Vectors (Cambridge (CIE) O Level Maths): Exam Questions

Exam code: 4024

3 hours46 questions
1
2 marks

VW→=(10−24)

Find  |VW→|.

2
6 marks

stack A B with rightwards arrow on top space equals space open parentheses 6
minus 1 close parentheses               stack B C with rightwards arrow on top space equals space open parentheses negative 2
5 close parentheses                stack D C with rightwards arrow on top space equals space open parentheses 2
minus 3 close parentheses

Find

i) AC→,

 

stack A C with rightwards arrow on top space equals space open parentheses
space space space
space space space space space space space close parentheses  [2]

ii) BD→,

 

stack B D with rightwards arrow on top space equals space open parentheses
space space space
space space space space space space space close parentheses  [2]

iii) |BC→|.

  

  [2]

3
4 marks

p=(45)       q=(−27)

i) Find 2p+q.  

(     ) [2]

ii) Find |p|.  

[2]

4
4 marks

a=(−32)       b=(54)       c=(149)

i) Find  3a−2b .

 

 

 (          ) [2]

ii) Find  | a |.

 

 

[2]

5
3 marks
cie-igcse-2018-oct-nov-p4-tz3-q1b

i) Find the column vector AB→.

 

 

AB→=(          ) [1]

ii) Find  |AB→|.

 

 

|AB→|=................................................. [2]

6
5 marks

OA→=(43)      AB→=(8−7)      AC→=(−36)

Find

i) |OB→|,

|OB→|=............................................... [3]

ii) BC→.

BC→=(   ) [2] 

7
2 marks

Find the magnitude of the vector (−17).

1a
4 marks

The diagram shows triangle OPT.

q22-paper4-spec-2025-cie-igcse-further-maths

In the diagram OT→ = t and OP→ = p. OK : KT = 2 :1 and TL : LP = 2 :1.

Find, in terms of t and p, in its simplest form

i)   PL→

[2]

ii)  KL→

[2]

1b
2 marks

KL is extended to the point M.

KM→ = −23t + 43p.

Show that M lies on OP extended.

2
4 marks

P is the point (16, 9) and Q is the point (22, 24).

N is the point on PQ such that PN = 2NQ.
Find the co-ordinates of N.

(.................... , ....................)

3
3 marks
cie-igcse-2020-may-jun-p4-tz2-q2d

In the diagram, O is the origin, OT=2TD and M is the midpoint of TC.
OC→=c and OD→=d.  

Find the position vector of M.
Give your answer in terms of c and d in its simplest form.

4
5 marks

a=(−32)       b=(54)       c=(149)

ma+nb=c  

Write down two simultaneous equations and solve them to find the value of m and the value of n.
Show all your working.  

m = ................................................ 
n = ................................................   

5a
2 marks
q2a-hard-4-13-vectors-edexcel-gcse-maths

OPTR is a trapezium.

OP→=a  PT→=b OR→ = 3b

i) Find OT→ in terms of a and b

[1]

ii) Find PR→ in terms of a and b Give your answer in its simplest form. [1]

5b
2 marks

S is the point on PR such that PS : SR = 1 : 3

Find OS→ in terms of a and b.
Give your answer in its simplest form.

5c
2 marks

What does your answer to part (b) tell you about the position of point S?

6a
5 marks

AB→=(−35)

i) Calculate |AB→|.

|AB→| = ................................................ [2]

ii) AC→=(62) and C is the point (10, -1).

a) Find the coordinates of the point A.

[1]

b) B is the midpoint of AD.  Find the coordinates of the point D. [2]

6b
5 marks
q10b-june-2021-4024-21-cambridge-o-level-maths-d

The diagram shows triangle OPQ.
 OP = p and OQ = q.  
R is the point on OQ such that OR = 2RQ.  
S is the midpoint of PQ.  
Express, as simply as possible, in terms of p and/or q

i) PQ→,

PQ →=...................[1]

ii) OS→

OS→=........................[2]

iii) SR→

SR→=...................[2]

1
6 marks
cie-igcse-2020-oct-nov-p4-tz3-q8b

In the diagram, OAB and OED are straight lines. O is the origin, A is the midpoint of OB and E is the midpoint of AC.
AC→ = a and CB→ = b.  

Find, in terms of a and b, in its simplest form 

i) AB→,

      AB→ = ................................................ [1]

ii) OE→,

      OE→ = ................................................ [2]

iii) the position vector of D.

      [3]

2a
3 marks
cie-igcse-spec-p4-q6a-diagram

OPQR is a rectangle and O is the origin. M is the midpoint of RQ and PT : TQ = 2 : 1. OP→ = p and  OR→ = r.

Find, in terms of p and/or r, in its simplest form

i) MQ→,

MQ→ = ..............................................  [1]

ii) MT→,

MT→ = .............................................. [1]

iii) OT→,

OT→ = .............................................. [1]

2b
2 marks

RQ and  OT are extended and meet at U.

Find the position vector of U in terms of p and r. Give your answer in its simplest form.

3a
5 marks
cie-igcse-2018-oct-nov-p4-tz2-q11b

OAB is a triangle and C is the mid-point of OB.
D is on AB such that AD : DB = 3 : 5.
OAE is a straight line such that OA:AE = 2 : 3. OA→=a and OC→=c.  

Find the following vectors, in terms of a and c, in their simplest form

i) AB→,

 

 

AB→=................................................ [1]

ii) AD→,

 

 

AD→=................................................ [1]

iii) CE→,

 

 

CE→=................................................ [1]

iv) CD→.

 

 

CD→=................................................ [2]

3b
1 mark

CE→=kCD→

Find the value of k.

 

 

k = ................................................

4
4 marks
q2-vhard-4-13-vectors-edexcel-gcse-maths

ABC is a straight line.

AB : BC = 2:5

OA →= 2a+bOB→ =3a +2b

Express  OC → in terms of  a and b.
Give your answer in its simplest form.