Shapes of Simple Molecules & Ions (AQA A Level Chemistry): Revision Note
Exam code: 7405
Electron Pairs
The valence shell electron pair repulsion theory (VSEPR) predicts the shape and bond angles of molecules
Electrons are negatively charged and will repel other electrons when close to each other
In a molecule, the bonding pairs of electrons will repel other electrons around the central atom, forcing the molecule to adopt a shape in which these repulsive forces are minimised
When determining the shape and bond angles of a molecule, the following VSEPR rules should be considered:
Valence shell electrons are the electrons in the outer shell of the central atom
Electron pairs repel each other because they are negatively charged
The molecule adopts the shape that minimises these repulsions
Lone pairs repel more strongly than bonding pairs because their electron clouds are more concentrated and lie closer to the nucleus
Multiple bonds count as a single region of electron density, but repulsion between two multiple bonds is greater than between two single bonds
The order of repulsion is:
lone pair–lone pair > lone pair–bond pair > bond pair–bond pair

Shapes of Molecules & Ions
Molecules can adopt the following shapes and bond angles:

Examples




Summary of the VSEPR theory
Electron pairs | Bonding pairs | Lone pairs | Molecular geometry | Bond angles |
|---|---|---|---|---|
2 | 2 | 0 | Linear | 180° |
3 | 3 | 0 | Trigonal planar | 120° |
3 | 2 | 1 | Bent | <120° |
4 | 4 | 0 | Tetrahedral | 109.5° |
4 | 3 | 1 | Trigonal pyramidal | 107° |
4 | 2 | 2 | Bent | 104.5° |
5 | 5 | 0 | Trigonal bipyramidal | 120° (equatorial) 90° (axial) |
5 | 4 | 1 | Seesaw | <120° (equatorial) <90° (axial) |
5 | 3 | 2 | T-shaped | <90° |
5 | 2 | 3 | Linear | 180° |
6 | 6 | 0 | Octahedral | 90° |
6 | 5 | 1 | Square pyramidal | <90° |
6 | 4 | 2 | Square planar | 90° |
Worked Example
VSEPR & shapes of molecules
Draw the shape of the following molecules:
Phosphorus(V) chloride
N(CH3)3
CCl4
Answer 1:
Phosphorus is in group 15, so has 5 valence electrons; Cl is in group 17, so has 7 valence electrons
All 5 electrons are used to form covalent bonds with Cl, and there are no lone pairs
This gives a trigonal bipyramidal shape:

Phosphorus pentachloride or phosphorus (V) chloride
Answer 2:
Nitrogen is in group 15, so has 5 valence electrons; carbon is in group 14, so has 4 valence electrons, 3 of which are already used in the covalent bonds with hydrogen
Three of the valence electrons in N are used to form bonding pairs, so there is one lone pair left
N(CH3)3 has a trigonal pyramid shape:

Trimethylamine
Answer 3:
Carbon is in group 14, so has 4 valence electrons; chlorine is in group 17, so has 7 valence electrons
All four valence electrons are used to bond with chlorine, and there are no lone pairs
The shape of CCl4 is tetrahedral

Tetrachloromethane
Related topics
Examiner Tips and Tricks
To explain reduced bond angles: start from the parent geometry (109.5° tetrahedral) and deduct ~2.5° per lone pair (NH3 107°, H2O 104.5°). Examiners report that students wrongly start from 180°.
Always name VSEPR and state the repulsion order — lone pair–lone pair > lone pair–bond pair > bond pair–bond pair — to explain why an angle is reduced; if there are no lone pairs (e.g., SF₆, CCl₄), state that all bonding pairs repel equally. A common lost mark is not mentioning VSEPR at all.
Drawing 3D shapes: use at least one wedge (coming out) and one dash (going in), show the lone pair(s) on the central atom, and don't draw bonds at 180° when the true angle is smaller.
Unlock more, it's free!
Was this revision note helpful?
Build on this topic