Principles of Transition Metal Chemistry (Edexcel A Level Chemistry): Flashcards

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  • Define transition metal.

Cards in this collection (104)

  • Define transition metal.

    A transition metal is an element with an incomplete d-subshell that can form at least one stable ion with an incomplete d-subshell.

  • Why are scandium and zinc not classed as transition metals?

    Scandium and zinc are not transition metals because they do not form stable ions with an incomplete d-subshell.

    Sc only forms Sc3+ with configuration [Ar]3d0; Zn only forms Zn2+ with configuration [Ar]3d10.

  • What are the four characteristic properties of transition metals?

    Transition metals show four characteristic properties: variable oxidation states, the ability to form complex ions, the formation of coloured compounds, and the ability to act as catalysts.

  • Chromium has the electron configuration [Ar]3d54s1 rather than [Ar]3d44s2 because the ..........-filled d-subshell configuration is .......... more stable.

    Chromium has the electron configuration [Ar]3d54s1 rather than [Ar]3d44s2 because the half-filled d-subshell configuration is energetically more stable.

  • True or False?

    When transition metal atoms form ions, electrons are lost from the 3d subshell before the 4s subshell.

    False.

    Electrons are lost from the 4s subshell first. Once the orbitals are occupied, repulsion raises the 4s above the 3d in energy, making 4s the outer shell that is removed first.

  • What are variable oxidation states?

    Variable oxidation states are the ability of an element to form ions with more than one oxidation state.

    Transition metals show this property because successive ionisation energies of 3d and 4s electrons are similar, making multiple states energetically accessible.

  • Why is +2 a common oxidation state for transition metals?

    The +2 oxidation state is common because transition metals lose their two 4s electrons first when forming ions, leaving the 3d electrons intact.

  • The electron configuration of Mn3+ is 1s22s22p63s23p63d.........., because manganese has atomic number .......... and loses .......... electrons.

    The electron configuration of Mn3+ is 1s22s22p63s23p63d4, because manganese has atomic number 25 and loses 3 electrons.

  • True or False?

    Copper's ground state electron configuration is [Ar]3d94s2.

    False.

    Copper's configuration is [Ar]3d104s1. An electron is promoted from 4s to 3d to achieve a fully filled d-subshell, which is energetically more stable.

  • Define complex ion.

    A complex ion is a central metal ion surrounded by ligands that have each donated a lone pair of electrons to form coordinate bonds with the metal.

  • How is the overall charge on a complex ion determined?

    The overall charge on a complex ion is determined by summing the oxidation state of the central metal ion and the charges of all the ligands.

    If ligands are neutral, the overall charge equals the oxidation state of the metal.

  • Define ligand.

    A ligand is a molecule or ion that forms a coordinate (dative covalent) bond with a transition metal by donating a lone pair of electrons to the bond.

  • How are complex ions named when the overall ion is an anion?

    When the overall ion is an anion, the metal name is modified with the suffix -ate and sometimes a Latin stem is used.

    For example, copper becomes cuprate and nickel becomes nickelate.

  • In a complex ion, the ligands donate a .......... pair of electrons to the central metal ion, forming a .......... bond.

    In a complex ion, the ligands donate a lone pair of electrons to the central metal ion, forming a coordinate (dative covalent) bond.

  • What is the coordination number of the metal ion in [Fe(CN)6]3-?

    The coordination number of the iron ion in [Fe(CN)6]3- is 6, because there are six cyanide ligands each forming one coordinate bond with the central Fe3+ ion.

  • Define coordination number.

    The coordination number is the total number of coordinate bonds formed between ligands and the central metal atom or ion in a complex.

  • True or False?

    Ligands must carry a negative charge to donate a lone pair to a metal ion.

    False.

    Ligands can be neutral molecules or negatively charged ions, as long as they possess a lone pair of electrons available for donation. For example, H2O and NH3 are neutral ligands.

  • The ligand ammonia is named .......... when part of a complex, spelt with .......... m's, and the prefix for six ligands is .......... .

    The ligand ammonia is named ammine when part of a complex, spelt with two m's, and the prefix for six ligands is hexa.

  • Why do transition metal compounds appear coloured?

    Transition metal compounds appear coloured because they absorb certain frequencies of visible light, and the colour observed is the complementary colour to the light absorbed.

  • What is d-orbital splitting?

    D-orbital splitting is the separation of the five d-orbitals into two groups of different energy when ligands bond to a central transition metal ion, enabling electrons to absorb visible light and move to the higher energy level.

  • True or False?

    Zn2+ compounds are coloured because zinc has a partially filled d-subshell.

    False.

    Zn2+ has a completely filled 3d10 subshell. No d-orbital splitting and electron promotion is possible, so Zn2+ compounds are colourless.

  • A compound appears green because it absorbs all parts of the visible spectrum except .......... light, which is ...........

    A compound appears green because it absorbs all parts of the visible spectrum except green light, which is transmitted.

  • What four factors influence the size of the d-orbital splitting energy ΔE?

    The four factors that influence ΔE are:

    • The size and type of ligands

    • The nuclear charge and identity of the metal ion

    • The oxidation state of the metal

    • The shape of the complex

  • Why do [Cu(H2O)6]2+ and [Cu(NH3)4(H2O)2]2+ have different colours?

    The two complexes have different colours because NH3 has a higher charge density than H2O, causing greater d-orbital splitting.

    [Cu(H2O)6]2+ is light blue; [Cu(NH3)4(H2O)2]2+ is dark blue.

  • True or False?

    A higher oxidation state on the same metal always produces greater d-orbital splitting.

    True.

    A higher oxidation state creates a stronger interaction between the metal ion and its ligands, increasing the splitting energy ΔE. For example, [Fe(H2O)6]3+ absorbs in the blue region (appearing orange), while [Fe(H2O)6]2+ absorbs in the red region (appearing green).

  • What is the relationship between splitting energy ΔE and the frequency of light absorbed?

    The splitting energy ΔE is directly proportional to the frequency of the light absorbed and inversely proportional to its wavelength.

    A larger ΔE means higher-frequency (shorter-wavelength) light is absorbed.

  • Complementary colours are colours that are directly .......... each other on the .......... wheel.

    Complementary colours are colours that are directly opposite each other on the colour wheel.

  • Define monodentate.

    A monodentate ligand is one that forms only one dative bond to the central metal ion, because it has a single lone pair available for donation.

  • Give four examples of monodentate ligands.

    Four examples of monodentate ligands are:

    • Water (H2O)

    • Ammonia (NH3)

    • Chloride ions (Cl-)

    • Cyanide ions (CN-)

  • Define bidentate.

    A bidentate ligand is one that forms two dative bonds to the central metal ion, because it contains two atoms each with a lone pair available for donation.

  • What are the two common examples of bidentate ligands?

    The two common bidentate ligands are:

    • 1,2-diaminoethane (H2NCH2CH2NH2), also written as 'en'

    • Ethanedioate ion (C2O42-), also written as 'ox'

  • A monodentate ligand forms .......... dative bond; a bidentate ligand forms .......... ; EDTA4- is .......... and forms .......... dative bonds.

    A monodentate ligand forms one dative bond; a bidentate ligand forms two; EDTA4- is hexadentate and forms six dative bonds.

  • True or False?

    A ligand must carry a negative charge in order to act as a monodentate ligand.

    False.

    Monodentate ligands can be neutral molecules or anions. H2O and NH3 are neutral monodentate ligands; Cl- and CN- are anionic monodentate ligands. The requirement is a lone pair, not a charge.

  • Define multidentate.

    A multidentate ligand is one that forms more than two dative bonds to the central metal ion, because it contains more than two atoms with lone pairs available for donation.

  • True or False?

    1,2-diaminoethane forms two dative bonds because each nitrogen atom donates one lone pair to the central metal ion.

    True.

    1,2-diaminoethane (en) contains two nitrogen atoms, each with a lone pair. It is therefore a bidentate ligand that chelates the metal ion by forming two coordinate bonds.

  • EDTA4- is classified as a .......... ligand because it contains .......... atoms with lone pairs, allowing it to form .......... dative bonds to a metal ion.

    EDTA4- is classified as a hexadentate ligand because it contains six atoms with lone pairs, allowing it to form six dative bonds to a metal ion.

  • Define octahedral complex.

    An octahedral complex is a transition metal complex in which the central metal ion forms six coordinate (dative covalent) bonds with surrounding ligands, giving bond angles of 90°.

  • In an octahedral complex, six coordinate bonds may be formed with six .......... ligands — for example, water or ammonia molecules — or with three .......... ligands, each donating two bonds.

    In an octahedral complex, six coordinate bonds may be formed with six monodentate ligands — for example, water or ammonia molecules — or with three bidentate ligands, each donating two bonds.

  • What are bidentate ligands?

    Bidentate ligands are ligands that each form two dative covalent bonds to the central metal ion. Three bidentate ligands give six coordinate bonds in total, producing an octahedral complex. Examples include 1,2-diaminoethane and the ethanedioate ion.

  • What types of ligand can form an octahedral complex?

    An octahedral complex can be formed with six monodentate ligands (such as H2O, NH3, OH-, or SCN-), three bidentate ligands (such as 1,2-diaminoethane or ethanedioate), or one multidentate ligand such as EDTA4-, which forms all six coordinate bonds.

  • Define coordination number.

    The coordination number is the total number of dative covalent bonds formed between the central metal ion and its ligands. In an octahedral complex, the coordination number is 6.

  • Why are octahedral complexes with six monodentate ligands sometimes described as having six-fold coordination?

    They are described as having six-fold coordination because the central metal ion forms six separate coordinate bonds, one to each of the six monodentate ligands surrounding it.

  • True or False?

    The bond angles in an octahedral complex are 90°.

    True.

    All six ligands are arranged symmetrically around the central metal ion in three dimensions, giving bond angles of exactly 90° throughout the complex.

  • How does EDTA4- form an octahedral complex with a transition metal ion?

    EDTA4- is a multidentate ligand that forms all six coordinate bonds to the central metal ion by itself, satisfying the six-fold coordination requirement of an octahedral complex in a single ligand.

  • True or False?

    When using VSEPR to predict the shape of a transition metal complex, the 3d electrons on the metal ion are included in the count.

    False.

    When applying electron pair repulsion theory to transition metal complexes, the 3d electrons on the metal ion and the overall charge on the complex are ignored. Only the electron pairs donated by the ligands are counted.

  • Define tetrahedral complex.

    A tetrahedral complex is a transition metal complex in which the central metal ion forms four coordinate bonds with surrounding ligands arranged at bond angles of 109.5°.

  • Why do complexes with four chloride ligands tend to adopt a tetrahedral rather than an octahedral geometry?

    Chloride ligands are large, so only four can fit around the central metal ion without excessive steric repulsion. This gives a tetrahedral arrangement with bond angles of 109.5°.

  • True or False?

    The bond angles in a tetrahedral complex are 90°.

    False.

    Tetrahedral complexes have bond angles of 109.5°, not 90°. Bond angles of 90° are characteristic of octahedral and square planar complexes.

  • What is the coordination number of a tetrahedral complex?

    The coordination number of a tetrahedral complex is 4, since the central metal ion forms four dative covalent bonds with the surrounding ligands.

  • Tetrahedral complexes most commonly form with four .......... ligands because these ligands are too .......... for six to fit around the central metal ion.

    Tetrahedral complexes most commonly form with four chloride ligands because these ligands are too large for six to fit around the central metal ion.

  • How does a tetrahedral complex differ from an octahedral complex in terms of coordination number and bond angles?

    A tetrahedral complex has a coordination number of 4 and bond angles of 109.5°. An octahedral complex has a coordination number of 6 and bond angles of 90°.

  • True or False?

    Complexes with four coordinate bonds always adopt a tetrahedral geometry.

    False.

    Complexes with four coordinate bonds can also adopt a square planar geometry. Tetrahedral geometry is most common when the ligands are large (such as Cl-), while square planar geometry occurs with certain ligands such as CN-.

  • Give an example of a tetrahedral complex and state its formula.

    The tetrachlorocuprate(II) ion, [CuCl4]2-, is an example of a tetrahedral complex. The four large Cl- ligands adopt a tetrahedral arrangement around the Cu2+ central ion.

  • What is cisplatin?

    Cisplatin is a square planar platinum(II) complex, [PtCl2(NH3)2], used as an anticancer drug. It works by binding to nitrogen atoms on DNA bases, distorting the DNA double helix and preventing cancer cells from replicating.

  • Why does cisplatin bind to DNA in preference to water molecules?

    Nitrogen atoms on DNA bases are better ligands than water molecules. Nitrogen forms stronger dative covalent bonds to the platinum centre, so cisplatin displaces the water ligands and binds preferentially to the DNA bases.

  • True or False?

    Cisplatin has a square planar geometry with bond angles of 90°.

    True.

    Cisplatin, [PtCl2(NH3)2], is a square planar complex. All bond angles between adjacent ligands in a square planar complex are 90°.

  • Why does cisplatin affect cancer cells more than most healthy cells?

    Cancer cells replicate much faster than normal cells. Because cisplatin works by preventing DNA replication, it has a greater effect on rapidly dividing cells. However, it does also affect healthy cells that replicate quickly, such as hair follicles.

  • Define cis-isomer.

    A cis-isomer is a geometric isomer in which two identical groups are on the same side of a molecule. In cisplatin [PtCl2(NH3)2], the two Cl- ligands and the two NH3 ligands are each on the same side of the square planar complex.

  • Cisplatin works by entering the cell and undergoing .......... exchange, replacing Cl- with water. It then binds to .......... atoms on DNA bases, distorting the helix and preventing DNA from replicating.

    Cisplatin works by entering the cell and undergoing ligand exchange, replacing Cl- with water. It then binds to nitrogen atoms on DNA bases, distorting the helix and preventing DNA from replicating.

  • Why does cisplatin cause hair loss as a side effect?

    Cisplatin binds to DNA in all rapidly dividing cells, not only cancer cells. Hair follicle cells divide quickly, so they are also affected by cisplatin, causing hair loss during treatment.

  • True or False?

    Trans-platin is as effective as cisplatin as an anticancer drug.

    False.

    Only the cis-isomer (cisplatin) is effective as an anticancer drug. Trans-platin, where the Cl- ligands are on opposite sides of the square planar complex, cannot bind to two adjacent nitrogen atoms on the same DNA strand in the same way.

  • What types of cancer can cisplatin be used to treat?

    Cisplatin has been used to treat a range of cancers including testicular, ovarian, cervical, breast, lung and brain cancer. It was discovered in the 1960s and remains an important chemotherapy agent.

  • What is haemoglobin?

    Haemoglobin is a protein complex that transports oxygen in the blood. It contains four haem groups, each with an Fe2+ ion at its centre, which forms dative covalent bonds with oxygen molecules to carry them around the body.

  • Why does oxygen bond weakly to haemoglobin, and why is this important?

    Oxygen is a poor ligand and forms only weak dative covalent bonds to the Fe2+ ion. This is important because the weak bonds break easily, allowing oxygen to be released into cells where it is needed.

  • True or False?

    Carbon monoxide is a better ligand than oxygen and binds irreversibly to the Fe2+ ion in haemoglobin.

    True.

    CO forms stronger dative covalent bonds to Fe2+ than O2 does. This binding is essentially irreversible, preventing oxygen from being transported to cells and making CO highly toxic.

  • In haemoglobin, each .......... group contains an Fe2+ ion at the centre of a square planar complex. Oxygen molecules bond .......... to this ion, allowing them to be transported and released into cells.

    In haemoglobin, each haem group contains an Fe2+ ion at the centre of a square planar complex. Oxygen molecules bond weakly to this ion, allowing them to be transported and released into cells.

  • How does carbon monoxide cause poisoning at the molecular level?

    CO undergoes ligand exchange, binding strongly and irreversibly to the Fe2+ ion in haemoglobin in place of oxygen. This forms carboxyhaemoglobin, preventing the transport of oxygen to cells.

  • What is carboxyhaemoglobin?

    Carboxyhaemoglobin is the complex formed when carbon monoxide replaces oxygen as the ligand bound to the Fe2+ ion in haemoglobin. It is darker red than oxyhaemoglobin and is a sign of carbon monoxide poisoning.

  • What is the coordination environment of the Fe2+ ion in each haem group?

    Each Fe2+ ion forms four dative covalent bonds to nitrogen atoms from the haem group in a square planar arrangement, a fifth dative bond to the protein (globin), and a sixth bond to an oxygen molecule when carrying oxygen.

  • True or False?

    Anaemia can result from a deficiency in iron.

    True.

    Anaemia occurs when a person does not have enough haemoglobin in their blood. A deficiency in iron means insufficient Fe2+ is available to form the haem complexes needed for oxygen transport. This can be treated by taking iron sulfate tablets.

  • What colour change is associated with carbon monoxide poisoning, and why?

    Carbon monoxide poisoning produces a darker red colour in the blood. This is because carboxyhaemoglobin (CO bound to Fe2+) is darker red than oxyhaemoglobin (O2 bound to Fe2+).

  • Define heterogeneous catalyst.

    A heterogeneous catalyst is in a different physical state (phase) from the reactants.

    The reaction occurs at active sites on the surface of the catalyst.

  • Why are transition metals especially useful as catalysts for redox reactions?

    Transition metals can form more than one stable oxidation state, allowing them to accept and lose electrons easily.

    This means they can be oxidised and then reduced (or vice versa) during a catalytic cycle, facilitating redox reactions.

  • True or False?

    In the Haber process, iron acts as a homogeneous catalyst.

    False.

    Iron is a solid catalyst while the reactants N2 (g) and H2 (g) are gases, so iron acts as a heterogeneous catalyst.

  • A heterogeneous catalyst is in a .......... physical state from the reactants, while a homogeneous catalyst is in the .......... physical state as the reactants.

    A heterogeneous catalyst is in a different physical state from the reactants, while a homogeneous catalyst is in the same physical state as the reactants.

  • State the equation for the Haber process and identify the catalyst used.

    N2 (g) + 3H2 (g) ⇌ 2NH3 (g)

    The catalyst is iron (Fe), acting as a heterogeneous catalyst because it is a solid while the reactants are gases.

  • True or False?

    Transition metals can catalyse redox reactions because they have variable oxidation states of similar stability.

    True.

    The ability to adopt multiple stable oxidation states means transition metals can be readily oxidised and reduced within a catalytic cycle, making them effective redox catalysts.

  • Define homogeneous catalyst.

    A homogeneous catalyst is in the same physical state (phase) as the reactants.

    Reactants and catalyst are typically all in aqueous solution or all in the gas phase.

  • What are the two types of catalyst, and how do they differ?

    The two types are heterogeneous and homogeneous catalysts.

    A heterogeneous catalyst is in a different physical state from the reactants; a homogeneous catalyst is in the same physical state as the reactants.

  • Define heterogeneous catalyst.

    A heterogeneous catalyst is in a different physical state (phase) from the reactants.

    The reaction occurs at active sites on the surface of the solid catalyst.

  • What is a catalytic converter and how does it reduce pollution from car exhausts?

    A catalytic converter is a device in a car exhaust system containing finely divided platinum and rhodium on a ceramic support.

    It converts toxic CO and NO into less harmful N2 and CO2 via surface adsorption: 2NO (g) + 2CO (g) → N2 (g) + 2CO2 (g).

  • True or False?

    Adsorption and absorption are the same process.

    False.

    Adsorption occurs only at the surface of a substance; absorption involves a substance becoming distributed throughout another (like water in a sponge).

  • Define active site.

    An active site is the location on the surface of a heterogeneous catalyst where adsorption of reactant molecules occurs.

    Reactants bind here, bonds are weakened, and reaction takes place before products are desorbed.

  • In the Contact Process, V2O5 is reduced to .......... when it converts SO2 to SO3, then re-oxidised back to .......... by reaction with oxygen.

    In the Contact Process, V2O5 is reduced to V2O4 when it converts SO2 to SO3, then re-oxidised back to V2O5 by reaction with oxygen.

    This demonstrates the variable oxidation state of vanadium (+5 → +4 → +5).

  • What is the Contact Process and which heterogeneous catalyst does it use?

    The Contact Process is the industrial manufacture of sulfuric acid.

    The key step converts SO2 (g) to SO3 (g) using vanadium(V) oxide (V2O5) as the heterogeneous catalyst.

  • Define adsorption.

    Adsorption is the process by which reactant molecules become attached to the surface of a heterogeneous catalyst at its active sites.

    This weakens bonds in the adsorbed reactants, making them more reactive.

  • Why must the strength of adsorption be intermediate for an effective heterogeneous catalyst?

    If adsorption is too strong (e.g. tungsten, W), products cannot desorb from the surface.

    If adsorption is too weak (e.g. silver, Ag), reactants do not bind in sufficient concentration to react. Metals such as Ni and Pt have an intermediate strength that is most effective.

  • True or False?

    Increasing the surface area of a heterogeneous catalyst improves its effectiveness.

    True.

    A larger surface area provides more active sites for reactant molecules to adsorb onto, increasing the rate of reaction. This is why catalysts are often finely divided or coated onto a porous support.

  • Define homogeneous catalyst.

    A homogeneous catalyst is in the same physical state (phase) as the reactants.

    A key feature is the formation of an intermediate species for which a specific formula can be written.

  • How do Fe2+ ions act as a homogeneous catalyst in the reaction between I- and S2O82-?

    Fe2+ ions act as a homogeneous catalyst via a two-step redox cycle:

    1. Fe2+ reduces S2O82- to SO42-, forming Fe3+

    2. Fe3+ oxidises I- to I2, regenerating Fe2+

  • Fe2+ is oxidised to .......... in the first step of the catalytic cycle, then reduced back to .......... in the second step, fulfilling its role as a catalyst.

    Fe2+ is oxidised to Fe3+ in the first step of the catalytic cycle, then reduced back to Fe2+ in the second step, fulfilling its role as a catalyst.

  • Why is the uncatalysed reaction between S2O82- and I- slow despite being energetically favourable?

    Both S2O82- and I- are negatively charged, so electrostatic repulsion between the ions reduces the frequency of successful collisions.

    Adding Fe2+ ions provides an alternative pathway that avoids direct collision between the two negative ions.

  • True or False?

    In homogeneous catalysis, the catalyst forms an intermediate species with a specific formula.

    True.

    A key feature of homogeneous catalysis is the formation of an identifiable intermediate species, unlike heterogeneous catalysis where the reaction occurs at surface active sites.

  • What overall reaction does Fe2+ catalyse, and why is this an example of homogeneous catalysis?

    Fe2+ catalyses: S2O82- (aq) + 2I- (aq) → I2 (aq) + 2SO42- (aq)

    It is homogeneous catalysis because the catalyst (Fe2+) and all reactants and products are in the same phase — aqueous solution.

  • True or False?

    A homogeneous catalyst lowers the activation energy by providing an alternative reaction pathway.

    True.

    A homogeneous catalyst provides a reaction pathway of lower activation energy by forming an intermediate species. This is shown on an energy profile as a two-step pathway with lower energy barriers than the uncatalysed route.

  • What experimental observation indicates the formation of iodine in the Fe2+-catalysed reaction between I- and S2O82-?

    Adding starch to the reaction mixture produces a blue-black colour when iodine (I2) is formed.

    This acts as a visual indicator of the product and can be used to monitor the reaction rate.

  • Define autocatalysis.

    Autocatalysis describes a reaction that is speeded up by one of its own products, which acts as a catalyst for the reaction.

    The rate increases over time as more catalyst is produced.

  • What is unusual about the shape of a concentration–time graph for an autocatalytic reaction?

    The gradient becomes steeper as the reaction proceeds, meaning the rate increases over time.

    This is the opposite of a normal reaction where the rate decreases as reactants are consumed, and occurs because more autocatalyst is produced as the reaction progresses.

  • In the reaction between manganate(VII) ions and oxalate ions, the autocatalyst is .......... ions, which are formed as a .......... of the reaction.

    In the reaction between manganate(VII) ions and oxalate ions, the autocatalyst is Mn2+ ions, which are formed as a product of the reaction.

  • How do Mn2+ ions act as an autocatalyst in the reaction between MnO4- and C2O42-?

    Mn2+ ions undergo a redox cycle between two oxidation states:

    1. Mn2+ is oxidised to Mn3+ by MnO4-

    2. Mn3+ is reduced back to Mn2+ by C2O42-

    As more Mn2+ product accumulates, the rate of reaction increases.

  • True or False?

    The autocatalyst in the manganate(VII)/oxalate reaction is present at the start of the reaction.

    False.

    Mn2+ ions are a product of the reaction, so they are not present at the beginning. The rate is initially slow and then increases as Mn2+ accumulates.

  • How can the rate of the manganate(VII)/oxalate autocatalytic reaction be monitored experimentally?

    The reaction can be followed using a colorimeter, which measures how the absorption of light changes as the purple MnO4- ions are consumed.

    The accelerating rate is shown by an increasingly rapid change in colour.

  • True or False?

    Mn2+ ions catalyse the manganate(VII)/oxalate reaction by cycling between oxidation states +2 and +3.

    True.

    Mn2+ (aq) is oxidised to Mn3+ (aq) by MnO4-, then Mn3+ is reduced back to Mn2+ by C2O42-. This redox cycle allows Mn2+ to be regenerated and act as an autocatalyst.

  • What evidence from the reaction between MnO4- and C2O42- shows that Mn2+ is the autocatalyst rather than any other species?

    Mn2+ ions appear as a product in the overall equation for the reaction, and the rate increases as more Mn2+ accumulates.

    Adding Mn2+ ions at the start speeds up the reaction immediately, confirming Mn2+ is the autocatalyst.

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