Rate Determining Step (AQA A Level Chemistry): Revision Note

Exam code: 7405

Stewart Hird

Written by: Stewart Hird

Reviewed by: Caroline Carroll

Updated on

Rate Determining Step

Rate-determining step and intermediates

  • A chemical reaction can only go as fast as the slowest part of the reaction

    • So, the rate-determining step is the slowest step in the reaction

  • If a reactant appears in the rate-determining step, then the concentration of that reactant will also appear in the rate equation

  • For example, the rate equation for the reaction below is rate = k [CH3Br] [OH-]

    CH3Br + OH- → CH3OH + Br-

    • This suggests that both CH3Br and OH- take part in the slow rate-determining step

  • This reaction is bimolecular

    • Unimolecular: one species involved in the rate-determining step

    • Bimolecular: two species involved in the rate-determining step

  • The intermediate is derived from substances that react together to form it in the rate-determining step

    • For example, for the reaction above, the intermediate would consist of CH3Br and OH-

Diagram showing the intermediate formed from CH₃Br and OH⁻ during nucleophilic substitution, with partial bonds to both the hydroxide and bromide.
The intermediate is formed from the species that are involved in the rate-determining step (and thus appear in the rate equation)

Examiner Tips and Tricks

The most common way students lose marks: they define the rate-determining step as the "slowest step" but don't use the rate equation to justify which step is rate-determining.

Don't just state the RDS is the 'slowest step' — examiners expect you to show that the number of moles of each reactant consumed up to and including the RDS matches the orders in the rate equation.

Predicting the reaction mechanism

  • The overall reaction equation and rate equation can be used to predict a possible reaction mechanism of a reaction

    • This shows the individual reaction steps that are taking place

  • For example, nitrogen dioxide (NO2) and carbon monoxide (CO) react to form nitrogen monoxide (NO) and carbon dioxide (CO2)

    • The overall reaction equation is:

NO2 (g) + CO (g) → NO (g) + CO2 (g)

  • The rate equation is:

Rate = k [NO2]2

  • From the rate equation, it can be concluded that the reaction is zero order with respect to CO (g) and second order with respect to NO2 (g)

  • This means that there are two molecules of NO2 (g) involved in the rate-determining step and zero molecules of CO (g)

  • A possible reaction mechanism could therefore be:

Step 1:

 2NO2 (g) → NO (g) + NO3 (g)                   slow (rate-determining step)

Step 2:

   NO3 (g) + CO (g) → NO2 (g) + CO2 (g)     fast

Overall:

    2NO2 (g) + NO3 (g) + CO (g) → NO (g) + NO3 (g) + NO2 (g) + CO2 (g)

    =     NO2 (g) + CO (g) → NO (g) + CO2 (g)

Predicting the reaction order and deducing the rate equation

  • The order of a reactant and thus the rate equation can be deduced from a reaction mechanism if the rate-determining step is known

  • For example, the reaction of nitrogen oxide (NO) with hydrogen (H2) to form nitrogen (N2) and water

2NO (g) + 2H2 (g) → N2 (g) + 2H2O (l)

  • The reaction mechanism for this reaction is:

Step 1:

   NO (g) + NO (g) → N2O2 (g)                      fast

Step 2:

   N2O2 (g) + H2 (g) → H2O (l) + N2O (g)     slow (rate-determining step)

Step 3:

   N2O (g) + H2 (g) → N2 (g) + H2O (l)           fast

  • The second step in this reaction mechanism is the rate-determining step

  • The rate-determining step consists of:

    • N2O2, which is formed from the reaction of two NO molecules

    • One H2 molecule

  • The reaction is, therefore, second order with respect to NO and first order with respect to H2

  • So, the rate equation becomes:

Rate = k [NO]2 [H2]

  • The reaction is, therefore, third-order overall

Examiner Tips and Tricks

Remember: reaction orders must be deduced from experimental rate data, not from the coefficients in the balanced overall equation.

Identifying the rate-determining step

  • The rate-determining step can be identified from a rate equation, given that the reaction mechanism is known

  • For example, propane (CH3CH2CH3) undergoes bromination in alkaline solutions

  • The overall reaction is:

CH3CH2CH3 + Br2 + OH- → CH3CH2CH2Br + H2O + Br-

  • The reaction mechanism is:

Two-step reaction mechanism for the bromination of propane under alkaline conditions, showing the rate-determining first step.
Reaction mechanism for the bromination of propane under alkaline conditions
  • The rate equation is:

Rate = k [CH3CH2CH3] [OH-]

  • From the rate equation, it can be deduced that only CH3CH2CH3 and OH- are involved in the rate-determining step and not bromine (Br2)

  • CH3CH2CH3 and OH- are only involved in the first step of the reaction mechanism; therefore, the rate-determining step is:

    • CH3CH2CH3 + OH-  CH3CH2CH2- + H2O

Identifying intermediates and catalysts

  • When a rate equation includes a species that is not part of the chemical reaction equation, then this species is a catalyst

  • For example, the halogenation of butanone under acidic conditions

  • The reaction equation is:

Chemical equation showing propanone reacting with iodine under acidic conditions to form an iodinated ketone, CH₃CH₂COCH₂I, and hydrogen iodide.
Overall equation for the halogenation of butanone under acidic conditions
  • The reaction mechanism is:

Four-step reaction mechanism for the halogenation of butanone under acidic conditions, showing H⁺ as a catalyst in the rate-determining step.
Reaction mechanism of the halogenation of butanone under acidic conditions
  • The rate equation is:

Rate = k [CH3CH2COCH3] [H+]

  • The H+ is not a reactant in the chemical reaction equation, but does appear in the rate equation

    • H+ must, therefore, be a catalyst

  • Furthermore, the rate equation suggests that CH3CH2COCH3 and H+ must be involved in the rate-determining (slowest) step

  • The CH3CH2COCH3 and H+ appear in the rate-determining step in the form of an intermediate (which is a combination of the two species)

Structure of the intermediate formed from CH₃CH₂COCH₃ and H⁺ in the rate-determining step of butanone halogenation.
Intermediate is formed in the rate-determining step from the reaction of CH3CH2COCH3 and H+

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.