Trends of Period 3 Elements: First Ionisation Energy (AQA A Level Chemistry): Revision Note
Exam code: 7405
Trend: First Ionisation Energy
The first ionisation energy (IE) is the energy required to remove one mole of electrons from one mole of atoms of an element in the gaseous state to form one mole of gaseous ions
For example, the first ionisation energy of sodium is:
Na (g) → Na+ (g) + e-
First ionisation energies of the Period 3 elements
Period 3 Element | First IE/ kJ mol-1 |
|---|---|
Na | 494 |
Mg | 736 |
Al | 577 |
Si | 786 |
P | 1060 |
S | 1000 |
Cl | 1260 |
Ar | 1520 |
There is a general increase in first ionisation energy across a period
Across a period, the effective nuclear charge increases because the number of protons increases, while shielding remains approximately constant
As a result, the atomic radius decreases
The stronger attraction between the positively charged nucleus and the outer electron makes it more difficult to remove the electron, so the first ionisation energy increases
However, small decreases (or “dips”) are observed between magnesium and aluminium, and between phosphorus and sulfur
The dip between Mg and Al occurs because
Al is [Ar]3s23p1 and Mg is [Ar]3s2
The outer electron removed from aluminium is in a higher-energy 3p subshell, which is slightly easier to remove than a 3s electron
The dip between P and S occurs because:
S is [Ar]3s23p4, and P is [Ar]3s23p3
Sulfur has a pair of electrons in one 3p orbital, and electron–electron repulsion makes it easier to remove one of the paired electrons compared with phosphorus, where the 3p electrons are unpaired
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