrow on top in terms of bold a and bold b.

straight T is the point such that PT equals 1 third PS.

b) Express RT with rightwards arrow on top in terms of bold a and bold b. Give your answer in simplest form.

Answer:

Part (a)

To get from R to S you can go

  • the 'wrong way' down vector bold a to Q

  • then the 'right way' down vector bold b to S

RS with rightwards arrow on top equals negative bold a plus bold b space space open parentheses or space bold b minus bold a close parentheses

Part (b)

Write RT with rightwards arrow on top as a vector pathway; one possibility is

RT with rightwards arrow on top equals RQ with rightwards arrow on top plus QP with rightwards arrow on top plus PT with rightwards arrow on top

Use what you know about those vectors

  • RQ with rightwards arrow on top equals negative QR with rightwards arrow on top equals negative bold a

  • Because PQRS is a parallelogram, sides QP and RS are parallel and the same length

    • Therefore QP with rightwards arrow on top equals RS with rightwards arrow on top equals negative bold a plus bold b (using the answer from part (a) )

  • Also because PQRS is a parallelogram, sides PS and QR are parallel and the same length

    • And space PT equals 1 third PS

    • So space PT with rightwards arrow on top equals 1 third PS with rightwards arrow on top equals 1 third QR with rightwards arrow on top equals 1 third bold a

RT with rightwards arrow on top equals negative bold a plus open parentheses negative bold a plus bold b close parentheses plus 1 third bold a

Collect like terms and simplify

RT with rightwards arrow on top equals negative 5 over 3 bold a plus bold b space space open parentheses or space bold b minus 5 over 3 bold a close parentheses

Worked Example

In triangle ABC, space AC with rightwards arrow on top equals open parentheses table row 8 row cell negative 2 end cell end table close parentheses space and space CB with rightwards arrow on top equals open parentheses table row cell negative 1 end cell row 7 end table close parentheses.

A scalene triangle ABC with point M as the midpoint of segment AC.

a) Express AB with rightwards arrow on top in component form.

straight M is the midpoint of AC.

b) Express MB with rightwards arrow on top in component form.

Answer:

Part (a)

Find a path from A to B using vectors whose components you know

  • You can get from A to B by going from A to C, then from C to B

AB with rightwards arrow on top equals AC with rightwards arrow on top plus CB with rightwards arrow on top

Substitute in the components from the question

AB with rightwards arrow on top equals open parentheses table row 8 row cell negative 2 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell row 7 end table close parentheses

Add the components

AB with rightwards arrow on top equals open parentheses table row cell 8 plus open parentheses negative 1 close parentheses end cell row cell negative 2 plus 7 end cell end table close parentheses

AB with rightwards arrow on top equals open parentheses table row 7 row 5 end table close parentheses

Part (b)

Write MB with rightwards arrow on top as a vector pathway; one possibility is

MB with rightwards arrow on top equals MC with rightwards arrow on top plus CB with rightwards arrow on top

straight M is the midpoint of AC

  • That means that MC with rightwards arrow on top equals 1 half AC with rightwards arrow on top

MB with rightwards arrow on top equals 1 half AC with rightwards arrow on top plus CB with rightwards arrow on top

Substitute in the components from the question

MB with rightwards arrow on top equals 1 half open parentheses table row 8 row cell negative 2 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell row 7 end table close parentheses

Multiply the components of open parentheses table row 8 row cell negative 2 end cell end table close parentheses by 1 half

MB with rightwards arrow on top equals open parentheses table row 4 row cell negative 1 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell row 7 end table close parentheses

Add the components

MB with rightwards arrow on top equals open parentheses table row cell 4 plus open parentheses negative 1 close parentheses end cell row cell negative 1 plus 7 end cell end table close parentheses

MB with rightwards arrow on top equals open parentheses table row 3 row 6 end table close parentheses

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Roger B

Author: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.