Polynomials (Edexcel International AS Maths: Pure 2): Exam Questions

Exam code: XMA01

3 hours29 questions
1
2 marks

Use the factor theorem to verify that (x−2) is a factor of x3−x2−14x+24.

2
4 marks

Divide  x3+6x2+11x+6  by  (x+2).

3
6 marks

Given f(x)=x3−5x2−2x+24 has a root at x=3, fully factorise f(x).

4
4 marks

Use polynomial division to show that (x−2) is a factor of 2x3+3x2−18x+8.

5
4 marks

Given x=−2 is a root of the function f(x)=x3−3x2−8x+4, fully factorise f(x).

6
3 marks

Given that (x−4) is a factor of x3−kx2−4x+16, find the value of k.

7
4 marks

Given that x=12 is a root of the function f(x)=2x3+(p2+1)x2−11x+4, find the possible values of p.

8a
4 marks

Given that (x+1) is a factor of  f(x)=x3−5x2+3x+9, fully factorise f(x).

8b
3 marks

Sketch the graph of y=f(x), labelling the coordinates of all points where the graph intersects the coordinate axes.

 

9
4 marks

Find the remainder when  x3−7x−6  is divided by (x+4).

10
5 marks

The function f(x) is given by f(x)=x4+ax3−13x2−38x−4b, where a and b are constants.

Given that both (x+1)  and (x+2) are factors of f(x), find the values a of b .

1
2 marks

Divide x3−6x2−9x+14  by (x−7).

2a
2 marks

 f(x)=2x3−x2−16x+15

Find the remainder when f(x) is divided by (x−2).

2b
4 marks

Given that (x+3) is a factor of f(x), factorise f(x) completely.

3a
2 marks

 f(x)=2x3−3x2−72x−35 

Show that f(x)=(2x+1)(ax2+bx+c),  where a, band c are constants to be found.

3b
4 marks

Hence factorise f(x) completely.

3c
2 marks

Write down all the real roots of the equation f(x)=0. 

4a
2 marks

f(x)=4x3+4x2−23x−30 

Use the factor theorem to show that (x+2) is a factor of f(x).

4b
4 marks

Factorise f(x) completely.

4c
2 marks

Write down all the real roots of the equation f(x)=0.

5a
6 marks

f(x)=x3+9x2+rx+s. Given that f(2)=0 and f(−1)=−54 :

find the values of  r and  s.

5b
3 marks

Factorise f(x) completely.

6
5 marks

Consider the function f(x)=4x3+6x2−7x+2.

(i) Find the quotient and remainder when 4x3+6x2−7x+2 is divided by (x−2). 

(ii) Hence write  4x3+6x2−7x+2 in the form (x−2)(ax2+bx+c)+d, where a, b, c and d are constants to be determined.

7a
5 marks

The function f(x)=2x3−5x2+ax+b  has (2x+3) as a factor, and when f(x) is divided by (x−2) the remainder is 7. 

Show that a and b must satisfy the simultaneous equations:             2a+b=11

         3a−2b=−36

7b
2 marks

Hence find a and b.

1
2 marks

Divide x3−19x−30 by (x−5).

2a
2 marks

f(x)=x3−28x+48

Find the remainder when f(x) is divided by (x−3).

2b
4 marks

Given that (x+6) is a factor of f(x), factorise f(x) completely.

3a
2 marks

f(x)=6x3−19x2+11x+6

Show that f(x)=(2x−3)(ax2+bx+c) where a, b and c are constants to be found. 

3b
4 marks

Hence factorise f(x) completely.

3c
2 marks

Write down all the real roots of the equation f(x)=0.

4a
2 marks

f(x)=4x3−7x−3

Use the factor theorem to show that (2x+1) is a factor of f(x).

4b
4 marks

Factorise f(x) completely.

4c
2 marks

Write down all the real roots of the equation f(x)=0.

5a
6 marks

f(x)=x3+rx2+sx−30. Given that f(2)=0  and f(−3)=−240 :

 find the values of r and s.

5b
3 marks

Factorise f(x) completely.

6
6 marks

Given that (x+4) is a factor of the function f(x)=px3+(5p+1)x2+5qx−2q−2 and that the remainder when f(x)  is divided by (x+1) is −12,  find the values of the constants p and q.

7
4 marks

Show that 3x3+16x2−22x can be written in the form (3x+1)(ax2+bx+c)+d, where a, b, c and d are constants to be found.

1
3 marks

Divide 4x4−37x2+9 by (2x−1).

2a
2 marks

f(x)=6x4+7x3−27x2−28x+12

Find the remainder when f(x) is divided by (2x+3).

2b
5 marks

Given that (x+2) is a factor of f(x), factorise f(x) completely. 

3a
2 marks

f(x)=3x4+x3−12x2−49x−15

Show that f(x)=(3x+1)(ax3+bx2+cx+d) where a, b, c and d are constants to be found.

3b
5 marks

Given that (x−3) is a factor of f(x), factorise f(x) completely.

3c
2 marks

Hence show that the equation f(x)=0 has exactly 2 real roots.

4
4 marks

 Given that 3 is a root of the equation 2x3−x2−11x−12=0, prove that the equation has no other real roots.

5a
1 mark

f(x)=2x4−15x3−10x2+105x+98

Show that f(−1)=0 and f(−2)=0.

5b
7 marks

Hence, solve f(x)=0.