Reciprocal & Inverse Trigonometric Functions (OCR A Level Maths A: Pure): Exam Questions

Exam code: H240

3 hours36 questions
1
2 marks

Sketch the graph of y=cosec x, for  −180°≤ x≤180°.

2a
2 marks

Write down the domain and range for the function arccos θ.

2b
2 marks

Hence sketch the graph of y=arccos θ.

3
3 marks

Solve the equation cot x=3, for  −π≤ x≤π, giving your answers to three significant figures.

4
4 marks

Sketch the graph of y=sec θ, for  −π≤θ≤π.

Label any points of intersection with the coordinate axes and state the equations of any asymptotes.

5
4 marks

Starting with the identity

         sin2 x+cos2 x≡1

show that

(i) 1+cot2 x≡cosec2 x

(ii) tan2 x+1≡sec2 x

6
3 marks

Show that

      sec2 θ sin θ≡tan θ sec θ

7a
2 marks

Write down the domain and range for the function arcsin θ.

7b
2 marks

Hence sketch the graph of y=arcsin θ.

8
3 marks

Solve the equation cosec2 x−2 cosec x−8=0  for 0°≤ x≤360°, giving your answers to one decimal place where appropriate.

9
3 marks

Show that

         cot x cosec x sec x≡1+cot2 x

10
4 marks

Solve the equation sec θ tan θ−sec θ=0, for 0≤ x≤2π, giving your answers in exact form.

11a
2 marks

Write down the domain and range for the function arctan θ.

11b
2 marks

Hence sketch the graph of y=arctan θ.

12a
2 marks

Sketch the graph of y=2 sec 2x, for −π≤ x≤π.

12b
2 marks

Draw a suitable line on your graph to show that the equation 2 sec 2x=4  has four solutions in the range  −π≤ x≤π.

1a
2 marks

Use the definitions of the secant, cosecant and cotangent functions to show that

sec θ cot θ≡cosec θ.  

1b
3 marks

Hence solve, in the range 0≤θ≤2π, the equation

sec θ cot θ=−2

2a
2 marks

Show that the equation

3−sec θ=2sec θ

can be rewritten in the form

 (sec θ−2)(sec θ−1)=0

2b
4 marks

Hence solve, in the range 0≤θ≤2π, the equation

3−sec θ=2sec θ

3a
3 marks

Using the double angle formula sin 2A≡2 sin A cos A, show that the equation

sec x cosec x−5=cosec 2x

can be rewritten in the form

coesec 2x=5.

3b
3 marks

Hence solve, in the range 0≤ x≤2π, the equation

sec x cosec x−5=cosec 2x

giving your answers correct to 3 significant figures.

4a
3 marks

Show that the equation

tan2 x=6 sec x−10

can be rewritten in the form

 (sec x−3)2=0

4b
3 marks

Hence solve, in the range 0≤ x≤2π, the equation

tan2 x=6 sec x−10

giving your answers correct to 3 significant figures.

5
5 marks

Given that x satisfies the equation arccos x=k , where   0<k<π2

(i) state the range of possible values of x,

(ii) express both sin k and tan k in terms of x.

 ,

6a
4 marks

Prove that for 0≤ x≤1, arcsin x=arccos1−x2.

6b
2 marks

Explain why this is not true for −1≤ x<0.

7
5 marks

(i) Sketch, in the interval −2π≤θ≤2π, the graph of y=3+2 cosec θ , include asymptotes and label the coordinates of all maximum and minimum points.

(ii) Hence, deduce the number of solutions to the equation 3+2 cosec θ=12 in the interval  −2π≤θ≤2π.

8a
3 marks

The function  f is defined as f(x)=arccos x , −1≤ x≤1, and the function  g  is such that  g(x)=f(3x).

Sketch the graph of y=f(x)  and state the range of  f.

8b
3 marks

Sketch the graph of  y=g(x)  and state the domain of  g.

8c
2 marks

Find the inverse function g−1(x) and state its domain.

1a
2 marks

Rewrite tan θ cosec θ as a single trigonometric function.

1b
3 marks

Hence solve, in the range −π<θ≤π, the equation

tan θ cosec θ=−233

2
6 marks

Solve, in the range 0≤θ≤2π, the equation

2cosec θ−cosec θ=1

3
6 marks

Using the double angle formula sin 2A≡2 sin A cos A,  find the solutions to the equation

sec x cosec x−75=5 cosec 2x

in the range −π< x≤π.   Give your answers correct to 3 significant figures.

4a
3 marks

Show that the equation

2 cot2 x=1−5cosec x

can be rewritten in the form

(2 cosec x−1)(cosec x+3)=0

4b
3 marks

Hence solve, in the range 0≤ x≤2π, the equation

2 cot2 x=1−5cosec x

giving your answers correct to 3 significant figures.

5
5 marks

Given that x satisfies the equation  arcsin x=k, where  −π2<k<0  ,

(i) state the range of possible values of x,

(ii) express both cos k and tan k in terms of x.

6
7 marks

Prove that for −1≤ x≤0,arccos x=π−arcsin1−x2 .

7
5 marks

(i) Sketch, in the interval −2π≤θ≤2π, the graph of  y=−5+12sec θ  , include asymptotes and label the coordinates of all maximum and minimum points.

(ii) Hence deduce the range of values for k for which the equation   −5+12sec θ=k   has no solutions.

8a
3 marks

The function  f  is defined as f(x)=arctan x ,  x∈ℝ  , and the function  g  is such that  g(x)=2πf(x)−1  .

Sketch the graph of y=f(x) and state the range of  f.

8b
3 marks

Sketch the graph of y=g(x)and state the range of  g.

8c
2 marks

Find the inverse function g−1(x) and state its domain.

1
5 marks

Solve, in the range −π<θ≤π, the equation

sec θ cot θcosec θ tan θ=−3

2
6 marks

Solve, in the range 0≤θ≤2π, the equation

6 secθ+23sec θ =−3−43

Leaving your answers as exact values.

3
6 marks

Using the double angle formulae sin2A≡2sinAcosA and cos2A≡cos2A − sin2A,  find the solutions to the equation

(cosec x−sec x)(1sec x+1cosec x)=cot 2x+3

in the range −π< x≤π.   Give your answers correct to 3 significant figures.

4
6 marks

Solve, in the range 0≤ x≤2π, the equation

3 cot2 x−43=(6−23)cosec x−3

Leaving your answers as exact values.

5
5 marks

Given that x satisfies the equation  arctan x=k, where    −π2≤ k≤0

(i) state the range of possible values of x,

(ii) express both sin k and cos k in terms of x.

6
7 marks

Prove that for x≤−1,

arcsin1x=−arccos(−x2−1x)

7a
3 marks

Sketch, in the interval −2π≤θ≤π, the graph of  y=2+3 sec(θ+π2) , include asymptotes and label the coordinates of all maximum and minimum points.

7b
4 marks

Deduce the maximum and minimum values of  12+3 sec (θ+π2).

8a
4 marks

The function  f  is defined as  f : x↦arcsin x,  −1≤ x≤1 , and the function  g  is such that 

g(x)=4f(x3)π+2

Sketch the graph of y=g(x)and state the domain and range of  g.

8b
2 marks

Define the inverse function g−1 in the form  g−1 : x↦… 

8c
3 marks

Over the same domain as  g, the function h is defined as  h : x↦p arccos(qx).

Given that  h(x)=−g(x) for all x in the two functions’ common domain, determine the values of p and q.