Functions (SQA National 5 Maths): Flashcards

Exam code: X847 75

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  • Define a function.

Cards in this collection (8)

  • Define a function.

    A function is a rule made of one or more operations that turns a set of numbers into another set of numbers.

    The numbers put in are the inputs and the numbers coming out are the outputs.

  • In \text{f} \left(x\right) = 2 x + 1 what is the input and what is the output?

    x is the input and \text{f} \left(x\right) is the output, so the notation names the rule and the number going into it at the same time.

    Letters other than \text{f} can be used, with \text{g}, \text{h} and \text{j} all common.

  • How is \text{f} \left(6\right) evaluated when \text{f} \left(x\right) = 4 x + 5 is given?

    Substitute 6 into the expression everywhere an x appears, giving \text{f} \left(6\right) = 4 \left(6\right) + 5.

    Working that out gives \text{f} \left(6\right) = 29.

  • Complete the working for the function \text{f} \left(x\right) = 2 x + 1 by filling in the two missing values.

    \text{f} \left(- 4\right) = 2 \times \left(\_\_\_\_\_\_\right) + 1 = \_\_\_\_\_\_

    The completed working is:

    \text{f} \left(- 4\right) = 2 \times \left(- 4\right) + 1 = - 7

    Keeping the - 4 inside brackets while multiplying is what stops the sign being lost.

  • True or False?

    \text{f} \left(t + 5\right) means \text{f} multiplied by t + 5.

    False.

    The brackets in function notation show the input, so \text{f} \left(t + 5\right) is the output when t + 5 is put into the function.

    Nothing is being multiplied, so it does not equal \text{f} t + 5 \text{f}.

  • In what way do \text{f} \left(x\right) = 15 and \text{f} \left(15\right) mean different things?

    \text{f} \left(x\right) = 15 says the output is 15, so an equation has to be solved to find the input.

    \text{f} \left(15\right) says the input is 15, so you substitute and work out the output.

  • True or False?

    Putting a letter rather than a number into a function gives an answer that still contains that letter.

    True.

    A function carries out the same operations whatever goes in, so \text{f} \left(x\right) = 2 x + 1 gives \text{f} \left(a\right) = 2 a + 1.

    The answer stays in terms of a because there is no number to work out.

  • If the output of a function is known how do you find the input?

    Replace \text{f} \left(x\right) with the rule of the function, set that equal to the known output, and solve the resulting equation.

    For \text{f} \left(x\right) = 2 x + 1 with an output of 15 the equation is 2 x + 1 = 15, giving an input of x = 7.

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