Integrating with Partial Fractions (Edexcel A Level Further Maths: Core Pure): Revision Note

Exam code: 9FM0

Paul

Written by: Paul

Reviewed by: Dan Finlay

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Integrating with partial fractions

What is meant by partial fractions with quadratic denominators?

  • For linear denominators the denominator of the original fraction can be factorised such that the denominator becomes a product of linear terms of the form (ax + b)

  • With squared linear denominators, the same applies, except that some (usually just one) of the factors on the denominator may be squared, i.e. (ax + b)2

  • In both the above cases it can be shown that the numerators of each of the partial fractions will be a constant (A, B, C, etc)

  • For this course, quadratic denominators refer to fractions that contain a quadratic factor (that cannot be factorised) on the denominator

    • the denominator of the quadratic partial fraction will be of the form (ax2 + bx + c); very often b = 0 leaving it as (ax2 + c)

    • the numerator of the quadratic partial fraction could be of linear form, (Ax + B)

How do I find partial fractions involving quadratic denominators?

  •  STEP 1          Factorise the denominator as far as possible (if not already done so)

    • Sometimes the numerator can be factorised too

  • STEP 2          Split the fraction into a sum with

    • the linear denominator having an (unknown) constant numerator

    • the quadratic denominator having an (unknown) linear numerator

  • STEP 3          Multiply through by the denominator to eliminate fractions

  • STEP 4          Substitute values into the identity and solve for the unknown constants

    • Use the root of the linear factor as a value of x to find one of the unknowns

    • Use any two values for x to form two equations to solve simultaneously

      • x = 0 is a good choice if this has not already been used with the linear factor

  • STEP 5          Write the original as partial fraction

How do I integrate the fraction with the quadratic denominator?

  •  The quadratic denominator will be of the form ax2+c

    • If it is not then you can get it to look like this by completing the square

  • Split into to fraction Ax+Bax2+c=Axax2+c+Bax2+c

  • Integrate Axax2+c using logarithms to get A2aln|ax2+c|

  • Integrate Bax2+c using the formula booklet or using a trigonometric or hyperbolic substitution

    • If a and have the same sign then use x=catan(u)

    • If a and have different signs then use x=catanh(u)

      • Or in this case you can factorise using surds and then use partial fractions

Worked Example

Find 8x29x(x3)(4x2+9)dx

5-2-3-edex-fm--alevel-we1-hypsub-soltn-a1
5-2-3-edex-fm--alevel-we1-hypsub-soltn-a2

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Paul

Author: Paul

Expertise: Maths Content Creator

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.