Iteration (AQA GCSE Maths: Higher): Exam Questions

Exam code: 8300

1 hour17 questions
1a
3 marks

Using  xn+1 = 2  4xn2

with  x0 = 2.5

find the values of x1x2 and x3

1b
2 marks

Explain the relationship between the values of x1 , x2 and x3 and the equation 
 x3 + 2x2 +4 =0

2
2 marks

A sequence of numbers is formed by the iterative process

un+1=4un1         u1=9

Work out the values of u2 and u3

3a
2 marks

An approximate solution to an equation is found using the iterative formula

xn+1(xn)3  210   with x1 = 1

Work out the values of x2 and x3

x2 = ......................

x3 = ......................

3b
1 mark

Work out the solution to 5 decimal places.

x = ......................

4a
2 marks

An approximate solution to an equation is found using this iterative process.

   xn+1 = (xn)3  38  and x1 = 1

Work out the values of  x2and x3

 x2   = ........................

x3   = .........................

4b
1 mark

Work out the solution to 6 decimal places.

x = .......................

5
3 marks

Use the formula xn+1 = (xn)330+2 with x1 = 2 to calculate x2 and x3.

Round your answers correct to 4 decimal places.

x2 = ............. and x3 = ................

1a
2 marks

Show that the equation x3 + x = 7 has a solution between 1 and 2

1b
1 mark

Show that the equation  x3 + x =7 can be rearranged to give x = 7x3

1c
3 marks

Starting with x0 = 2,
use the iteration formula xn+1 = 7xn3 three times to find an estimate for a solution of  x3 + x = 7

2a
2 marks

Show that the equation x3 + 4x= 1 has a solution between x = 0 and x = 1

2b
1 mark

Show that the equation x3 + 4x= 1 can be arranged to give  x = 14x34

2c
3 marks

Starting with  x0 = 0 , use the iteration formula xn+1 = 14  xn34 twice , to find an estimate for the solution of  x3 + 4x =1

3a
2 marks

Show that the equation 3x2  x3 + 3 = 0 can be rearranged to give 

   x = 3 + 3x2

3b
3 marks

Using 

      xn+1 = 3 + 3xn2 with x0 = 3.2,

find the values of x1 , x2 and x3

3c
1 mark

Explain what the values of x1 , x2 ,  and  x3 represent.

4a
2 marks

A sphere has radius r cm

An approximate value of r can be found using the iterative formula

rn+1=239rn

The starting value is  r1=7

Work out the values of  r2 and r3

r1=.....................r2=.....................

4b
1 mark

Continue the iteration to work out the radius to 1 decimal place.

................................................. cm

5
3 marks

xn+1=3xn+73

Use a starting value of x1 = 2 to work out a solution to x = 3x+73
Give your answer to 3 decimal places.

6
3 marks

Using xn+1=2xn27 with x0=2, find the values of x1, x2 and x3.

Where appropriate, round decimals to 4 decimal places.

1a
2 marks

Show that the equation x3 + 7x  5 = 0 has a solution between x = 0 and x = 1

1b
2 marks

Show that the equation x3 + 7x 5 =0 can be arranged to give x = 5x2 +7

1c
3 marks

Starting with x0 = 1, use the iteration formula xn+1 = 5xn2 + 7 three times to find an estimate for the solution of x3 + 7x  5 = 0

1d
2 marks

By substituting your answer to part (c) into x3 + 7x  5, comment on the accuracy of your estimate for the solution to x3 + 7x 5 = 0

2
3 marks

The number of bees in a beehive at the start of year n is Pn. The number of bees in the beehive at the start of the following year is given by 

Pn+1 = 1.05(Pn  250)

At the start of 2015 there were 9500 bees in the beehive.

How many bees will there be in the beehive at the start of 2018?

3
3 marks

The number of slugs in a garden  t days from now is pt where

   p0 = 100pt+1 =1.06pt

Work out the number of slugs in the garden 3 days from now.

4
3 marks

At the start of year n, the number of animals in a population is Pn
At the start of the following year, the number of animals in the population is Pn+1, where

Pn+1=kPn

At the start of 2017 the number of animals in the population was 4000
At the start of 2019 the number of animals in the population was 3610
Find the value of the constant k.

5a
3 marks

Use the iteration formula  xn+1=102xn3  to find the values of x1, x2 and x3
Start with x0=2

x1= ......     
x2= ......     
x3= .....      

5b
1 mark

The values of x1, x2 and x3 found part (a) are estimates of the solution of an equation of the form x3+ax+b=0 where a and b are integers.

Find the value of a and the value of b.

a= ......     
b= .....      

6a
3 marks

The number of rabbits on a farm at the end of month n is Pn The number of rabbits at the end of the next month is given by Pn+1=1.2 Pn  50

At the end of March there are 200 rabbits on the farm.

Work out how many rabbits there will be on the farm at the end of June.

6b
1 mark

Considering your results in part (a), suggest what will happen to the number of rabbits on the farm after a long time.