Enthalpy of Solution & Hydration (AQA A Level Chemistry): Revision Note

Exam code: 7405

Stewart Hird

Written by: Stewart Hird

Reviewed by: Philippa Platt

Updated on

Solution & Hydration

Enthalpy of solution

  • The standard enthalpy change of solution (increment H subscript s o l end subscript to the power of theta) is the enthalpy change that occurs when one mole of an ionic substance dissolves in sufficient water to form an infinitely dilute solution

  • The symbol (aq) is used to show that the substance is dissolved in a large excess of water

  • For example, the enthalpy change of solution for potassium chloride can be represented by either of the following equations:

KCl(s) + aq → KCl(aq)

OR

KCl(s) + aq → K+(aq) + Cl-(aq)

  • The standard enthalpy change of solution can be exothermic (negative) or endothermic (positive)

Enthalpy of hydration

  • The standard enthalpy change of hydration (increment H subscript h y d end subscript to the power of theta) is the enthalpy change when one mole of a specified gaseous ion dissolves in sufficient water to form an infinitely dilute solution

    • For example, the enthalpy change of hydration for magnesium ions is represented by the equation:

Mg2+(g) + aq → Mg2+(aq)

  • Hydration enthalpies measure the energy released when attractions form between ions and water molecules

    • These enthalpy changes are always exothermic

  • When an ionic solid dissolves in water, positive and negative ions are formed

  • Water is a polar molecule, with a δ⁻ oxygen atom and δ⁺ hydrogen atoms, which form ion–dipole attractions with the ions in solution.

  • The oxygen atoms are attracted to positive ions, while the hydrogen atoms are attracted to negative ions

Diagram illustrating how water molecules form ion-dipole bonds with K⁺ and Cl⁻ ions, leading to weakened electrostatic attraction and ion hydration.
The polar water molecules will form ion-dipole bonds
Diagram of energy changes in ionic dissolution, showing ionic lattice, gaseous ions, water molecules forming hydrated ions, and solution enthalpy.
The relationship between lattice enthalpy, hydration enthalpies and enthalpy of solution
  • From the diagram, we can see that the relationship is

Enthalpy of solution = reverse lattice enthalpy* + hydration enthalpy

  • The hydration enthalpy is the sum of the hydration enthalpies of each ion

  • If there is more than one cation or anion, such as in MgCl2, then you must multiply by the appropriate coefficient for that ion

Examiner Tips and Tricks

* This exam board uses the term 'lattice energy' for formation and dissolution in equal measure, so the term reverse lattice enthalpy here means the reverse of lattice formation enthalpy. It could also be termed lattice dissociation enthalpy here.

Calculating Enthalpy Changes

  • Questions on this topic often require you to calculate the hydration enthalpy of one ion, given the lattice enthalpy, the enthalpy of solution, and the hydration enthalpy of the other ion

  • This can be done by constructing an appropriate energy cycle and applying Hess’s Law to determine the unknown enthalpy change

  • The energy cycle above shows that there are two possible routes from gaseous ions to ions in aqueous solution

    • Route 1 (indirect route): gaseous ions → ionic solid → ions in aqueous solution

    • Route 2 (direct route): gaseous ions → ions in aqueous solution

  • According to Hess’s Law, the total enthalpy change for both routes is the same, so:

increment H subscript h y d end subscript to the power of theta = increment H subscript l a t t end subscript to the power of theta + increment H subscript s o l end subscript to the power of theta

  • Each ion will have its own enthalpy change of hydration, increment H subscript h y d end subscript to the power of theta, which will need to be taken into account during calculations

    • The total increment H subscript h y d end subscript to the power of theta is found by adding the  increment H subscript h y d end subscript to the power of theta values of both anions and cations together

Worked Example

Calculate the enthalpy of hydration of the chloride ion, given the following data:

increment H subscript l a t t end subscript to the power of theta [KCl] = -711 kJ mol-1

increment H subscript s o l end subscript to the power of theta [KCl] = +26 kJ mol-1

increment H subscript h y d end subscript to the power of theta[K+] = -322 kJ mol-1

Answer

Step 1: Draw the energy cycle and make ΔHhyd[Cl-] the subject of the formula:

Energy cycle explaining hydration, lattice, and solution enthalpy changes of KCl(s), showing direct and indirect pathways between gaseous and aqueous ions.

Step 2: Substitute the values to find increment H subscript h y d end subscript to the power of theta [Cl-]

increment H subscript h y d end subscript to the power of theta [Cl-]   = (-711) + (+26) - (-322) = -363 kJ mol-1

Alternative Diagram

  • You can also draw a Born-Haber cycle as an alternative approach to the same problem

Energy level diagram:

Chemical Energetics - Energy Level Diagram KCl (1), downloadable AS & A Level Chemistry revision notes
Chemical Energetics - Energy Level Diagram KCl (2), downloadable AS & A Level Chemistry revision notes

Worked Example

Construct an energy cycle to calculate the increment H subscript h y d end subscript to the power of theta of magnesium ions in magnesium chloride, given the following data:

increment H subscript l a t t end subscript to the power of theta [MgCl2] = -2592 kJ mol-1

increment H subscript s o l end subscript to the power of theta [MgCl2] = -55 kJ mol-1

increment H subscript h y d end subscript to the power of theta [Cl-] = -363 kJ mol-1

Answer

Step 1: Draw an energy cycle:

Worked Example - Energy Cycle MgCl2, downloadable AS & A Level Chemistry revision notes

Step 2: Substitute the values to find increment H subscript h y d end subscript to the power of theta [Mg2+]

increment H subscript h y d end subscript to the power of theta [Mg2+]  = (-2592) + (-55) - (2 x -363) = -1921 kJ mol-1

Alternative solution

  • Here is the same solution using a Born-Haber cycle

    Diagram of a Born-Haber cycle for MgCl2, showing both direct and indirect routes between gaseous ions and aqueous ions, with enthalpy changes labelled.

Examiner Tips and Tricks

It does not matter whether you use Hess cycles or Born–Haber style cycles to solve these problems, as long as the information is correctly labelled and the arrow directions match the definitions.

Exam questions in this topic often include diagrams with missing labels, which you must complete before calculating unknown values.

The key to success in energy cycle calculations is to stay calm and work step by step: label each enthalpy change carefully, show your working clearly, and use brackets to separate mathematical operations from the enthalpy changes.

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener