Gravitational Potential (Cambridge (CIE) A Level Physics): Flashcards

Exam code: 9702

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  • Define gravitational potential, φ.

Cards in this collection (8)

  • Define gravitational potential, φ.

    The work done per unit mass in bringing a small test mass from infinity to that point.

  • Why does gravitational potential always have a negative value?

    It is defined as zero at infinity, and since the gravitational force is attractive, work must be done on a mass to move it away from the mass to infinity, so the potential at any closer point is lower than zero.

  • How does gravitational potential change with distance from a mass?

    It increases (becomes less negative) as distance from the mass increases.

  • State the equation for gravitational potential φ due to a point mass M at distance r, and define each symbol.

    \phi = -\frac{GM}{r}

    • φ = gravitational potential (J kg-1)

    • G = Newton's gravitational constant

    • M = mass of the body producing the field (kg)

    • r = distance from the centre of the mass to the point (m)

  • The gravitational potential difference between two points is given by \Delta \phi = \phi_{f} - \phi_{i}, where \phi_{f} is the .......... gravitational potential.

    The gravitational potential difference between two points is given by \Delta \phi = \phi_{f} - \phi_{i}, where \phi_{f} is the final gravitational potential.

  • Define the gravitational potential energy of a system of two point masses, and state the equation.

    The work done to assemble the system from infinite separation of its components: E_{p} = -\frac{Gm_{1}m_{2}}{r}

  • State the equation relating the work done, W, to move a mass m in a gravitational field to the change in gravitational potential, ΔV.

    W = m\Delta V

  • True or False?

    The equation ΔG.P.E. = mgΔh can be used to find the change in gravitational potential energy of a satellite moving between two orbits far above the Earth's surface.

    False.

    mgΔh only applies in a uniform gravitational field near the Earth's surface. Far from the surface, g is not constant, so \Delta E_{p} = Gm_{1}m_{2}\left(\frac{1}{r_{1}} - \frac{1}{r_{2}}\right) must be used instead.

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