Nucleophilic Substitution (AQA A Level Chemistry): Revision Note

Exam code: 7405

Stewart Hird

Written by: Stewart Hird

Reviewed by: Caroline Carroll

Updated on

Mechanism: Nucleophilic Substitution

  • nucleophile is an electron-rich species that can donate a pair of electrons

    • ‘Nucleophile’ means ‘nucleus/positive charge loving’ as nucleophiles are attracted to positively charged species

    • Nucleophilic refers to reactions that involve a nucleophile

  • Various species can behave as nucleophiles, and some make better nucleophiles than others

Diagram comparing water molecule with δ− on oxygen and δ+ on hydrogens to hydroxide ion showing oxygen bearing a full formal negative charge.
A hydroxide ion is a better nucleophile as it has a full formal negative charge whereas the oxygen atom in water only carries a partial negative charge
  • nucleophilic substitution reaction is one in which a nucleophile attacks a carbon atom that carries a partial positive charge

  • An atom that has a partial negative charge is replaced by the nucleophile

  • Halogenoalkanes will undergo nucleophilic substitution reactions due to the polar C-X bond (where X is a halogen)

Diagram showing a polar C–X bond: carbon has lower electronegativity and partial positive charge, halogen higher electronegativity and partial negative charge
Due to large differences in electronegativity between the carbon and halogen atom, the C-X bond is polar
Mechanism diagram of nucleophilic substitution: Nu⁻ attacks the δ⁺ carbon of a haloalkane, displacing halide X⁻ to form a substituted alkane and X⁻ ion
General Mechanism for Nucleophilic Substitution
  • Halogenoalkanes undergo substitution reactions with the nucleophiles OH, CN, and NH3

Mechanism with OH-

  • For example, in the following reaction, a halogenoalkane reacts with aqueous alkali to form an alcohol

Chemical equation showing bromoethane reacting with hydroxide ion to form ethanol and bromide ion, labelled with the names bromoethane and ethanol
The halogen is replaced by a nucleophile, OH–
  • The mechanism for the reaction is as follows

Mechanism showing nucleophilic substitution of bromoethane by hydroxide ion to form ethanol and bromide, with δ+ carbon and δ− bromine indicated.
Nucleophilic substitution reaction of bromoethane and aqueous alkali (e.g. NaOH)

Mechanism with CN-

  • The nucleophile in this reaction is the cyanide, CN- ion

  • Ethanolic solution of potassium cyanide (KCN in ethanol) is heated under reflux with the halogenoalkane

  • The product is a nitrile

    • For example, bromoethane reacts with ethanolic potassium cyanide when heated under reflux to form propanenitrile

    • The halogen is replaced by a nucleophile, :CN 

CH3CH2Br + :CN → CH3CH2CN + :Br

  • The nucleophilic substitution of halogenoalkanes with KCN adds an extra carbon atom to the carbon chain

  • This reaction can therefore be used by chemists to make a compound with one more carbon atom than the best available organic starting material

Reaction scheme showing bromoethane with KCN in ethanol and heat forming propanenitrile and KBr, highlighting formation of a new carbon–carbon bond.
Bromoethane reacts with ethanolic potassium cyanide when heated under reflux to form propanenitrile
  • The mechanism for the reaction is as follows

Mechanism diagram showing cyanide ion attacking bromoethane, displacing bromide and forming propanenitrile in a nucleophilic substitution reaction
Nucleophilic substitution reaction of bromoethane and aqueous cyanide ions

Mechanism with NH3

  • When ammonia reacts with a haloalkane, a nucleophilic substitution reaction takes place, forming a primary amine

    • For example, chloromethane reacts with ammonia in two steps to make methylamine and ammonium chloride

CH3Cl + NH3 → [CH3NH3]+Cl-

[CH3NH3]+Cl- + NH3 → CH3NH2 + NH4+Cl-

  • Excess ammonia is used to prevent further substitution and favour the formation of a primary amine 

Mechanism of haloalkane with ammonia: lone pair attack, carbon–halogen bond breaks, then proton transfer to give primary amine, ammonium ion and halide ion
The mechanism of nucleophilic substitution between ammonia and a halogenoalkane

Related topics

Examiner Tips and Tricks

Make sure your arrows are clearly curly - if they are not curly enough, then you will not be awarded the mark. Your first arrow must start at the lone pair of the nucleophile and go clearly to the delta positive carbon atom. Your second arrow must start touching the C-X bond and move clearly to the delta negative X atom.

Make sure you show the products formed, including the :X- atom which has been substituted.

Arrows must be double-headed (half-headed "fishhook" arrows are only for free-radical substitution and are penalised here).

The nucleophile must be drawn as the free ion (:OH⁻, :CN⁻), since mark schemes penalise a covalent "NaOH / KOH / KCN" drawn with a bond to the metal.

The carbon should carry a partial charge (δ+), not a full positive charge (a full + is only accepted in an SN1 carbocation route).

Arrows must never start at an atom — always from a lone pair or a bond.

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.