Thermodynamic Terms (AQA A Level Chemistry): Revision Note
Exam code: 7405
Defining Thermodynamic Terms
Thermodynamics is the branch of physical chemistry concerned with heat energy, temperature, and energy changes in chemical and physical processes
Energy cycles, such as Born–Haber cycles, are diagrams used to represent enthalpy changes for ionic compounds using Hess’s Law
To understand these cycles, you must know the definitions of several key enthalpy changes
The enthalpy change (ΔH) is the heat energy transferred during a reaction at constant pressure
Key enthalpy definitions include:
Enthalpy of formation
Ionisation energy
Enthalpy of atomisation
Bond enthalpy
Electron affinity
Enthalpy of formation
The standard enthalpy of formation (Δf Hꝋ) is the enthalpy change when one mole of a compound is formed from its elements in their standard states under standard conditions
In this specification, standard conditions are 298 K and a pressure of 100 kPa
The value of Δf Hꝋ can be positive (endothermic) or negative (exothermic), depending on the balance between bond breaking and bond formation during the reaction
An equation must show the formation of exactly one mole of the compound from its elements in their standard states
For example, the standard enthalpy of formation of sodium chloride is:
Na(s) + ½Cl2 (g) → NaCl (s) Δf Hꝋ = -411 kJ mol -1
The enthalpy of formation applies only to compounds
By definition, the standard enthalpy of formation of an element in its standard state is zero
Ionisation energy
The ionisation energy of an element is the amount of energy required to remove an electron from a gaseous atom of an element to form a gaseous ion under standard conditions
Ionisation enthalpy is always endothermic, as energy is needed to overcome the attraction between an electron and the nucleus
The first ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms of an element to form one mole of gaseous 1+ ions
E.g., the first ionisation energy of gaseous sodium:
Na (g) → Na+ (g) + e– ΔH ꝋ = +500 kJ mol-1
Enthalpy of atomisation
The standard enthalpy of atomisation is the enthalpy change when one mole of gaseous atoms is formed from an element in its standard state under standard conditions
Atomisation is always endothermic because energy is required to break the bonds holding the atoms together in the element
Therefore, ΔH ꝋ always has a positive value
An equation for atomisation must show the formation of one mole of gaseous atoms
For example, sodium is a solid in its standard state. Its standard enthalpy of atomisation is:
Na (s) → Na (g) ΔH ꝋ = +108 kJ mol -1
This represents the energy required to form one mole of gaseous sodium atoms from solid sodium
Worked Example
Writing equations for the standard enthalpy of atomisation
Write down the equations for the standard enthalpy of atomisation (ΔHꝋ) for:
(i) Potassium
(ii) Mercury
Answer
Answer 1: Potassium in its elemental form is a solid, therefore the standard enthalpy of atomisation is the energy required to form 1 mole of K(g) from K(s)
K(s) → K(g)
Answer 2: Mercury in its elemental form is a liquid, so the standard enthalpy change of atomisation of mercury is the energy required to form 1 mole of Hg(g) from Hg(l)
Hg(l) → Hg(g)
Bond enthalpy
Bond enthalpy (also called bond dissociation enthalpy) is the energy required to break one mole of a specific covalent bond in the gaseous state
It is usually represented as E(bond), for example:
E(H–H) is the bond enthalpy of one mole of H–H bonds
Bond enthalpy values are always quoted as positive because breaking bonds is an endothermic process
When considering bond formation, the same value is used but with a negative sign, since bond formation is exothermic
For example, chlorine exists as Cl2 (g).
The bond enthalpy of chlorine is:
Cl2 (g) → 2Cl (g) E(Cl-Cl) = +242 kJ mol -1
This looks similar to the atomisation enthalpy of chlorine, but there is an important difference
Bond enthalpy refers to breaking one mole of bonds
Atomisation enthalpy refers to the formation of one mole of gaseous atoms
Therefore, the atomisation enthalpy of chlorine is half the bond enthalpy:
½Cl2 (g) → Cl (g) ΔH ꝋ = +121 kJ mol -1
If an element is a liquid in its standard state, its atomisation enthalpy would also include the enthalpy of vaporisation before bond breaking occurs
Enthalpy of Lattice Formation and Dissociation
Lattice enthalpy can be defined either as lattice formation enthalpy or lattice dissociation enthalpy
Because strong electrostatic attractions form between oppositely charged ions in the solid lattice, a large amount of energy is released
Therefore, the enthalpy of lattice formation is exothermic and has a large negative value
The large negative value indicates that the ionic lattice is much more stable than the separated gaseous ions
In the gas phase, the ions are far apart, and there are no strong electrostatic attractions between them
The more exothermic the lattice enthalpy, the stronger the ionic bonding in the lattice
Lattice enthalpy cannot be measured directly in a single experiment
Instead, it is determined indirectly using a Born–Haber cycle and other experimentally measured enthalpy changes
For example, for sodium chloride:
Na+(g) + Cl-(g) →NaCl (s) ΔHꝋ = -776 kJ mol -1
This equation represents the enthalpy change when one mole of solid sodium chloride is formed from its gaseous ions
Worked Example
Writing equations for lattice energy
Write down the equations that represent the enthalpy of lattice formation for:
(i) magnesium oxide
(ii) lithium chloride
Answer
Answer 1: Mg2+ (g) + O2- (g) → MgO (s)
Answer 2: Li+ (g) + Cl- (g) → LiCl (s)
Electron Affinity
The electron affinity of an element is the enthalpy change when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous negative ions under standard conditions
For example, the first electron affinity of chlorine is:
Cl (g)+ e– → Cl- (g) ΔH ꝋ = -364 kJ mol-1
The first electron affinity is usually exothermic because energy is released when an electron is attracted to the positively charged nucleus of a gaseous atom
However, the second electron affinity is always endothermic
For example, for oxygen:
O– (g) + e– → O2- (g) ΔH ꝋ = +844 kJ mol-1
This is because energy must be supplied to overcome the electrostatic repulsion between the negatively charged ion and the incoming electron
Examiner Tips and Tricks
Make sure the correct state symbols are stated when writing these equations – you must use these correctly throughout this entire topic.
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