Gibbs Free Energy (AQA A Level Chemistry): Revision Note

Exam code: 7405

Stewart Hird

Written by: Stewart Hird

Reviewed by: Caroline Carroll

Updated on

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Gibbs Free Energy

  • The thermodynamic feasibility of a reaction depends on two factors: the enthalpy change (ΔH) and the entropy change (ΔS)

  • These factors are combined in the Gibbs free energy change, ΔG, which determines whether a reaction is thermodynamically feasible under standard conditions

  • The Gibbs equation is:

ΔGꝋ = ΔHreactionꝋ - TΔSsystemꝋ

Where:

ΔGꝋ is the standard Gibbs free energy change (kJ mol⁻¹)

ΔHreactionꝋ is the standard enthalpy change (kJ mol⁻¹)

T is the temperature in kelvin (K)

ΔSsystemꝋ is the standard entropy change (J K⁻¹ mol⁻¹)

  • Because ΔH° is given in kJ mol⁻¹ and ΔS° is usually given in J K⁻¹ mol⁻¹, the entropy value must be converted to kJ K⁻¹ mol⁻¹ (by dividing by 1000) before substituting into the equation

Calculating ΔGꝋ

  • There are two ways you can calculate the value of ΔGꝋ

    • From ΔHꝋ and ΔSꝋ values

    • From the ΔGꝋ  values of all the substances present

Worked Example

Calculate the free energy change for the following reaction:

2NaHCO3 (s) → Na2CO3 (s) + H2O (l) + CO2 (g)

ΔHꝋ = +135 kJ mol-1        ΔSꝋ = +344 J K-1 mol-1

Answer

Step 1: Convert the entropy value in kilojoules

ΔSꝋ = +344 J K-1 mol-1  ÷ 1000 = +0.344 kJ K-1 mol-1 

Step 2: Substitute the terms into the Gibbs Equation

ΔGꝋ = ΔHreactionꝋ - TΔSsystemꝋ

= +135 - (298 x 0.344)

= +32.49 kJ mol-1 

The temperature is 298 K since standard values are quoted in the question

Worked Example

What is the standard free energy change, ΔGꝋ, for the following reaction?

C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)

Substance

ΔGꝋ in kJ mol⁻¹

C2H5OH (l)

-175

O2 (g)

0

CO2 (g)

-394

H2O (g)

-229

Answer

ΔGꝋ = ΣΔGproductsꝋ - ΣΔGreactantsꝋ

ΔGꝋ = [(2 x CO2 ) + (3 x H2O )] - [(C2H5OH) + (3 x O2)]

ΔGꝋ = [(2 x -394 ) + (3 x -229 )] - [-175 + 0]

ΔGꝋ = -1300 kJ mol-1 

Examiner Tips and Tricks

The idea of free energy is what's left over to do useful work when you've carried out the reaction. The enthalpy change is the difference between the energy you put in to break the chemical bonds and the energy out when making new bonds; the entropy change is the 'cost' of carrying out the reaction, so free energy is what you are left with!

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.