Reverse Percentages (SQA National 5 Maths): Revision Note
Exam code: X847 75
Working with reverse percentages
What is a reverse percentage?
A reverse percentage question is one where you are given the value after a percentage increase or decrease and are asked to find the value before the change
Examiner Tips and Tricks
You should be familiar with calculating percentage increases and decreases from your National 4 Maths course.
For example, to increase an amount by 5%
The new amount will be 100%+5%=105% of the original amount
As a decimal number, 105%=1.05
So multiply the original amount by the multiplier, 1.05, to find the new amount
Or to decrease an amount by 5%
The new amount will be 100%-5%=95% of the original amount
As a decimal number, 95%=0.95
So multiply the original amount by the multiplier, 0.95, to find the new amount
How do I solve reverse percentage questions using percentage multipliers?
You should think about the before quantity
even though it is not given in the question
Find the percentage change as a multiplier,
This is the decimal equivalent of a percentage change
A percentage increase of 4% means
= 1 + 0.04 = 1.04
A percentage decrease of 7% means
= 1 - 0.07 = 0.93
Use
to write an equation
Get the order right: the percentage change happens to the "before", not to the "after"
Rearrange the equation to make the "before" quantity the subject
Divide the "after" quantity by the multiplier, p
How do I solve reverse percentage questions by scaling?
This is best seen through an example:
Prices in a sale have been reduced by 10%. In the sale the price of a games console is £441. What was the price of the games console before the sale?
The new price is 100-10=90% of the original price
So 90% = £441
That means 1% =
= £4.90
And therefore 100% = 4.90
100 = £490
The price of the games console before the sale was £490
Examiner Tips and Tricks
Make sure you are confident with at least one method to solve reverse percentage questions.
What is a common mistake with reverse percentage questions?
Here is an example: a price of a mobile increases by 10% to £220
To find the price before, you do not apply a 10% decrease to £220
That would give 220
0.9 = £198 (incorrect)
Use before × p = after instead
before
1.1 = 220
before =
= £200 (correct)
Examiner Tips and Tricks
To spot a reverse percentage question, see if you are being asked to find a quantity in the past.
E.g. 'Find the old / original / before amount ...'
Worked Example
This year Jennie's salary is £33,170.
This is an increase of 7% on last year's salary.
Calculate Jennie's salary last year.
Answer:
Method 1 - Using percentage multipliers
Use "before" × p = "after" to write an equation
The "before" amount is unknown
The "after" amount is 31 500
The multiplier for a 7% increase is p = 1 + 0.07 = 1.07
"before" × 1.07 = 33 170
Find the value of "before" by dividing both sides by 1.07
"before" = = 31 000
She was paid £31 000 before the pay rise
Jennie's salary last year was £31,000
Method 2 - Using scaling
This year's salary is 100+7 = 107% of last year's salary
107% = 33 170
Therefore
1% = = 310
And
100% = 310100 = 31 000
She was paid £31 000 before the pay rise
Jennie's salary last year was £31,000
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